Programa de Python para imprimir una array dada en forma de espiral inversa

Python3

# Python3 Code to Print a given 
# matrix in reverse spiral form
 
# This is a modified code of
# https:#www.geeksforgeeks.org/print-a-given-matrix-in-spiral-form/
R, C = 3, 6
 
def ReversespiralPrint(m, n, a):
 
    # Large array to initialize it
    # with elements of matrix
    b = [0 for i in range(100)]
 
    #/* k - starting row index
    #l - starting column index*/
    i, k, l = 0, 0, 0
 
    # Counter for single dimension array
    # in which elements will be stored
    z = 0
 
    # Total elements in matrix
    size = m * n
 
    while (k < m and l < n):
         
        # Variable to store value of matrix.
        val = 0
 
        # Print the first row
        # from the remaining rows
        for i in range(l, n):
             
            # printf("%d ", a[k][i])
            val = a[k][i]
            b[z] = val
            z += 1
        k += 1
 
        # Print the last column
        # from the remaining columns
        for i in range(k, m):
 
            # printf("%d ", a[i][n-1])
            val = a[i][n - 1]
            b[z] = val
            z += 1
 
        n -= 1
 
        # Print the last row
        # from the remaining rows
        if (k < m):
            for i in range(n - 1, l - 1, -1):
                 
                # printf("%d ", a[m-1][i])
                val = a[m - 1][i]
                b[z] = val
                z += 1
 
        m -= 1
 
        # Print the first column
        # from the remaining columns
        if (l < n):
            for i in range(m - 1, k - 1, -1):
                 
                # printf("%d ", a[i][l])
                val = a[i][l]
                b[z] = val
                z += 1
            l += 1
 
    for i in range(size - 1, -1, -1):
        print(b[i], end = " ")
 
# Driver Code
a = [[1, 2, 3, 4, 5, 6],
     [7, 8, 9, 10, 11, 12],
     [13, 14, 15, 16, 17, 18]]
 
ReversespiralPrint(R, C, a)
 
# This code is contributed by mohit kumar