Dado un diccionario anidado, la tarea es convertir este diccionario en un diccionario aplanado donde la clave está separada por ‘_’ en caso de que se inicie la clave anidada.
A continuación se presentan algunos métodos para resolver la tarea anterior.
Método #1: Usar un enfoque ingenuo
Python3
# Python code to demonstrate
# conversion of nested dictionary
# into flattened dictionary
# code to convert ini_dict to flattened dictionary
# default separator '_'
def flatten_dict(dd, separator ='_', prefix =''):
return { prefix + separator + k if prefix else k : v
for kk, vv in dd.items()
for k, v in flatten_dict(vv, separator, kk).items()
} if isinstance(dd, dict) else { prefix : dd }
# initialising_dictionary
ini_dict = {'geeks': {'Geeks': {'for': 7}},
'for': {'geeks': {'Geeks': 3}},
'Geeks': {'for': {'for': 1, 'geeks': 4}}}
# printing initial dictionary
print ("initial_dictionary", str(ini_dict))
# printing final dictionary
print ("final_dictionary", str(flatten_dict(ini_dict)))
Salida:
initial_dictionary {‘geeks’: {‘Geeks’: {‘for’: 7}}, ‘Geeks’: {‘for’: {‘geeks’: 4, ‘for’: 1}}, ‘for’: {‘geeks’: {‘Geeks’: 3}}}
final_dictionary {‘Geeks_for_for’: 1, ‘geeks_Geeks_for’: 7, ‘for_geeks_Geeks’: 3, ‘Geeks_for_geeks’: 4}
initial_dictionary {‘geeks’: {‘Geeks’: {‘for’: 7}}, ‘Geeks’: {‘for’: {‘geeks’: 4, ‘for’: 1}}, ‘for’: {‘geeks’: {‘Geeks’: 3}}}
final_dictionary {‘Geeks_for_for’: 1, ‘geeks_Geeks_for’: 7, ‘for_geeks_Geeks’: 3, ‘Geeks_for_geeks’: 4}
Método #2: Usar mapeo mutuo
Python3
# Python code to demonstrate
# conversion of nested dictionary
# into flattened dictionary
from collections import MutableMapping
# code to convert ini_dict to flattened dictionary
# default separator '_'
def convert_flatten(d, parent_key ='', sep ='_'):
items = []
for k, v in d.items():
new_key = parent_key + sep + k if parent_key else k
if isinstance(v, MutableMapping):
items.extend(convert_flatten(v, new_key, sep = sep).items())
else:
items.append((new_key, v))
return dict(items)
# initialising_dictionary
ini_dict = {'geeks': {'Geeks': {'for': 7}},
'for': {'geeks': {'Geeks': 3}},
'Geeks': {'for': {'for': 1, 'geeks': 4}}}
# printing initial dictionary
print ("initial_dictionary", str(ini_dict))
# printing final dictionary
print ("final_dictionary", str(convert_flatten(ini_dict)))
Salida:
initial_dictionary {‘Geeks’: {‘for’: {‘for’: 1, ‘geeks’: 4}}, ‘for’: {‘geeks’: {‘Geeks’: 3}}, ‘geeks’: {‘Geeks’: {‘for’: 7}}}
final_dictionary {‘Geeks_for_geeks’: 4, ‘for_geeks_Geeks’: 3, ‘geeks_Geeks_for’: 7, ‘Geeks_for_for’: 1}
initial_dictionary {‘Geeks’: {‘for’: {‘for’: 1, ‘geeks’: 4}}, ‘for’: {‘geeks’: {‘Geeks’: 3}}, ‘geeks’: {‘Geeks’: {‘for’: 7}}}
final_dictionary {‘Geeks_for_geeks’: 4, ‘for_geeks_Geeks’: 3, ‘geeks_Geeks_for’: 7, ‘Geeks_for_for’: 1}
Método #3: Usar Generadores de Python
Python3
# Python code to demonstrate
# conversion of nested dictionary
# into flattened dictionary
my_map = {"a" : 1,
"b" : {
"c": 2,
"d": 3,
"e": {
"f":4,
6:"a",
5:{"g" : 6},
"l":[1,"two"]
}
}}
# Expected Output
# {'a': 1, 'b_c': 2, 'b_d': 3, 'b_e_f': 4, 'b_e_6': 'a', 'b_e_5_g': 6, 'b_e_l': [1, 'two']}
ini_dict = {'geeks': {'Geeks': {'for': 7}},
'for': {'geeks': {'Geeks': 3}},
'Geeks': {'for': {'for': 1, 'geeks': 4}}}
# Expected Output
# {‘Geeks_for_geeks’: 4, ‘for_geeks_Geeks’: 3, ‘Geeks_for_for’: 1, ‘geeks_Geeks_for’: 7}
def flatten_dict(pyobj, keystring=''):
if type(pyobj) == dict:
keystring = keystring + '_' if keystring else keystring
for k in pyobj:
yield from flatten_dict(pyobj[k], keystring + str(k))
else:
yield keystring, pyobj
print("Input : %s\nOutput : %s\n\n" %
(my_map, { k:v for k,v in flatten_dict(my_map) }))
print("Input : %s\nOutput : %s\n\n" %
(ini_dict, { k:v for k,v in flatten_dict(ini_dict) }))
Salida:
initial_dictionary {‘for’: {‘geeks’: {‘Geeks’: 3}}, ‘geeks’: {‘Geeks’: {‘for’: 7}}, ‘Geeks’: {‘for’: { ‘para’: 1, ‘geeks’: 4}}}
final_dictionary {‘Geeks_for_geeks’: 4, ‘for_geeks_Geeks’: 3, ‘Geeks_for_for’: 1, ‘geeks_Geeks_for’: 7}
initial_dictionary {‘for’: {‘geeks’: {‘Geeks’: 3}}, ‘geeks’: {‘Geeks’: {‘for’: 7}}, ‘Geeks’: {‘for’: { ‘para’: 1, ‘geeks’: 4}}}
final_dictionary {‘Geeks_for_geeks’: 4, ‘for_geeks_Geeks’: 3, ‘Geeks_for_for’: 1, ‘geeks_Geeks_for’: 7}
Publicación traducida automáticamente
Artículo escrito por garg_ak0109 y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA