Dada una array mat[][] que tiene n filas y m columnas. Necesitamos encontrar elementos únicos en la array, es decir, aquellos elementos que no se repiten en la array o aquellos elementos cuya frecuencia es 1.
Ejemplos:
Input : 20 15 30 2 2 3 5 30 6 7 6 8 Output : 3 20 5 7 8 15 Input : 1 2 3 5 6 2 1 3 5 6 2 2 Output : No unique element in the matrix
Siga estos pasos para encontrar un elemento único:
1. Cree una tabla hash o diccionario vacío.
2. Recorra todos los elementos de la array
3. Si el elemento está presente en el diccionario, incremente su cuenta
4. De lo contrario, inserte el elemento con valor = 1.
C++
// C++ program to find unique // element in matrix #include<bits/stdc++.h> using namespace std; #define R 4 #define C 4 // function that calculate unique element int unique(int mat[R][C], int n, int m) { int maximum = 0, flag = 0; for(int i = 0; i < n; i++) for(int j = 0; j < m; j++) // Find maximum element in // a matrix if(maximum < mat[i][j]) maximum = mat[i][j]; // Take 1-D array of (maximum + 1) // size int b[maximum + 1] = {0}; for(int i = 0 ; i < n; i++) for(int j = 0; j < m; j++) b[mat[i][j]]++; //print unique element for(int i = 1; i <= maximum; i++) if(b[i] == 1) cout << i << " "; flag = 1; if(!flag){ cout << "No unique element in the matrix"; } } // Driver program int main() { int mat[R][C] = {{ 1, 2, 3, 20}, {5, 6, 20, 25}, {1, 3, 5, 6}, {6, 7, 8, 15}}; // function that calculate unique element unique(mat, R, C); return 0; } // This code is contributed by Naman_Garg.
Java
// Java program to find unique // element in matrix class GFG { static int R = 4, C = 4; // function that calculate // unique element static void unique(int mat[][], int n, int m) { int maximum = 0, flag = 0; for(int i = 0; i < n; i++) for(int j = 0; j < m; j++) // Find maximum element // in a matrix if(maximum < mat[i][j]) maximum = mat[i][j]; // Take 1-D array of // (maximum + 1) size int b[] = new int [maximum + 1]; for(int i = 0 ; i < n; i++) for(int j = 0; j < m; j++) b[mat[i][j]]++; //print unique element for(int i = 1; i <= maximum; i++) if(b[i] == 1) System.out.print(i + " "); flag = 1; if(flag == 0) { System.out.println("No unique element " + "in the matrix"); } } // Driver Code public static void main(String args[]) { int mat[][] = {{1, 2, 3, 20}, {5, 6, 20, 25}, {1, 3, 5, 6}, {6, 7, 8, 15}}; // function that calculate // unique element unique(mat, R, C); } } // This code is contributed // by Arnab Kundu
Python3
# Python 3 program to find unique # element in matrix def unique(mat, n, m): maximum = 0; flag = 0 for i in range(0, n): for j in range(0, m): # Find maximum element in # a matrix if(maximum < mat[i][j]): maximum = mat[i][j]; uniqueElementDict = [0] * (maximum + 1) # loops to traverse through the matrix for i in range(0, n): for j in range(0, m): uniqueElementDict[mat[i][j]] += 1 # Print all those keys whose count is 1 for key in range(maximum + 1): if uniqueElementDict[key] == 1: print (key, end = " ") flag = 1 if(flag == 0): print("No unique element in the matrix") # Driver Code mat = [[1, 2, 3, 20], [5, 6, 20, 25], [1, 3, 5, 6], [6, 7, 8, 15]] n = 4 m = 4 unique(mat, n, m)
C#
// C# program to find unique // element in matrix using System; class GFG { static int R = 4, C = 4; // function that calculate // unique element static void unique(int [,]mat, int n, int m) { int maximum = 0, flag = 0; for(int i = 0; i < n; i++) for(int j = 0; j < m; j++) // Find maximum element // in a matrix if(maximum < mat[i, j]) maximum = mat[i, j]; // Take 1-D array of // (maximum + 1) size int []b = new int [maximum + 1]; for(int i = 0 ; i < n; i++) for(int j = 0; j < m; j++) b[mat[i, j]]++; // print unique element for(int i = 1; i <= maximum; i++) if(b[i] == 1) Console.Write(i + " "); flag = 1; if(flag == 0) { Console.WriteLine("No unique element " + "in the matrix"); } } // Driver Code public static void Main() { int [,]mat = {{1, 2, 3, 20}, {5, 6, 20, 25}, {1, 3, 5, 6}, {6, 7, 8, 15}}; // function that calculate // unique element unique(mat, R, C); } } // This code is contributed // by Subhadeep
PHP
<?php // PHP program to find unique // element in matrix $R = 4; $C = 4; // function that calculate unique element function unique($mat, $n, $m) { $maximum = 0; $flag = 0; for($i = 0; $i < $n; $i++) for($j = 0; $j < $m; $j++) // Find maximum element in // a matrix if($maximum < $mat[$i][$j]) $maximum = $mat[$i][$j]; // Take 1-D array of (maximum + 1) // size $b = array(); for($j = 0; $j < $maximum + 1; $j++) $b[$j] = 0; for($i = 0 ; $i < $n; $i++) for($j = 0; $j < $m; $j++) $b[$mat[$i][$j]]++; // print unique element for($i = 1; $i <= $maximum; $i++) if($b[$i] == 1) echo "$i "; $flag = 1; if(!$flag) { echo "No unique element in the matrix"; } } // Driver Code $mat = array(array(1, 2, 3, 20), array(5, 6, 20, 25), array(1, 3, 5, 6), array(6, 7, 8, 15)); // function that calculate unique element unique($mat, $R, $C); // This code is contributed by iAyushRaj ?>
Javascript
<script> // Javascript program to find unique // element in matrix var R = 4, C = 4; // Function that calculate // unique element function unique(mat, n, m) { var maximum = 0, flag = 0; for(var i = 0; i < n; i++) for(var j = 0; j < m; j++) // Find maximum element // in a matrix if (maximum < mat[i][j]) maximum = mat[i][j]; // Take 1-D array of // (maximum + 1) size var b = Array(maximum+1).fill(0); for(var i = 0 ; i < n; i++) for(var j = 0; j < m; j++) b[mat[i][j]]++; // Print unique element for(var i = 1; i <= maximum; i++) if (b[i] == 1) document.write(i + " "); flag = 1; if (flag == 0) { document.write("No unique element " + "in the matrix<br>"); } } // Driver Code var mat = [ [ 1, 2, 3, 20 ], [ 5, 6, 20, 25 ], [ 1, 3, 5, 6 ], [ 6, 7, 8, 15 ] ]; // Function that calculate // unique element unique(mat, R, C); // This code is contributed by rrrtnx </script>
2 7 8 15 25
Análisis de Complejidad:
Complejidad de tiempo: O(m*n) donde m es el número de filas & n es el número de columnas.
Espacio Auxiliar: O(max(array)).
Publicación traducida automáticamente
Artículo escrito por shivani.mittal y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA