Dada una lista de tuplas, la tarea es eliminar todas aquellas tuplas que no contienen ningún valor de carácter.
Ejemplo:
Input: [(', ', 12), ('...', 55),
('-Geek', 115), ('Geeksfor', 115),]
Output: [('-Geek', 115), ('Geeksfor', 115)]
Método #1: Usar la comprensión de listas
# Python code to remove all those
# elements from list of tuple
# which does not contains any alphabet.
# List initialization
List = [(', ', 12), ('Paras', 5),
('jain.', 11), ('...', 55),
('-Geek', 115), ('Geeksfor', 115),
(':', 63), ('Data', 3), ('-', 15),
('Structure', 32), ('Algo', 80),]
# Using list comprehension
out = [(a, b) for a, b in List
if any(c.isalpha() for c in a)]
# Printing output
print(out)
Producción:
[(‘Paras’, 5), (‘jain.’, 11), (‘-Geek’, 115), (‘Geeksfor’, 115), (‘Data’, 3), (‘Structure’, 32) , (‘Algo’, 80)]
Método #2: Usando Regex
# Python code to remove all those
# elements from list of tuple
# which does not contains any alphabet.
# List initialization
List = [(', ', 12), ('Paras', 5),
('jain.', 11), ('...', 55),
('-Geek', 115), ('Geeksfor', 115),
(':', 63), ('Data', 3), ('-', 15),
('Structure', 32), ('Algo', 80),]
# Importing
import re
# Using regex
out = [t for t in List if re.search(r'\w', t[0])]
# Printing output
print(out)
Producción:
[(‘Paras’, 5), (‘jain.’, 11), (‘-Geek’, 115), (‘Geeksfor’, 115), (‘Data’, 3), (‘Structure’, 32) , (‘Algo’, 80)]
Método 3: uso de filtro y lambda
# Python code to remove all those
# elements from list of tuple
# which does not contains any alphabet.
# List initialization
List = [(', ', 12), ('Paras', 5),
('jain.', 11), ('...', 55),
('-Geek', 115), ('Geeksfor', 115),
(':', 63), ('Data', 3), ('-', 15),
('Structure', 32), ('Algo', 80),]
# Using filter
out = filter(lambda x:any(c.isalpha()
for c in x[0]), List)
# Converting in list
out = list(out)
# Printing output
print(out)
Producción:
[(‘Paras’, 5), (‘jain.’, 11), (‘-Geek’, 115), (‘Geeksfor’, 115), (‘Data’, 3), (‘Structure’, 32) , (‘Algo’, 80)]
Publicación traducida automáticamente
Artículo escrito por everythingispossible y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA