Dada una serie de strings, imprímalas en orden alfabético (diccionario). Si hay duplicados en la array de entrada, debemos imprimirlos solo una vez.
Ejemplos:
Input : "abc", "xy", "bcd" Output : abc bcd xy Input : "geeks", "for", "geeks", "a", "portal", "to", "learn", "can", "be", "computer", "science", "zoom", "yup", "fire", "in", "data" Output : a be can computer data fire for geeks in learn portal science to yup zoom
Trie es una estructura de datos eficiente utilizada para almacenar datos como strings. Para imprimir la string en orden alfabético, primero debemos insertarla en el trie y luego realizar un recorrido de preorden para imprimir en orden alfabético.
Implementación:
CPP
// C++ program to sort an array of strings // using Trie #include <bits/stdc++.h> using namespace std; const int MAX_CHAR = 26; struct Trie { // index is set when node is a leaf // node, otherwise -1; int index; Trie* child[MAX_CHAR]; /*to make new trie*/ Trie() { for (int i = 0; i < MAX_CHAR; i++) child[i] = NULL; index = -1; } }; /* function to insert in trie */ void insert(Trie* root, string str, int index) { Trie* node = root; for (int i = 0; i < str.size(); i++) { /* taking ascii value to find index of child node */ char ind = str[i] - 'a'; /* making new path if not already */ if (!node->child[ind]) node->child[ind] = new Trie(); // go to next node node = node->child[ind]; } // Mark leaf (end of word) and store // index of word in arr[] node->index = index; } /* function for preorder traversal */ bool preorder(Trie* node, string arr[]) { if (node == NULL) return false; for (int i = 0; i < MAX_CHAR; i++) { if (node->child[i] != NULL) { /* if leaf node then print key*/ if (node->child[i]->index != -1) cout << arr[node->child[i]->index] << endl; preorder(node->child[i], arr); } } } void printSorted(string arr[], int n) { Trie* root = new Trie(); // insert all keys of dictionary into trie for (int i = 0; i < n; i++) insert(root, arr[i], i); // print keys in lexicographic order preorder(root, arr); } // Driver code int main() { string arr[] = { "abc", "xy", "bcd" }; int n = sizeof(arr) / sizeof(arr[0]); printSorted(arr, n); return 0; }
Java
// Java program to sort an array of strings using Trie // Author : Rohit Jain // GFG user_id : @rj03012002 import java.util.*; class GFG { // Alphabet size static final int MAX_CHAR = 26; // trie node static class Trie { // index is set when node is a leaf // node, otherwise -1; int index; Trie child[] = new Trie[MAX_CHAR]; /*to make new trie*/ Trie() { for (int i = 0; i < MAX_CHAR; i++) child[i] = null; index = -1; } } /* function to insert in trie */ static void insert(Trie root, String str, int index) { Trie node = root; for (int i = 0; i < str.length(); i++) { /* taking ascii value to find index of child node */ int ind = str.charAt(i) - 'a'; /* making new path if not already */ if (node.child[ind] == null) node.child[ind] = new Trie(); // go to next node node = node.child[ind]; } // Mark leaf (end of word) and store // index of word in arr[] node.index = index; } /* function for preorder traversal */ static boolean preorder(Trie node, String arr[]) { if (node == null) { return false; } for (int i = 0; i < MAX_CHAR; i++) { if (node.child[i] != null) { /* if leaf node then print key*/ if (node.child[i].index != -1) { System.out.print( arr[node.child[i].index] + " "); } preorder(node.child[i], arr); } } return false; } static void printSorted(String arr[], int n) { Trie root = new Trie(); // insert all keys of dictionary into trie for (int i = 0; i < n; ++i) { insert(root, arr[i], i); } // print keys in lexicographic order preorder(root, arr); } public static void main(String[] args) { String arr[] = { "abc", "xy", "bcd" }; int n = arr.length; printSorted(arr, n); } }
Python3
# Python3 program to sort an array of strings # using Trie MAX_CHAR = 26 class Trie: # index is set when node is a leaf # node, otherwise -1; # to make new trie def __init__(self): self.child = [None for i in range(MAX_CHAR)] self.index = -1 # def to insert in trie def insert(root,str,index): node = root for i in range(len(str)): # taking ascii value to find index of # child node ind = ord(str[i]) - ord('a') # making new path if not already if (node.child[ind] == None): node.child[ind] = Trie() # go to next node node = node.child[ind] # Mark leaf (end of word) and store # index of word in arr[] node.index = index # function for preorder traversal def preorder(node, arr): if (node == None): return False for i in range(MAX_CHAR): if (node.child[i] != None): # if leaf node then print key if (node.child[i].index != -1): print(arr[node.child[i].index]) preorder(node.child[i], arr) def printSorted(arr,n): root = Trie() # insert all keys of dictionary into trie for i in range(n): insert(root, arr[i], i) # print keys in lexicographic order preorder(root, arr) # Driver code arr = [ "abc", "xy", "bcd" ] n = len(arr) printSorted(arr, n) # This code is contributed by shinjanpatra
Javascript
<script> // JavaScript program to sort an array of strings // using Trie const MAX_CHAR = 26; class Trie { // index is set when node is a leaf // node, otherwise -1; /*to make new trie*/ constructor() { this.child = new Array(MAX_CHAR).fill(null); this.index = -1; } } /* function to insert in trie */ function insert(root,str,index) { let node = root; for (let i = 0; i < str.length; i++) { /* taking ascii value to find index of child node */ let ind = str.charCodeAt(i) - 'a'.charCodeAt(0); /* making new path if not already */ if (node.child[ind] == null) node.child[ind] = new Trie(); // go to next node node = node.child[ind]; } // Mark leaf (end of word) and store // index of word in arr[] node.index = index; } /* function for preorder traversal */ function preorder(node, arr) { if (node == null) return false; for (let i = 0; i < MAX_CHAR; i++) { if (node.child[i] != null) { /* if leaf node then print key*/ if (node.child[i].index != -1) document.write(arr[node.child[i].index],"</br>"); preorder(node.child[i], arr); } } } function printSorted(arr,n) { let root = new Trie(); // insert all keys of dictionary into trie for (let i = 0; i < n; i++) insert(root, arr[i], i); // print keys in lexicographic order preorder(root, arr); } // Driver code let arr = [ "abc", "xy", "bcd" ]; let n = arr.length; printSorted(arr, n); // This code is contributed by shinjanpatra </script>
abc bcd xy
Complejidad temporal: O(n)
Espacio auxiliar: O(n)
Este artículo es una contribución de Pranav . Si te gusta GeeksforGeeks y te gustaría contribuir, también puedes escribir un artículo usando write.geeksforgeeks.org o enviar tu artículo por correo a review-team@geeksforgeeks.org. Vea su artículo que aparece en la página principal de GeeksforGeeks y ayude a otros Geeks.
Publicación traducida automáticamente
Artículo escrito por GeeksforGeeks-1 y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA