Detectar bucle en una lista enlazada – Part 1

Dada una lista enlazada, compruebe si la lista enlazada tiene un bucle o no. El siguiente diagrama muestra una lista enlazada con un bucle. 

C++

// C++ program to detect loop in a linked list
#include <bits/stdc++.h>
using namespace std;
 
/* Link list node */
struct Node {
    int data;
    struct Node* next;
};
 
void push(struct Node** head_ref, int new_data)
{
    /* allocate node */
    struct Node* new_node = new Node;
 
    /* put in the data  */
    new_node->data = new_data;
 
    /* link the old list off the new node */
    new_node->next = (*head_ref);
 
    /* move the head to point to the new node */
    (*head_ref) = new_node;
}
 
// Returns true if there is a loop in linked list
// else returns false.
bool detectLoop(struct Node* h)
{
    unordered_set<Node*> s;
    while (h != NULL) {
        // If this node is already present
        // in hashmap it means there is a cycle
        // (Because you will be encountering the
        // node for the second time).
        if (s.find(h) != s.end())
            return true;
 
        // If we are seeing the node for
        // the first time, insert it in hash
        s.insert(h);
 
        h = h->next;
    }
 
    return false;
}
 
/* Driver program to test above function*/
int main()
{
    /* Start with the empty list */
    struct Node* head = NULL;
 
    push(&head, 20);
    push(&head, 4);
    push(&head, 15);
    push(&head, 10);
 
    /* Create a loop for testing */
    head->next->next->next->next = head;
 
    if (detectLoop(head))
        cout << "Loop found";
    else
        cout << "No Loop";
 
    return 0;
}
// This code is contributed by Geetanjali

Java

// Java program to detect loop in a linked list
import java.util.*;
 
public class LinkedList {
 
    static Node head; // head of list
 
    /* Linked list Node*/
    static class Node {
        int data;
        Node next;
        Node(int d)
        {
            data = d;
            next = null;
        }
    }
 
    /* Inserts a new Node at front of the list. */
    static public void push(int new_data)
    {
        /* 1 & 2: Allocate the Node &
                  Put in the data*/
        Node new_node = new Node(new_data);
 
        /* 3. Make next of new Node as head */
        new_node.next = head;
 
        /* 4. Move the head to point to new Node */
        head = new_node;
    }
 
    // Returns true if there is a loop in linked
    // list else returns false.
    static boolean detectLoop(Node h)
    {
        HashSet<Node> s = new HashSet<Node>();
        while (h != null) {
            // If we have already has this node
            // in hashmap it means their is a cycle
            // (Because you we encountering the
            // node second time).
            if (s.contains(h))
                return true;
 
            // If we are seeing the node for
            // the first time, insert it in hash
            s.add(h);
 
            h = h.next;
        }
 
        return false;
    }
 
    /* Driver program to test above function */
    public static void main(String[] args)
    {
        LinkedList llist = new LinkedList();
 
        llist.push(20);
        llist.push(4);
        llist.push(15);
        llist.push(10);
 
        /*Create loop for testing */
        llist.head.next.next.next.next = llist.head;
 
        if (detectLoop(head))
            System.out.println("Loop found");
        else
            System.out.println("No Loop");
    }
}
 
// This code is contributed by Arnav Kr. Mandal.

Python3

# Python3 program to detect loop
# in the linked list
 
# Node class
 
 
class Node:
 
    # Constructor to initialize
    # the node object
    def __init__(self, data):
        self.data = data
        self.next = None
 
 
class LinkedList:
 
    # Function to initialize head
    def __init__(self):
        self.head = None
 
    # Function to insert a new
    # node at the beginning
    def push(self, new_data):
        new_node = Node(new_data)
        new_node.next = self.head
        self.head = new_node
 
    # Utility function to print it
    # the linked LinkedList
    def printList(self):
        temp = self.head
        while(temp):
            print(temp.data, end=" ")
            temp = temp.next
 
    def detectLoop(self):
        s = set()
        temp = self.head
        while (temp):
 
            # If we have already has
            # this node in hashmap it
            # means their is a cycle
            # (Because you we encountering
            # the node second time).
            if (temp in s):
                return True
 
            # If we are seeing the node for
            # the first time, insert it in hash
            s.add(temp)
 
            temp = temp.next
 
        return False
 
 
# Driver program for testing
llist = LinkedList()
llist.push(20)
llist.push(4)
llist.push(15)
llist.push(10)
 
# Create a loop for testing
llist.head.next.next.next.next = llist.head
 
if(llist.detectLoop()):
    print("Loop found")
else:
    print("No Loop ")
 
# This code is contributed by Gitanjali.

C#

// C# program to detect loop in a linked list
using System;
using System.Collections.Generic;
 
class LinkedList {
 
    // head of list
    public Node head;
 
    /* Linked list Node*/
    public class Node {
        public int data;
        public Node next;
        public Node(int d)
        {
            data = d;
            next = null;
        }
    }
 
    /* Inserts a new Node at front of the list. */
    public void push(int new_data)
    {
        /* 1 & 2: Allocate the Node &
                Put in the data*/
        Node new_node = new Node(new_data);
 
        /* 3. Make next of new Node as head */
        new_node.next = head;
 
        /* 4. Move the head to point to new Node */
        head = new_node;
    }
 
    // Returns true if there is a loop in linked
    // list else returns false.
    public static bool detectLoop(Node h)
    {
        HashSet<Node> s = new HashSet<Node>();
        while (h != null) {
            // If we have already has this node
            // in hashmap it means their is a cycle
            // (Because you we encountering the
            // node second time).
            if (s.Contains(h))
                return true;
 
            // If we are seeing the node for
            // the first time, insert it in hash
            s.Add(h);
 
            h = h.next;
        }
 
        return false;
    }
 
    /* Driver code*/
    public static void Main(String[] args)
    {
        LinkedList llist = new LinkedList();
 
        llist.push(20);
        llist.push(4);
        llist.push(15);
        llist.push(10);
 
        /*Create loop for testing */
        llist.head.next.next.next.next = llist.head;
 
        if (detectLoop(llist.head))
            Console.WriteLine("Loop found");
        else
            Console.WriteLine("No Loop");
    }
}
 
// This code has been contributed by 29AjayKumar

Javascript

<script>
 
// JavaScript program to detect loop in a linked list
    var head; // head of list
 
    /* Linked list Node */
    class Node {
        constructor(val) {
            this.data = val;
            this.next = null;
        }
    }
    /* Inserts a new Node at front of the list. */
      function push(new_data) {
        /*
         * 1 & 2: Allocate the Node & Put in the data
         */
var new_node = new Node(new_data);
 
        /* 3. Make next of new Node as head */
        new_node.next = head;
 
        /* 4. Move the head to point to new Node */
        head = new_node;
    }
 
    // Returns true if there is a loop in linked
    // list else returns false.
    function detectLoop(h) {
        var s = new Set();
        while (h != null) {
            // If we have already has this node
            // in hashmap it means their is a cycle
            // (Because you we encountering the
            // node second time).
            if (s.has(h))
                return true;
 
            // If we are seeing the node for
            // the first time, insert it in hash
            s.add(h);
 
            h = h.next;
        }
 
        return false;
    }
 
    /* Driver program to test above function */
     
 
        push(20);
        push(4);
        push(15);
        push(10);
 
        /* Create loop for testing */
        head.next.next.next.next = head;
 
        if (detectLoop(head))
            document.write("Loop found");
        else
            document.write("No Loop");
 
// This code is contributed by todaysgaurav
 
</script>

C++

// C++ program to detect loop in a linked list
#include <bits/stdc++.h>
using namespace std;
 
/* Link list node */
struct Node {
    int data;
    struct Node* next;
    int flag;
};
 
void push(struct Node** head_ref, int new_data)
{
    /* allocate node */
    struct Node* new_node = new Node;
 
    /* put in the data */
    new_node->data = new_data;
 
    new_node->flag = 0;
 
    /* link the old list off the new node */
    new_node->next = (*head_ref);
 
    /* move the head to point to the new node */
    (*head_ref) = new_node;
}
 
// Returns true if there is a loop in linked list
// else returns false.
bool detectLoop(struct Node* h)
{
    while (h != NULL) {
        // If this node is already traverse
        // it means there is a cycle
        // (Because you we encountering the
        // node for the second time).
        if (h->flag == 1)
            return true;
 
        // If we are seeing the node for
        // the first time, mark its flag as 1
        h->flag = 1;
 
        h = h->next;
    }
 
    return false;
}
 
/* Driver program to test above function*/
int main()
{
    /* Start with the empty list */
    struct Node* head = NULL;
 
    push(&head, 20);
    push(&head, 4);
    push(&head, 15);
    push(&head, 10);
 
    /* Create a loop for testing */
    head->next->next->next->next = head;
 
    if (detectLoop(head))
        cout << "Loop found";
    else
        cout << "No Loop";
 
    return 0;
}
// This code is contributed by Geetanjali

C

// C program to detect loop in a linked list
#include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
 
/* Link list node */
typedef struct Node {
    int data;
    struct Node* next;
    int flag;
} Node;
 
void push(struct Node** head_ref, int new_data)
{
    /* allocate node */
    struct Node* new_node = (Node*)malloc(sizeof(Node));
 
    /* put in the data */
    new_node->data = new_data;
 
    new_node->flag = 0;
 
    /* link the old list off the new node */
    new_node->next = (*head_ref);
 
    /* move the head to point to the new node */
    (*head_ref) = new_node;
}
 
// Returns true if there is a loop in linked list
// else returns false.
bool detectLoop(struct Node* h)
{
    while (h != NULL) {
        // If this node is already traverse
        // it means there is a cycle
        // (Because you we encountering the
        // node for the second time).
        if (h->flag == 1)
            return true;
 
        // If we are seeing the node for
        // the first time, mark its flag as 1
        h->flag = 1;
 
        h = h->next;
    }
 
    return false;
}
 
/* Driver program to test above function*/
int main()
{
    /* Start with the empty list */
    struct Node* head = NULL;
 
    push(&head, 20);
    push(&head, 4);
    push(&head, 15);
    push(&head, 10);
 
    /* Create a loop for testing */
    head->next->next->next->next = head;
 
    if (detectLoop(head))
        printf("Loop found");
    else
        printf("No Loop");
 
    return 0;
}
 
// This code is contributed by Aditya Kumar (adityakumar129)

Java

// Java program to detect loop in a linked list
import java.util.*;
 
class GFG{
 
// Link list node
static class Node
{
    int data;
    Node next;
    int flag;
};
 
static Node push(Node head_ref, int new_data)
{
     
    // Allocate node
    Node new_node = new Node();
 
    // Put in the data
    new_node.data = new_data;
 
    new_node.flag = 0;
 
    // Link the old list off the new node
    new_node.next = head_ref;
 
    // Move the head to point to the new node
    head_ref = new_node;
    return head_ref;
}
 
// Returns true if there is a loop in linked
// list else returns false.
static boolean detectLoop(Node h)
{
    while (h != null)
    {
         
        // If this node is already traverse
        // it means there is a cycle
        // (Because you we encountering the
        // node for the second time).
        if (h.flag == 1)
            return true;
 
        // If we are seeing the node for
        // the first time, mark its flag as 1
        h.flag = 1;
 
        h = h.next;
    }
    return false;
}
 
// Driver code
public static void main(String[] args)
{
     
    // Start with the empty list
    Node head = null;
 
    head = push(head, 20);
    head = push(head, 4);
    head = push(head, 15);
    head = push(head, 10);
 
    // Create a loop for testing
    head.next.next.next.next = head;
 
    if (detectLoop(head))
        System.out.print("Loop found");
    else
        System.out.print("No Loop");
}
}
 
// This code is contributed by Rajput-Ji

Python3

# Python3 program to detect loop in a linked list
  
''' Link list node '''
class Node:
     
    def __init__(self):
        self.data = 0
        self.next = None
        self.flag = 0
     
def push(head_ref, new_data):
 
    ''' allocate node '''
    new_node = Node();
  
    ''' put in the data '''
    new_node.data = new_data;
  
    new_node.flag = 0;
  
    ''' link the old list off the new node '''
    new_node.next = (head_ref);
  
    ''' move the head to point to the new node '''
    (head_ref) = new_node;   
    return head_ref
 
# Returns true if there is a loop in linked list
# else returns false.
def detectLoop(h):
 
    while (h != None):
        # If this node is already traverse
        # it means there is a cycle
        # (Because you we encountering the
        # node for the second time).
        if (h.flag == 1):
            return True;
  
        # If we are seeing the node for
        # the first time, mark its flag as 1
        h.flag = 1;
        h = h.next;  
    return False;
 
''' Driver program to test above function'''
if __name__=='__main__':
     
    ''' Start with the empty list '''
    head = None;
  
    head = push(head, 20);
    head = push(head, 4);
    head = push(head, 15);
    head = push(  head, 10)
  
    ''' Create a loop for testing '''
    head.next.next.next.next = head;
  
    if (detectLoop(head)):
        print("Loop found")
    else:
        print("No Loop")
 
# This code is contributed by rutvik_56

C#

// C# program to detect loop in a linked list
using System;
 
class GFG{
 
// Link list node
class Node
{
    public int data;
    public Node next;
    public int flag;
};
 
static Node push(Node head_ref, int new_data)
{
     
    // Allocate node
    Node new_node = new Node();
 
    // Put in the data
    new_node.data = new_data;
 
    new_node.flag = 0;
 
    // Link the old list off the new node
    new_node.next = head_ref;
 
    // Move the head to point to the new node
    head_ref = new_node;
    return head_ref;
}
 
// Returns true if there is a loop in linked
// list else returns false.
static bool detectLoop(Node h)
{
    while (h != null)
    {
         
        // If this node is already traverse
        // it means there is a cycle
        // (Because you we encountering the
        // node for the second time).
        if (h.flag == 1)
            return true;
 
        // If we are seeing the node for
        // the first time, mark its flag as 1
        h.flag = 1;
 
        h = h.next;
    }
    return false;
}
 
// Driver code
public static void Main(string[] args)
{
     
    // Start with the empty list
    Node head = null;
 
    head = push(head, 20);
    head = push(head, 4);
    head = push(head, 15);
    head = push(head, 10);
 
    // Create a loop for testing
    head.next.next.next.next = head;
 
    if (detectLoop(head))
        Console.Write("Loop found");
    else
        Console.Write("No Loop");
}
}
 
// This code is contributed by pratham76

Javascript

<script>
 
// JavaScript program to detect loop in a linked list
 
// Link list node
class Node
{
    constructor()
    {
        let data;
        let next;
        let flag;
    }
}
 
function push( head_ref, new_data)
{
    // Allocate node
    let new_node = new Node();
  
    // Put in the data
    new_node.data = new_data;
  
    new_node.flag = 0;
  
    // Link the old list off the new node
    new_node.next = head_ref;
  
    // Move the head to point to the new node
    head_ref = new_node;
    return head_ref;
}
 
// Returns true if there is a loop in linked
// list else returns false.   
function detectLoop(h)
{
    while (h != null)
    {
          
        // If this node is already traverse
        // it means there is a cycle
        // (Because you we encountering the
        // node for the second time).
        if (h.flag == 1)
            return true;
  
        // If we are seeing the node for
        // the first time, mark its flag as 1
        h.flag = 1;
  
        h = h.next;
    }
    return false;
}
 
// Driver code
 
// Start with the empty list
    let head = null;
  
    head = push(head, 20);
    head = push(head, 4);
    head = push(head, 15);
    head = push(head, 10);
  
    // Create a loop for testing
    head.next.next.next.next = head;
  
    if (detectLoop(head))
        document.write("Loop found");
    else
        document.write("No Loop");
 
 
 
// This code is contributed by rag2127
 
</script>

C++

// C++ program to detect loop in a linked list
#include <bits/stdc++.h>
using namespace std;
 
/* Link list node */
class Node {
public:
    int data;
    Node* next;
};
 
void push(Node** head_ref, int new_data)
{
    /* allocate node */
    Node* new_node = new Node();
 
    /* put in the data */
    new_node->data = new_data;
 
    /* link the old list off the new node */
    new_node->next = (*head_ref);
 
    /* move the head to point to the new node */
    (*head_ref) = new_node;
}
 
int detectLoop(Node* list)
{
    Node *slow_p = list, *fast_p = list;
 
    while (slow_p && fast_p && fast_p->next) {
        slow_p = slow_p->next;
        fast_p = fast_p->next->next;
        if (slow_p == fast_p) {
            return 1;
        }
    }
    return 0;
}
 
/* Driver code*/
int main()
{
    /* Start with the empty list */
    Node* head = NULL;
 
    push(&head, 20);
    push(&head, 4);
    push(&head, 15);
    push(&head, 10);
 
    /* Create a loop for testing */
    head->next->next->next->next = head;
    if (detectLoop(head))
        cout << "Loop found";
    else
        cout << "No Loop";
    return 0;
}
 
// This is code is contributed by rathbhupendra

C

// C program to detect loop in a linked list
#include <stdio.h>
#include <stdlib.h>
 
/* Link list node */
struct Node {
    int data;
    struct Node* next;
};
 
void push(struct Node** head_ref, int new_data)
{
    /* allocate node */
    struct Node* new_node
        = (struct Node*)malloc(sizeof(struct Node));
 
    /* put in the data  */
    new_node->data = new_data;
 
    /* link the old list off the new node */
    new_node->next = (*head_ref);
 
    /* move the head to point to the new node */
    (*head_ref) = new_node;
}
 
int detectLoop(struct Node* list)
{
    struct Node *slow_p = list, *fast_p = list;
 
    while (slow_p && fast_p && fast_p->next) {
        slow_p = slow_p->next;
        fast_p = fast_p->next->next;
        if (slow_p == fast_p) {
            return 1;
        }
    }
    return 0;
}
 
/* Driver program to test above function*/
int main()
{
    /* Start with the empty list */
    struct Node* head = NULL;
 
    push(&head, 20);
    push(&head, 4);
    push(&head, 15);
    push(&head, 10);
 
    /* Create a loop for testing */
    head->next->next->next->next = head;
 
    if (detectLoop(head))
        printf("Loop found");
    else
        printf("No Loop");
    return 0;
}

Java

// Java program to detect loop in a linked list
class LinkedList {
    Node head; // head of list
 
    /* Linked list Node*/
    class Node {
        int data;
        Node next;
        Node(int d)
        {
            data = d;
            next = null;
        }
    }
 
    /* Inserts a new Node at front of the list. */
    public void push(int new_data)
    {
        /* 1 & 2: Allocate the Node &
                Put in the data*/
        Node new_node = new Node(new_data);
 
        /* 3. Make next of new Node as head */
        new_node.next = head;
 
        /* 4. Move the head to point to new Node */
        head = new_node;
    }
 
    void detectLoop()
    {
        Node slow_p = head, fast_p = head;
        int flag = 0;
        while (slow_p != null && fast_p != null
               && fast_p.next != null) {
            slow_p = slow_p.next;
            fast_p = fast_p.next.next;
            if (slow_p == fast_p) {
                flag = 1;
                break;
            }
        }
        if (flag == 1)
            System.out.println("Loop found");
        else
            System.out.println("Loop not found");
    }
 
    /* Driver program to test above functions */
    public static void main(String args[])
    {
        LinkedList llist = new LinkedList();
 
        llist.push(20);
        llist.push(4);
        llist.push(15);
        llist.push(10);
 
        /*Create loop for testing */
        llist.head.next.next.next.next = llist.head;
 
        llist.detectLoop();
    }
}
/* This code is contributed by Rajat Mishra. */

Python

# Python program to detect loop in the linked list
 
# Node class
 
 
class Node:
 
    # Constructor to initialize the node object
    def __init__(self, data):
        self.data = data
        self.next = None
 
 
class LinkedList:
 
    # Function to initialize head
    def __init__(self):
        self.head = None
 
    # Function to insert a new node at the beginning
    def push(self, new_data):
        new_node = Node(new_data)
        new_node.next = self.head
        self.head = new_node
 
    # Utility function to print it the linked LinkedList
    def printList(self):
        temp = self.head
        while(temp):
            print temp.data,
            temp = temp.next
 
    def detectLoop(self):
        slow_p = self.head
        fast_p = self.head
        while(slow_p and fast_p and fast_p.next):
            slow_p = slow_p.next
            fast_p = fast_p.next.next
            if slow_p == fast_p:
                return 1
        return 0
 
 
# Driver program for testing
llist = LinkedList()
llist.push(20)
llist.push(4)
llist.push(15)
llist.push(10)
 
# Create a loop for testing
llist.head.next.next.next.next = llist.head
if(llist.detectLoop()):
    print "Found Loop"
else:
    print "No Loop"
 
# This code is contributed by Nikhil Kumar Singh(nickzuck_007)

C#

// C# program to detect loop in a linked list
using System;
 
public class LinkedList {
    Node head; // head of list
 
    /* Linked list Node*/
    public class Node {
        public int data;
        public Node next;
        public Node(int d)
        {
            data = d;
            next = null;
        }
    }
 
    /* Inserts a new Node at front of the list. */
    public void push(int new_data)
    {
        /* 1 & 2: Allocate the Node &
                Put in the data*/
        Node new_node = new Node(new_data);
 
        /* 3. Make next of new Node as head */
        new_node.next = head;
 
        /* 4. Move the head to point to new Node */
        head = new_node;
    }
 
    Boolean detectLoop()
    {
        Node slow_p = head, fast_p = head;
        while (slow_p != null && fast_p != null
               && fast_p.next != null) {
            slow_p = slow_p.next;
            fast_p = fast_p.next.next;
            if (slow_p == fast_p) {
                return true;
            }
        }
        return false;
    }
 
    /* Driver code */
    public static void Main(String[] args)
    {
        LinkedList llist = new LinkedList();
 
        llist.push(20);
        llist.push(4);
        llist.push(15);
        llist.push(10);
        /*Create loop for testing */
        llist.head.next.next.next.next = llist.head;
 
        Boolean found = llist.detectLoop();
        if (found) {
            Console.WriteLine("Loop Found");
        }
        else {
            Console.WriteLine("No Loop");
        }
    }
}
 
// This code is contributed by Princi Singh

Javascript

<script>
 
// Javascript program to detect loop in a linked list
let head; // head of list
 
/* Linked list Node*/
class Node
{
    constructor(d)
    {
        this.data = d;
        this.next = null;
    }
}
 
/* Inserts a new Node at front of the list. */
function push(new_data)
{
     
    /* 1 & 2: Allocate the Node &
            Put in the data*/
    let new_node = new Node(new_data);
 
    /* 3. Make next of new Node as head */
    new_node.next = head;
 
    /* 4. Move the head to point to new Node */
    head = new_node;
}
 
function detectLoop()
{
    let slow_p = head, fast_p = head;
    let flag = 0;
     
    while (slow_p != null && fast_p != null &&
           fast_p.next != null)
    {
        slow_p = slow_p.next;
        fast_p = fast_p.next.next;
        if (slow_p == fast_p)
        {
            flag = 1;
            break;
        }
    }
    if (flag == 1)
        document.write("Loop found<br>");
    else
        document.write("Loop not found<br>");
}
 
// Driver code
push(20);
push(4);
push(15);
push(10);
 
// Create loop for testing
head.next.next.next.next = head;
 
detectLoop();
 
// This code is contributed by avanitrachhadiya2155
 
</script>

C++

// C++ program to return first node of loop
#include <bits/stdc++.h>
using namespace std;
 
struct Node {
    int key;
    struct Node* next;
};
 
Node* newNode(int key)
{
    Node* temp = new Node;
    temp->key = key;
    temp->next = NULL;
    return temp;
}
 
// A utility function to print a linked list
void printList(Node* head)
{
    while (head != NULL) {
        cout << head->key << " ";
        head = head->next;
    }
    cout << endl;
}
 
// Function to detect first node of loop
// in a linked list that may contain loop
bool detectLoop(Node* head)
{
    // Create a temporary node
    Node* temp = new Node;
    while (head != NULL) {
        // This condition is for the case when there is no loop
        if (head->next == NULL)
            return false;
        // Check if next is already pointing to temp
        if (head->next == temp)
            return true;
        // Store the pointer to the next node
        // in order to get to it in the next step
        Node* next = head->next;
        // Make next point to temp
        head->next = temp;
        // Get to the next node in the list
        head = next;
    }
    return false;
}
 
/* Driver program to test above function*/
int main()
{
    Node* head = newNode(1);
    head->next = newNode(2);
    head->next->next = newNode(3);
    head->next->next->next = newNode(4);
    head->next->next->next->next = newNode(5);
    /* Create a loop for testing(5 is pointing to 3) */
    head->next->next->next->next->next = head->next->next;
    bool found = detectLoop(head);
    if (found)
        cout << "Loop Found";
    else
        cout << "No Loop";
    return 0;
}
 
// This code is contributed by Aditya Kumar (adityakumar129)

C

// C++ program to return first node of loop
#include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
 
typedef struct Node {
    int key;
    struct Node* next;
} Node;
 
Node* newNode(int key)
{
    Node* temp = (Node*)malloc(sizeof(Node));
    temp->key = key;
    temp->next = NULL;
    return temp;
}
 
// A utility function to print a linked list
void printList(Node* head)
{
    while (head != NULL) {
        printf("%d ", head->key);
        head = head->next;
    }
    printf("\n");
}
 
// Function to detect first node of loop
// in a linked list that may contain loop
bool detectLoop(Node* head)
{
    // Create a temporary node
    Node* temp = (Node*)malloc(sizeof(Node));
    while (head != NULL) {
        // This condition is for the case when there is no
        // loop
        if (head->next == NULL)
            return false;
        // Check if next is already pointing to temp
        if (head->next == temp)
            return true;
        // Store the pointer to the next node
        // in order to get to it in the next step
        Node* next = head->next;
        // Make next point to temp
        head->next = temp;
        // Get to the next node in the list
        head = next;
    }
    return false;
}
 
/* Driver program to test above function*/
int main()
{
    Node* head = newNode(1);
    head->next = newNode(2);
    head->next->next = newNode(3);
    head->next->next->next = newNode(4);
    head->next->next->next->next = newNode(5);
    /* Create a loop for testing(5 is pointing to 3) */
    head->next->next->next->next->next = head->next->next;
    bool found = detectLoop(head);
    if (found)
        printf("Loop Found");
    else
        printf("No Loop");
    return 0;
}
 
// This code is contributed by Aditya Kumar (adityakumar129)

Java

// Java program to return first node of loop
class GFG {
 
    static class Node {
        int key;
        Node next;
    };
 
    static Node newNode(int key)
    {
        Node temp = new Node();
        temp.key = key;
        temp.next = null;
        return temp;
    }
 
    // A utility function to print a linked list
    static void printList(Node head)
    {
        while (head != null) {
            System.out.print(head.key + " ");
            head = head.next;
        }
        System.out.println();
    }
 
    // Function to detect first node of loop
    // in a linked list that may contain loop
    static boolean detectLoop(Node head)
    {
 
        // Create a temporary node
        Node temp = new Node();
        while (head != null) {
 
            // This condition is for the case
            // when there is no loop
            if (head.next == null) {
                return false;
            }
 
            // Check if next is already
            // pointing to temp
            if (head.next == temp) {
                return true;
            }
 
            // Store the pointer to the next node
            // in order to get to it in the next step
            Node next = head.next;
 
            // Make next point to temp
            head.next = temp;
 
            // Get to the next node in the list
            head = nex;
        }
 
        return false;
    }
 
    // Driver code
    public static void main(String args[])
    {
        Node head = newNode(1);
        head.next = newNode(2);
        head.next.next = newNode(3);
        head.next.next.next = newNode(4);
        head.next.next.next.next = newNode(5);
 
        // Create a loop for testing(5 is pointing to 3) /
        head.next.next.next.next.next = head.next.next;
 
        boolean found = detectLoop(head);
        if (found)
            System.out.println("Loop Found");
        else
            System.out.println("No Loop");
    }
}
 
// This code is contributed by Arnab Kundu

Python3

# Python3 program to return first node of loop
 
# A binary tree node has data, pointer to
# left child and a pointer to right child
# Helper function that allocates a new node
# with the given data and None left and
# right pointers
 
 
class newNode:
    def __init__(self, key):
        self.key = key
        self.left = None
        self.right = None
 
# A utility function to print a linked list
 
 
def printList(head):
    while (head != None):
        print(head.key, end=" ")
        head = head.next
 
    print()
 
# Function to detect first node of loop
# in a linked list that may contain loop
 
 
def detectLoop(head):
 
    # Create a temporary node
    temp = ""
    while (head != None):
 
        # This condition is for the case
        # when there is no loop
        if (head.next == None):
            return False
 
        # Check if next is already
        # pointing to temp
        if (head.next == temp):
            return True
 
        # Store the pointer to the next node
        # in order to get to it in the next step
        next = head.next
 
        # Make next point to temp
        head.next = temp
 
        # Get to the next node in the list
        head = nex
 
    return False
 
 
# Driver Code
head = newNode(1)
head.next = newNode(2)
head.next.next = newNode(3)
head.next.next.next = newNode(4)
head.next.next.next.next = newNode(5)
 
# Create a loop for testing(5 is pointing to 3)
head.next.next.next.next.next = head.next.next
 
found = detectLoop(head)
if (found):
    print("Loop Found")
else:
    print("No Loop")
 
# This code is contributed by SHUBHAMSINGH10

C#

// C# program to return first node of loop
using System;
public class GFG {
 
    public class Node {
        public int key;
        public Node next;
    };
 
    static Node newNode(int key)
    {
        Node temp = new Node();
        temp.key = key;
        temp.next = null;
        return temp;
    }
 
    // A utility function to print a linked list
    static void printList(Node head)
    {
        while (head != null) {
            Console.Write(head.key + " ");
            head = head.next;
        }
        Console.WriteLine();
    }
 
    // Function to detect first node of loop
    // in a linked list that may contain loop
    static Boolean detectLoop(Node head)
    {
 
        // Create a temporary node
        Node temp = new Node();
        while (head != null) {
 
            // This condition is for the case
            // when there is no loop
            if (head.next == null) {
                return false;
            }
 
            // Check if next is already
            // pointing to temp
            if (head.next == temp) {
                return true;
            }
 
            // Store the pointer to the next node
            // in order to get to it in the next step
            Node next = head.next;
 
            // Make next point to temp
            head.next = temp;
 
            // Get to the next node in the list
            head = nex;
        }
 
        return false;
    }
 
    // Driver code
    public static void Main(String[] args)
    {
        Node head = newNode(1);
        head.next = newNode(2);
        head.next.next = newNode(3);
        head.next.next.next = newNode(4);
        head.next.next.next.next = newNode(5);
 
        // Create a loop for testing(5 is pointing to 3)
        head.next.next.next.next.next = head.next.next;
 
        Boolean found = detectLoop(head);
        if (found) {
            Console.WriteLine("Loop Found");
        }
        else {
            Console.WriteLine("No Loop");
        }
    }
}
 
// This code is contributed by Princi Singh

Javascript

<script>
 
// Javascript program to return first node of loop
class Node
{
    constructor(key)
    {
        this.key = key;
        this.next = null;
    }
}
 
// A utility function to print a linked list
function printList(head)
{
     while (head != null)
    {
        document.write(head.key + " ");
        head = head.next;
    }
    document.write("<br>");
}
 
// Function to detect first node of loop
// in a linked list that may contain loop
function detectLoop(head)
{
     
    // Create a temporary node
    let temp = new Node();
    while (head != null)
    {
         
        // This condition is for the case
        // when there is no loop
        if (head.next == null)
        {
            return false;
        }
 
        // Check if next is already
        // pointing to temp
        if (head.next == temp)
        {
            return true;
        }
 
        // Store the pointer to the next node
        // in order to get to it in the next step
        let next = head.next;
 
        // Make next point to temp
        head.next = temp;
 
        // Get to the next node in the list
        head = nex;
    }
 
    return false;
}
 
// Driver code
let head = new Node(1);
head.next = new Node(2);
head.next.next = new Node(3);
head.next.next.next = new Node(4);
head.next.next.next.next = new Node(5);
 
// Create a loop for testing(5 is pointing to 3) /
head.next.next.next.next.next = head.next.next;
 
let found = detectLoop(head);
if (found)
    document.write("Loop Found");
else
    document.write("No Loop");
 
// This code is contributed by ab2127
 
</script>

C++

// C++ program to return first node of loop
#include <bits/stdc++.h>
using namespace std;
 
struct Node {
    int key;
    struct Node* next;
};
 
Node* newNode(int key)
{
    Node* temp = new Node;
    temp->key = key;
    temp->next = NULL;
    return temp;
}
 
// A utility function to print a linked list
void printList(Node* head)
{
    while (head != NULL) {
        cout << head->key << " ";
        head = head->next;
    }
    cout << endl;
}
 
/*returns distance between first and last node every time
 * last node moves forwards*/
int distance(Node* first, Node* last)
{
    /*counts no of nodes between first and last*/
    int counter = 0;
 
    Node* curr;
    curr = first;
 
    while (curr != last) {
        counter += 1;
        curr = curr->next;
    }
 
    return counter + 1;
}
 
// Function to detect first node of loop
// in a linked list that may contain loop
bool detectLoop(Node* head)
{
 
    // Create a temporary node
    Node* temp = new Node;
 
    Node *first, *last;
 
    /*first always points to head*/
    first = head;
    /*last pointer initially points to head*/
    last = head;
 
    /*current_length stores no of nodes between current
     * position of first and last*/
    int current_length = 0;
 
    /*prev_length stores no of nodes between previous
     * position of first and last*/
    int prev_length = -1;
 
    while (current_length > prev_length && last != NULL) {
        // set prev_length to current length then update the
        // current length
          prev_length = current_length;
        // distance is calculated
        current_length = distance(first, last);
        // last node points the next node
        last = last->next;
    }
     
    if (last == NULL) {
        return false;
    }
    else {
        return true;
    }
}
 
/* Driver program to test above function*/
int main()
{
    Node* head = newNode(1);
    head->next = newNode(2);
    head->next->next = newNode(3);
    head->next->next->next = newNode(4);
    head->next->next->next->next = newNode(5);
 
    /* Create a loop for testing(5 is pointing to 3) */
    head->next->next->next->next->next = head->next->next;
 
    bool found = detectLoop(head);
    if (found)
        cout << "Loop Found";
    else
        cout << "No Loop Found";
 
    return 0;
}

Java

// Java program to return first node of loop
import java.util.*;
class GFG
{
static class Node
{
    int key;
    Node next;
};
 
static Node newNode(int key)
{
    Node temp = new Node();
    temp.key = key;
    temp.next = null;
    return temp;
}
 
// A utility function to print a linked list
static void printList(Node head)
{
    while (head != null)
    {
        System.out.print(head.key + " ");
        head = head.next;
    }
    System.out.println();
}
 
/*returns distance between first and last node every time
 * last node moves forwards*/
static int distance(Node first, Node last)
{
   
    /*counts no of nodes between first and last*/
    int counter = 0;
    Node curr;
    curr = first;
    while (curr != last)
    {
        counter += 1;
        curr = curr.next;
    }
    return counter + 1;
}
 
// Function to detect first node of loop
// in a linked list that may contain loop
static boolean detectLoop(Node head)
{
 
    // Create a temporary node
    Node temp = new Node();
    Node first, last;
 
    /*first always points to head*/
    first = head;
   
    /*last pointer initially points to head*/
    last = head;
 
    /*current_length stores no of nodes between current
     * position of first and last*/
    int current_length = 0;
 
    /*current_length stores no of nodes between previous
     * position of first and last*/
    int prev_length = -1;
    while (current_length > prev_length && last != null)
    {
       
        // set prev_length to current length then update the
        // current length
          prev_length = current_length;
       
        // distance is calculated
        current_length = distance(first, last);
       
        // last node points the next node
        last = last.next;
    }
     
    if (last == null)
    {
        return false;
    }
    else
    {
        return true;
    }
}
 
/* Driver program to test above function*/
public static void main(String[] args)
{
    Node head = newNode(1);
    head.next = newNode(2);
    head.next.next = newNode(3);
    head.next.next.next = newNode(4);
    head.next.next.next.next = newNode(5);
 
    /* Create a loop for testing(5 is pointing to 3) */
    head.next.next.next.next.next = head.next.next;
    boolean found = detectLoop(head);
    if (found)
        System.out.print("Loop Found");
    else
        System.out.print("No Loop Found");
}
}
 
// This code is contributed by gauravrajput1

Python3

# Python program to return first node of loop
class newNode:
    def __init__(self, key):
        self.key = key
        self.left = None
        self.right = None
         
 
# A utility function to print a linked list
def printList(head):
 
    while (head != None) :
        print(head.key, end=" ")
        head = head.next;
     
    print()
 
 
# returns distance between first and last node every time
# last node moves forwards
def distance(first, last):
 
    # counts no of nodes between first and last
    counter = 0
 
    curr = first
 
    while (curr != last):
        counter = counter + 1
        curr = curr.next
     
 
    return counter + 1
 
   
# Function to detect first node of loop
# in a linked list that may contain loop
def detectLoop(head):
 
    # Create a temporary node
    temp = ""
 
    # first always points to head
    first = head;
    # last pointer initially points to head
    last = head;
 
    # current_length stores no of nodes between current
    # position of first and last
    current_length = 0
 
    #current_length stores no of nodes between previous
    # position of first and last*/
    prev_length = -1
 
    while (current_length > prev_length and last != None) :
        # set prev_length to current length then update the
        # current length
        prev_length = current_length
        # distance is calculated
        current_length = distance(first, last)
        # last node points the next node
        last = last.next;
     
     
    if (last == None) :
        return False
     
    else :
        return True
  
 
# Driver program to test above function
 
head = newNode(1);
head.next = newNode(2);
head.next.next = newNode(3);
head.next.next.next = newNode(4);
head.next.next.next.next = newNode(5);
 
# Create a loop for testing(5 is pointing to 3)
head.next.next.next.next.next = head.next.next;
 
found = detectLoop(head)
if (found) :
    print("Loop Found")
else :
    print("No Loop Found")
 
# This code is contributed by ihritik

C#

// C# program to return first node of loop
using System;
 
public class GFG
{
  public
    class Node
    {
      public
        int key;
      public
        Node next;
    };
 
  static Node newNode(int key)
  {
    Node temp = new Node();
    temp.key = key;
    temp.next = null;
    return temp;
  }
 
  // A utility function to print a linked list
  static void printList(Node head)
  {
    while (head != null)
    {
      Console.Write(head.key + " ");
      head = head.next;
    }
    Console.WriteLine();
  }
 
  /*returns distance between first and last node every time
 * last node moves forwards*/
  static int distance(Node first, Node last)
  {
 
    /*counts no of nodes between first and last*/
    int counter = 0;
    Node curr;
    curr = first;
    while (curr != last)
    {
      counter += 1;
      curr = curr.next;
    }
    return counter + 1;
  }
 
  // Function to detect first node of loop
  // in a linked list that may contain loop
  static bool detectLoop(Node head)
  {
 
    // Create a temporary node
    Node temp = new Node();
    Node first, last;
 
    /*first always points to head*/
    first = head;
 
    /*last pointer initially points to head*/
    last = head;
 
    /*current_length stores no of nodes between current
     * position of first and last*/
    int current_length = 0;
 
    /*current_length stores no of nodes between previous
     * position of first and last*/
    int prev_length = -1;
    while (current_length > prev_length && last != null)
    {
 
      // set prev_length to current length then update the
      // current length
      prev_length = current_length;
 
      // distance is calculated
      current_length = distance(first, last);
 
      // last node points the next node
      last = last.next;
    }
 
    if (last == null)
    {
      return false;
    }
    else
    {
      return true;
    }
  }
 
  /* Driver program to test above function*/
  public static void Main(String[] args)
  {
    Node head = newNode(1);
    head.next = newNode(2);
    head.next.next = newNode(3);
    head.next.next.next = newNode(4);
    head.next.next.next.next = newNode(5);
 
    /* Create a loop for testing(5 is pointing to 3) */
    head.next.next.next.next.next = head.next.next;
    bool found = detectLoop(head);
    if (found)
      Console.Write("Loop Found");
    else
      Console.Write("No Loop Found");
  }
}
 
// This code is contributed by gauravrajput1

Javascript

<script>
 
// Javascript program to return first node of loop
class Node
{
    constructor(key)
    {
        this.key = key;
        this.next = null;
    }
}
 
function newNode(key)
{
    let temp = new Node(key);
    return temp;
}
 
// A utility function to print a linked list
function printList(head)
{
    while (head != null)
    {
        document.write(head.key + " ");
        head = head.next;
    }
    document.write("</br>");
}
 
/*returns distance between first and last
node every time last node moves forwards*/
function distance(first, last)
{
 
    /*counts no of nodes between first and last*/
    let counter = 0;
    let curr;
    curr = first;
     
    while (curr != last)
    {
        counter += 1;
        curr = curr.next;
    }
    return counter + 1;
}
 
// Function to detect first node of loop
// in a linked list that may contain loop
function detectLoop(head)
{
 
    // Create a temporary node
    let temp = new Node();
    let first, last;
     
    /*first always points to head*/
    first = head;
     
    /*last pointer initially points to head*/
    last = head;
     
    /*current_length stores no of nodes
    between current position of first and last*/
    let current_length = 0;
     
    /*current_length stores no of nodes between
    previous position of first and last*/
    let prev_length = -1;
     
    while (current_length > prev_length &&
           last != null)
    {
     
        // Set prev_length to current length
        // then update the current length
        prev_length = current_length;
         
        // Distance is calculated
        current_length = distance(first, last);
         
        // Last node points the next node
        last = last.next;
    }
     
    if (last == null)
    {
        return false;
    }
    else
    {
        return true;
    }
}
 
// Driver code
let head = newNode(1);
head.next = newNode(2);
head.next.next = newNode(3);
head.next.next.next = newNode(4);
head.next.next.next.next = newNode(5);
 
/* Create a loop for testing(5 is pointing to 3) */
head.next.next.next.next.next = head.next.next;
let found = detectLoop(head);
if (found)
    document.write("Loop Found");
else
    document.write("No Loop Found");
     
// This code is contributed by divyeshrabadiya07
 
</script>

C++

// C++ program to return first node of loop
#include <bits/stdc++.h>
using namespace std;
 
struct Node {
    int key;
    struct Node* next;
};
 
Node* newNode(int key)
{
    Node* temp = new Node;
    temp->key = key;
    temp->next = NULL;
    return temp;
}
 
// Function to detect first node of loop
// in a linked list that may contain loop
bool detectLoop(Node* head)
{
     
    // If the head is null we will return false
    if (!head)
        return 0;
    else {
       
        // Traversing the linked list
        // for detecting loop
        while (head) {
            // If loop found
            if (head->key == -1) {
                return true;
            }
           
            // Changing the data of visited node to any
            // value which is outside th given range here it
            // is supposed the given range is (1 <= Data on
            // Node <= 10^3)
            else {
                head->key = -1;
                head = head->next;
            }
        }
        // If loop not found return false
        return 0;
    }
}
 
/* Driver program to test above function*/
int main()
{
    Node* head = newNode(1);
    head->next = newNode(2);
    head->next->next = newNode(3);
    head->next->next->next = newNode(4);
    head->next->next->next->next = newNode(5);
 
    /* Create a loop for testing(5 is pointing to 3) */
    head->next->next->next->next->next = head->next->next;
 
    bool found = detectLoop(head);
    cout << found << endl;
    return 0;
}

Java

// Java program to return first node of loop
import java.util.*;
 
class LinkedList{
     
// Head of list
static Node head;
 
// Linked list Node
static class Node
{
    int data;
    Node next;
     
    Node(int d)
    {
        data = d;
        next = null;
    }
}
 
/* Inserts a new Node at front of the list. */
static public void push(int new_data)
{
     
    /* 1 & 2: Allocate the Node &
              Put in the data*/
    Node new_node = new Node(new_data);
 
    /* 3. Make next of new Node as head */
    new_node.next = head;
 
    /* 4. Move the head to point to new Node */
    head = new_node;
}
 
// Function to detect first node of loop
// in a linked list that may contain loop
static boolean detectLoop(Node h)
{
     
    // If the head is null we will return false
    if (head == null)
        return false;
    else
    {
         
        // Traversing the linked list
        // for detecting loop
        while (head != null)
        {
             
            // If loop found
            if (head.data == -1)
            {
                return true;
            }
 
            // Changing the data of visited node to any
            // value which is outside th given range
            // here it is supposed the given range is (1
            // <= Data on Node <= 10^3)
            else
            {
                head.data = -1;
                head = head.next;
            }
        }
         
        // If loop not found return false
        return false;
    }
}
 
// Driver Code
public static void main(String[] args)
{
    LinkedList llist = new LinkedList();
 
    llist.push(1);
    llist.push(2);
    llist.push(3);
    llist.push(4);
    llist.push(5);
 
    /* Create a loop for testing */
    llist.head.next.next.next.next.next = llist.head.next.next;
     
    if (detectLoop(llist.head))
        System.out.println("1");
    else
        System.out.println("0");
}
}
 
// This code is contributed by RohitOberoi

Python3

# Python program to return first node of loop
class Node:
    def __init__(self,d):
        self.data = d
        self.next = None
 
head = None
def push(new_data):
    global head
    new_node = Node(new_data)
    new_node.next = head
    head=new_node
 
def detectLoop(h):
    global head
     
    if (head == None):
        return False
    else:
         
        while (head != None):
            if (head.data == -1):
                return True
            else:
                head.data = -1
                head = head.next
         
        return False
 
push(1);
push(2);
push(3);
push(4);
push(5);
 
head.next.next.next.next.next = head.next.next
 
if (detectLoop(head)):
    print("1")
else:
    print("0")
     
    # This code is contributed by patel2127.

C#

// C# program to return first node of loop
 
using System;
 
public class Node
{
    public int data;
    public Node next;
      
    public Node(int d)
    {
        data = d;
        next = null;
    }
}  
 
public class GFG{
     
    // Head of list
static Node head;
     
    /* Inserts a new Node at front of the list. */
static public void push(int new_data)
{
      
    /* 1 & 2: Allocate the Node &
              Put in the data*/
    Node new_node = new Node(new_data);
  
    /* 3. Make next of new Node as head */
    new_node.next = head;
  
    /* 4. Move the head to point to new Node */
    head = new_node;
}
  
// Function to detect first node of loop
// in a linked list that may contain loop
static bool detectLoop(Node h)
{
      
    // If the head is null we will return false
    if (head == null)
        return false;
    else
    {
          
        // Traversing the linked list
        // for detecting loop
        while (head != null)
        {
              
            // If loop found
            if (head.data == -1)
            {
                return true;
            }
  
            // Changing the data of visited node to any
            // value which is outside th given range
            // here it is supposed the given range is (1
            // <= Data on Node <= 10^3)
            else
            {
                head.data = -1;
                head = head.next;
            }
        }
          
        // If loop not found return false
        return false;
    }
}
  
// Driver Code
     
    static public void Main (){
         
         
  
    push(1);
    push(2);
    push(3);
    push(4);
    push(5);
  
    /* Create a loop for testing */
    head.next.next.next.next.next = head.next.next;
      
    if (detectLoop(head))
        Console.WriteLine("1");
    else
        Console.WriteLine("0");
         
    }
}

Javascript

<script>
// Javascript program to return first node of loop
// Linked list Node
class Node
{
    constructor(d)
    {
        this.data = d;
        this.next = null;
    }
}
 
// Head of list
let head;
 
/* Inserts a new Node at front of the list. */
function push(new_data)
{
    /* 1 & 2: Allocate the Node &
              Put in the data*/
    let new_node = new Node(new_data);
  
    /* 3. Make next of new Node as head */
    new_node.next = head;
  
    /* 4. Move the head to point to new Node */
    head = new_node;
}
 
// Function to detect first node of loop
// in a linked list that may contain loop
function detectLoop(h)
{
    // If the head is null we will return false
    if (head == null)
        return false;
    else
    {
          
        // Traversing the linked list
        // for detecting loop
        while (head != null)
        {
              
            // If loop found
            if (head.data == -1)
            {
                return true;
            }
  
            // Changing the data of visited node to any
            // value which is outside th given range
            // here it is supposed the given range is (1
            // <= Data on Node <= 10^3)
            else
            {
                head.data = -1;
                head = head.next;
            }
        }
          
        // If loop not found return false
        return false;
    }
}
 
// Driver Code
push(1);
push(2);
push(3);
push(4);
push(5);
 
/* Create a loop for testing */
head.next.next.next.next.next = head.next.next;
 
if (detectLoop(head))
    document.write("1");
else
    document.write("0");
 
// This code is contributed by unknown2108
</script>

Publicación traducida automáticamente

Artículo escrito por GeeksforGeeks-1 y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA

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