Dada una array arr[]. La tarea es encontrar la longitud del subarreglo más largo de arr[] tal que contenga solo elementos pares.
Ejemplos:
Input : arr[] = { 5, 2, 4, 7 } Output : Length = 2 subArr[] = {2, 4} Input : arr[] = {9, 8, 5, 4, 4, 4, 2, 4, 1} Output : Length 5 subArr[] = {4, 4, 4, 2, 4}
La idea es observar que el subarreglo más grande con solo elementos pares es el número máximo de elementos pares contiguos en el arreglo. Por lo tanto, la tarea ahora se reduce a encontrar el número máximo de elementos pares contiguos en la array.
Para hacer esto, recorra la array usando dos variables, ans y current_count . La variable ans almacena la respuesta final y current_count almacena la longitud del subarreglo con solo números pares.
Ahora, cada vez que se encuentre un elemento par, siga incrementando el conteo_actual y cada vez que se encuentre un elemento IMPAR, tome el máximo de ans y el conteo_actual y restablezca el conteo_actual a cero.
Al final, ans almacenará la longitud del subarreglo más grande con solo elementos pares.
A continuación se muestra la implementación del enfoque anterior:
C++
// C++ Program to find the Length of the // largest Subarray with only even elements #include <cmath> #include <iostream> using namespace std; // Function to find the Length of the // largest Subarray with only even elements int maxEvenSubarray(int array[], int N) { int ans = 0; int count = 0; // Iterate the loop for (int i = 0; i < N; i++) { // Check whether the element is // even in continuous fashion if (array[i] % 2 == 0) { count++; ans = max(ans, count); } else { // If element are not even in continuous // fashion, Reinitialize the count count = 0; } } // Check for the last element in the array ans = max(ans, count); return ans; } // Driver Code int main() { int arr[] = { 9, 8, 5, 4, 4, 4, 2, 4, 1 }; int N = sizeof(arr) / sizeof(arr[0]); cout << maxEvenSubarray(arr, N); return 0; }
Java
// Java Program to find the Length of the longest // Subarray with only Even Elements public class GFG { // Function to find the Length of the longest // Subarray with only Even Elements static int maxEvenSubarray(int array[], int N) { int ans = 0; int count = 0; // Iterate the loop for (int i = 0; i < array.length; i++) { // Check whether the element is // even in continuous fashion if (array[i] % 2 == 0) { count++; ans = Math.max(ans, count); } else { // If element are not even in continuous // fashion. Reinitialize the count count = 0; } } // Check for the last element in the array ans = Math.max(ans, count); return ans; } // Driver Code public static void main(String args[]) { int arr[] = { 9, 8, 5, 4, 4, 4, 2, 4, 1 }; int N = arr.length; System.out.println(maxEvenSubarray(arr, N)); } }
Python3
# Python3 Program to find the Length of the # largest Subarray with only even elements # Function to find the Length of the # largest Subarray with only even elements def maxEvenSubarray(array,N): ans = 0 count = 0 # Iterate the loop for i in range(0,N): # Check whether the element is # even in continuous fashion if array[i]%2==0: count +=1 ans = max(ans,count) else: # If element are not even in continuous # fashion, Reinitialize the count count = 0 # Check for the last element in the array ans = max(ans,count) return ans # Driver code if __name__=='__main__': arr = [9, 8, 5, 4, 4, 4, 2, 4, 1] N = len(arr) print(maxEvenSubarray(arr,N)) # This article is contributed by Shrikant13
C#
// C# Program to find the Length // of the largest Subarray with // only even elements using System; class GFG { // Function to find the Length // of the largest Subarray with // only even elements static int maxEvenSubarray(int []array, int N) { int ans = 0; int count = 0; // Iterate the loop for (int i = 0; i < N; i++) { // Check whether the element is // even in continuous fashion if (array[i] % 2 == 0) { count++; ans = Math.Max(ans, count); } else { // If element are not even in // continuous fashion, // Reinitialize the count count = 0; } } // Check for the last // element in the array ans = Math.Max(ans, count); return ans; } // Driver Code public static void Main() { int []arr = { 9, 8, 5, 4, 4, 4, 2, 4, 1 }; int N = arr.Length; Console.WriteLine(maxEvenSubarray(arr, N)); } } // This code is contributed by ihritik
PHP
<?php // PHP Program to find the Length // of the largest Subarray with // only even elements // Function to find the Length // of the largest Subarray with // only even elements function maxEvenSubarray($array, $N) { $ans = 0; $count = 0; // Iterate the loop for ($i = 0; $i < $N; $i++) { // Check whether the element is // even in continuous fashion if ($array[$i] % 2 == 0) { $count++; $ans = max($ans, $count); } else { // If element are not even in // continuous fashion, // Reinitialize the count $count = 0; } } // Check for the last // element in the array $ans = max($ans, $count); return $ans; } // Driver Code $arr = array( 9, 8, 5, 4, 4, 4, 2, 4, 1 ); $N = sizeof($arr); echo maxEvenSubarray($arr, $N); // This code is contributed by ihritik ?>
Javascript
<script> // Javascript Program to find the Length // of the largest Subarray with // only even elements // Function to find the Length // of the largest Subarray with // only even elements function maxEvenSubarray(array, N) { let ans = 0; let count = 0; // Iterate the loop for (let i = 0; i < N; i++) { // Check whether the element is // even in continuous fashion if (array[i] % 2 == 0) { count++; ans = Math.max(ans, count); } else { // If element are not even in // continuous fashion, // Reinitialize the count count = 0; } } // Check for the last // element in the array ans = Math.max(ans, count); return ans; } // Driver Code let arr = new Array( 9, 8, 5, 4, 4, 4, 2, 4, 1 ); let N = arr.length; document.write(maxEvenSubarray(arr, N)); // This code is contributed by _saurabh_jaiswal. </script>
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Publicación traducida automáticamente
Artículo escrito por bilal-hungund y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA