Eliminar todos los Nodes de la lista doblemente enlazada que son divisibles por K

Dada una lista doblemente enlazada que contiene N Nodes, la tarea es eliminar todos los Nodes de la lista que son divisibles por K.

Ejemplos: 

Entrada: Lista = 15 <=> 16 <=> 6 <=> 7 <=> 17, K = 2 
Salida: Lista final = 15 <=> 7 <=> 17

Entrada: Lista = 5 <=> 3 <=> 4 <=> 2 <=> 9, K = 3 
Salida: Lista final = 5 <=> 4 <=> 2 

Enfoque: la idea es atravesar los Nodes de la lista doblemente enlazada uno por uno y obtener el puntero de los Nodes que son divisibles por K. Elimine esos Nodes siguiendo el enfoque utilizado en esta publicación.

A continuación se muestra la implementación de la idea anterior: 

C++

// C++ implementation to delete all
// from the doubly linked list which
// are divisible by K
 
#include <bits/stdc++.h>
 
using namespace std;
 
// Node of the doubly linked list
struct Node {
    int data;
    Node *prev, *next;
};
 
// function to insert a node at the beginning
// of the Doubly Linked List
void push(Node** head_ref, int new_data)
{
    // allocate node
    Node* new_node = (Node*)malloc(sizeof(struct Node));
 
    // put in the data
    new_node->data = new_data;
 
    // since we are adding at the beginning,
    // prev is always NULL
    new_node->prev = NULL;
 
    // link the old list off the new node
    new_node->next = (*head_ref);
 
    // change prev of head node to new node
    if ((*head_ref) != NULL)
        (*head_ref)->prev = new_node;
 
    // move the head to point to the new node
    (*head_ref) = new_node;
}
 
// function to delete a node in a Doubly Linked List.
// head_ref --> pointer to head node pointer.
// del --> pointer to node to be deleted
void deleteNode(Node** head_ref, Node* del)
{
    // base case
    if (*head_ref == NULL || del == NULL)
        return;
 
    // If node to be deleted is head node
    if (*head_ref == del)
        *head_ref = del->next;
 
    // Change next only if node to be
    // deleted is NOT the last node
    if (del->next != NULL)
        del->next->prev = del->prev;
 
    // Change prev only if node to be
    // deleted is NOT the first node
    if (del->prev != NULL)
        del->prev->next = del->next;
 
    // Finally, free the memory occupied by del
    free(del);
 
    return;
}
 
// function to delete all nodes from the
// doubly linked list divisible by K
void deleteDivisibleNodes(Node** head_ref, int K)
{
    Node* ptr = *head_ref;
    Node* next;
 
    while (ptr != NULL) {
        next = ptr->next;
        // if true, delete node 'ptr'
        if (ptr->data % K == 0)
            deleteNode(head_ref, ptr);
        ptr = next;
    }
}
 
// function to print nodes in a
// given doubly linked list
void printList(Node* head)
{
    while (head != NULL) {
        cout << head->data << " ";
        head = head->next;
    }
}
 
// Driver program
int main()
{
    // start with the empty list
    Node* head = NULL;
 
    // create the doubly linked list
    // 15 <-> 16 <-> 7 <-> 6 <-> 17
    push(&head, 17);
    push(&head, 6);
    push(&head, 7);
    push(&head, 16);
    push(&head, 15);
 
    int K = 2;
 
    cout << "Original List: ";
    printList(head);
 
    deleteDivisibleNodes(&head, K);
 
    cout << "\nModified List: ";
    printList(head);
}

Java

// Java implementation to delete all
// from the doubly linked list which
// are divisible by K
class GFG
{
     
// Node of the doubly linked list
static class Node
{
    int data;
    Node prev, next;
};
 
// function to insert a node at the beginning
// of the Doubly Linked List
static Node push(Node head_ref, int new_data)
{
    // allocate node
    Node new_node = new Node();
 
    // put in the data
    new_node.data = new_data;
 
    // since we are adding at the beginning,
    // prev is always null
    new_node.prev = null;
 
    // link the old list off the new node
    new_node.next = (head_ref);
 
    // change prev of head node to new node
    if ((head_ref) != null)
        (head_ref).prev = new_node;
 
    // move the head to point to the new node
    (head_ref) = new_node;
    return head_ref;
}
 
// function to delete a node in a Doubly Linked List.
// head_ref -. pointer to head node pointer.
// del -. pointer to node to be deleted
static Node deleteNode(Node head_ref, Node del)
{
    // base case
    if (head_ref == null || del == null)
        return null;
 
    // If node to be deleted is head node
    if (head_ref == del)
        head_ref = del.next;
 
    // Change next only if node to be
    // deleted is NOT the last node
    if (del.next != null)
        del.next.prev = del.prev;
 
    // Change prev only if node to be
    // deleted is NOT the first node
    if (del.prev != null)
        del.prev.next = del.next;
 
    return head_ref;
}
 
// function to delete all nodes from the
// doubly linked list divisible by K
static Node deleteDivisibleNodes(Node head_ref, int K)
{
    Node ptr = head_ref;
    Node next;
 
    while (ptr != null)
    {
        next = ptr.next;
         
        // if true, delete node 'ptr'
        if (ptr.data % K == 0)
            deleteNode(head_ref, ptr);
        ptr = next;
    }
    return head_ref;
}
 
// function to print nodes in a
// given doubly linked list
static void printList(Node head)
{
    while (head != null)
    {
        System.out.print( head.data + " ");
        head = head.next;
    }
}
 
// Driver code
public static void main(String args[])
{
    // start with the empty list
    Node head = null;
 
    // create the doubly linked list
    // 15 <. 16 <. 7 <. 6 <. 17
    head = push(head, 17);
    head = push(head, 6);
    head = push(head, 7);
    head = push(head, 16);
    head = push(head, 15);
 
    int K = 2;
 
    System.out.print( "Original List: ");
    printList(head);
 
    head=deleteDivisibleNodes(head, K);
 
    System.out.print( "\nModified List: ");
    printList(head);
}
}
 
// This code is contributed by Arnab Kundu

Python3

    # Python3 implementation to delete all
# from the doubly linked list which
# are divisible by K
import math
 
# Node of the doubly linked list
class Node:
    def __init__(self,data):
        self.data = data
        self.next = None
 
# function to insert a node at the
# beginning of the Doubly Linked List
def push(head_ref, new_data):
     
    # allocate node
    new_node = Node(new_data)
     
    # put in the data
    new_node.data = new_data
 
    # since we are adding at the beginning,
    # prev is always None
    new_node.prev = None
 
    # link the old list off the new node
    new_node.next = head_ref
 
    # change prev of head node to new node
    if (head_ref != None):
        head_ref.prev = new_node
 
    # move the head to point
    # to the new node
    head_ref = new_node
    return head_ref
 
# function to delete a node
# in a Doubly Linked List.
# head_ref --> pointer to head node pointer.
# del --> pointer to node to be deleted
def deleteNode(head_ref, delete):
     
    # base case
    if (head_ref == None or delete == None):
        return
 
    # If node to be deleted is head node
    if (head_ref == delete):
        head_ref = delete.next
 
    # Change next only if node to be
    # deleted is NOT the last node
    if (delete.next != None):
        delete.next.prev = delete.prev
 
    # Change prev only if node to be
    # deleted is NOT the first node
    if (delete.prev != None):
        delete.prev.next = delete.next
 
    # Finally, free the memory
    # occupied by del, free(del)
    return
 
# function to delete all nodes from the
# doubly linked list divisible by K
def deleteDivisibleNodes(head_ref, K):
    ptr = head_ref
    #next
 
    while (ptr != None) :
        next = ptr.next
         
        # if true, delete node 'ptr'
        if (ptr.data % K == 0):
            deleteNode(head_ref, ptr)
        ptr = next
 
# function to print nodes in a
# given doubly linked list
def printList(head):
    while (head != None):
        print(head.data, end = " ")
        head = head.next
 
# Driver Code
if __name__=='__main__':
 
    # start with the empty list
    head = None
 
    # create the doubly linked list
    # 15 <- 16 <- 7 <- 6 <- 17
    head = push(head, 17)
    head = push(head, 6)
    head = push(head, 7)
    head = push(head, 16)
    head = push(head, 15)
 
    K = 2
 
    print("Original List: ", end = "")
    printList(head)
 
    deleteDivisibleNodes(head, K)
 
    print("\nModified List: ", end = "")
    printList(head)
 
# This code is contributed by AbhiThakur

C#

// C# implementation to delete all
// from the doubly linked list which
// are divisible by K
using System;
 
class GFG
{
     
// Node of the doubly linked list
public class Node
{
    public int data;
    public Node prev, next;
};
 
// function to insert a node at the beginning
// of the Doubly Linked List
static Node push(Node head_ref, int new_data)
{
    // allocate node
    Node new_node = new Node();
 
    // put in the data
    new_node.data = new_data;
 
    // since we are adding at the beginning,
    // prev is always null
    new_node.prev = null;
 
    // link the old list off the new node
    new_node.next = (head_ref);
 
    // change prev of head node to new node
    if ((head_ref) != null)
        (head_ref).prev = new_node;
 
    // move the head to point to the new node
    (head_ref) = new_node;
    return head_ref;
}
 
// function to delete a node in a Doubly Linked List.
// head_ref -. pointer to head node pointer.
// del -. pointer to node to be deleted
static Node deleteNode(Node head_ref, Node del)
{
    // base case
    if (head_ref == null || del == null)
        return null;
 
    // If node to be deleted is head node
    if (head_ref == del)
        head_ref = del.next;
 
    // Change next only if node to be
    // deleted is NOT the last node
    if (del.next != null)
        del.next.prev = del.prev;
 
    // Change prev only if node to be
    // deleted is NOT the first node
    if (del.prev != null)
        del.prev.next = del.next;
 
    return head_ref;
}
 
// function to delete all nodes from the
// doubly linked list divisible by K
static Node deleteDivisibleNodes(Node head_ref, int K)
{
    Node ptr = head_ref;
    Node next;
 
    while (ptr != null)
    {
        next = ptr.next;
         
        // if true, delete node 'ptr'
        if (ptr.data % K == 0)
            deleteNode(head_ref, ptr);
        ptr = next;
    }
    return head_ref;
}
 
// function to print nodes in a
// given doubly linked list
static void printList(Node head)
{
    while (head != null)
    {
        Console.Write( head.data + " ");
        head = head.next;
    }
}
 
// Driver code
public static void Main(String []args)
{
    // start with the empty list
    Node head = null;
 
    // create the doubly linked list
    // 15 <. 16 <. 7 <. 6 <. 17
    head = push(head, 17);
    head = push(head, 6);
    head = push(head, 7);
    head = push(head, 16);
    head = push(head, 15);
 
    int K = 2;
 
    Console.Write( "Original List: ");
    printList(head);
 
    head = deleteDivisibleNodes(head, K);
 
    Console.Write( "\nModified List: ");
    printList(head);
}
}
 
// This code contributed by Rajput-Ji

Javascript

<script>
// javascript implementation to delete all
// from the doubly linked list which
// are divisible by K     // Node of the doubly linked list
     class Node {
        constructor(val) {
            this.data = val;
            this.prev = null;
            this.next = null;
        }
    }
 
    // function to insert a node at the beginning
    // of the Doubly Linked List
    function push(head_ref , new_data) {
        // allocate node
var new_node = new Node();
 
        // put in the data
        new_node.data = new_data;
 
        // since we are adding at the beginning,
        // prev is always null
        new_node.prev = null;
 
        // link the old list off the new node
        new_node.next = (head_ref);
 
        // change prev of head node to new node
        if ((head_ref) != null)
            (head_ref).prev = new_node;
 
        // move the head to point to the new node
        (head_ref) = new_node;
        return head_ref;
    }
 
    // function to delete a node in a Doubly Linked List.
    // head_ref -. pointer to head node pointer.
    // del -. pointer to node to be deleted
    function deleteNode(head_ref,  del) {
        // base case
        if (head_ref == null || del == null)
            return null;
 
        // If node to be deleted is head node
        if (head_ref == del)
            head_ref = del.next;
 
        // Change next only if node to be
        // deleted is NOT the last node
        if (del.next != null)
            del.next.prev = del.prev;
 
        // Change prev only if node to be
        // deleted is NOT the first node
        if (del.prev != null)
            del.prev.next = del.next;
 
        return head_ref;
    }
 
    // function to delete all nodes from the
    // doubly linked list divisible by K
    function deleteDivisibleNodes(head_ref , K) {
var ptr = head_ref;
var next;
 
        while (ptr != null) {
            next = ptr.next;
 
            // if true, delete node 'ptr'
            if (ptr.data % K == 0)
                deleteNode(head_ref, ptr);
            ptr = next;
        }
        return head_ref;
    }
 
    // function to print nodes in a
    // given doubly linked list
    function printList(head) {
        while (head != null) {
            document.write(head.data + " ");
            head = head.next;
        }
    }
 
    // Driver code
     
        // start with the empty list
var head = null;
 
        // create the doubly linked list
        // 15 <. 16 <. 7 <. 6 <. 17
        head = push(head, 17);
        head = push(head, 6);
        head = push(head, 7);
        head = push(head, 16);
        head = push(head, 15);
 
        var K = 2;
 
        document.write("Original List: ");
        printList(head);
 
        head = deleteDivisibleNodes(head, K);
 
        document.write("<br/>Modified List: ");
        printList(head);
 
// This code is contributed by todaysgaurav
</script>
Producción: 

Original List: 15 16 7 6 17 
Modified List: 15 7 17

 

Complejidad temporal: O(N), donde N es el número total de Nodes.
 

Publicación traducida automáticamente

Artículo escrito por barykrg y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA

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