Python | ordenar un diccionario

Python, dado un diccionario, realiza una ordenación basada en claves o valores. [Python aplicable >=3.6v].

Entrada : test_dict = {“Gfg”: 5, “is”: 7, “Best”: 2}
Salida : {‘Best’: 2, ‘Gfg’: 5, ‘is’: 7}, {‘is’: 7, ‘Gfg’: 5, ‘Best’: 2}
Explicación : ordenados por claves, en orden ascendente e inverso.

Entrada : test_dict = {“Mejor”: 2, “para”: 9, “geeks”: 8}
Salida : {‘Mejor’: 2, ‘Gfg’: 5, ‘para’: 9}, {‘para’: 9, ‘geeks’: 8, ‘Best’: 2}
Explicación : ordenados por valores, en orden ascendente e inverso.

Caso 1: Ordenar por claves

Esta tarea se realiza usando sorted(), en esto, extraemos las claves usando el primer índice de elementos del diccionario extraídos por items(), y lo pasamos en clave como función lambda personalizada para ordenar por claves. Se agrega «reverse=True» para realizar la ordenación inversa.

# Python3 code to demonstrate working of 
# Sort a Dictionary
# Sort by Keys
  
# initializing dictionary
test_dict = {"Gfg" : 5, "is" : 7, "Best" : 2, "for" : 9, "geeks" : 8}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# using items() to get all items 
# lambda function is passed in key to perform sort by key 
res = {key: val for key, val in sorted(test_dict.items(), key = lambda ele: ele[0])}
  
# printing result 
print("Result dictionary sorted by keys : " + str(res)) 
  
# using items() to get all items 
# lambda function is passed in key to perform sort by key 
# adding "reversed = True" for reversed order
res = {key: val for key, val in sorted(test_dict.items(), key = lambda ele: ele[0], reverse = True)}
  
# printing result 
print("Result dictionary sorted by keys ( in reversed order ) : " + str(res)) 

The original dictionary is : {'Gfg': 5, 'is': 7, 'Best': 2, 'for': 9, 'geeks': 8}
Result dictionary sorted by keys : {'Best': 2, 'Gfg': 5, 'for': 9, 'geeks': 8, 'is': 7}
Result dictionary sorted by keys ( in reversed order ) : {'is': 7, 'geeks': 8, 'for': 9, 'Gfg': 5, 'Best': 2}

Caso 2: Ordenar por valores 

Esta tarea se puede realizar de manera similar a la anterior, la única diferencia es que para extraer valores, el segundo elemento de items() se pasa como comparador. 

# Python3 code to demonstrate working of 
# Sort a Dictionary
# Sort by Values 
  
# initializing dictionary
test_dict = {"Gfg" : 5, "is" : 7, "Best" : 2, "for" : 9, "geeks" : 8}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# using items() to get all items 
# lambda function is passed in key to perform sort by key 
# passing 2nd element of items()
res = {key: val for key, val in sorted(test_dict.items(), key = lambda ele: ele[1])}
  
# printing result 
print("Result dictionary sorted by values : " + str(res)) 
  
# using items() to get all items 
# lambda function is passed in key to perform sort by key 
# passing 2nd element of items()
# adding "reversed = True" for reversed order
res = {key: val for key, val in sorted(test_dict.items(), key = lambda ele: ele[1], reverse = True)}
  
# printing result 
print("Result dictionary sorted by values ( in reversed order ) : " + str(res))

The original dictionary is : {'Gfg': 5, 'is': 7, 'Best': 2, 'for': 9, 'geeks': 8}
Result dictionary sorted by values : {'Best': 2, 'Gfg': 5, 'is': 7, 'geeks': 8, 'for': 9}
Result dictionary sorted by values ( in reversed order ) : {'for': 9, 'geeks': 8, 'is': 7, 'Gfg': 5, 'Best': 2}