Algoritmo para compartir secretos de Shamir | Criptografía

CPP

// C++ implementation of shamir’s
// secret sharing algorithm
 
#include <bits/stdc++.h>
using namespace std;
 
// Function to calculate the value
// of y
// y = poly[0] + x*poly[1] + x^2*poly[2] + ...
int calculate_Y(int x, vector<int>& poly)
{
    // Initializing y
    int y = 0;
    int temp = 1;
 
    // Iterating through the array
    for (auto coeff : poly) {
 
        // Computing the value of y
        y = (y + (coeff * temp));
        temp = (temp * x);
    }
    return y;
}
 
// Function to perform the secret
// sharing algorithm and encode the
// given secret
void secret_sharing(int S, vector<pair<int, int> >& points,
                    int N, int K)
{
    // A vector to store the polynomial
    // coefficient of K-1 degree
    vector<int> poly(K);
 
    // Randomly choose K - 1 numbers but
    // not zero and poly[0] is the secret
    // create polynomial for this
 
    poly[0] = S;
 
    for (int j = 1; j < K; ++j) {
        int p = 0;
        while (p == 0)
 
            // To keep the random values
            // in range not too high
            // we are taking mod with a
            // prime number around 1000
            p = (rand() % 997);
 
        // This is to ensure we did not
        // create a polynomial consisting
        // of zeroes.
        poly[j] = p;
    }
 
    // Generating N points from the
    // polynomial we created
    for (int j = 1; j <= N; ++j) {
        int x = j;
        int y = calculate_Y(x, poly);
 
        // Points created on sharing
        points[j - 1] = { x, y };
    }
}
 
// This structure is used for fraction
// part handling multiplication
// and addition of fraction
struct fraction {
    int num, den;
 
    // A fraction consists of a
    // numerator and a denominator
    fraction(int n, int d)
    {
        num = n, den = d;
    }
 
    // If the fraction is not
    // in its reduced form
    // reduce it by dividing
    // them with their GCD
    void reduce_fraction(fraction& f)
    {
        int gcd = __gcd(f.num, f.den);
        f.num /= gcd, f.den /= gcd;
    }
 
    // Performing multiplication on the
    // fraction
    fraction operator*(fraction f)
    {
        fraction temp(num * f.num, den * f.den);
        reduce_fraction(temp);
        return temp;
    }
 
    // Performing addition on the
    // fraction
    fraction operator+(fraction f)
    {
        fraction temp(num * f.den + den * f.num,
                      den * f.den);
 
        reduce_fraction(temp);
        return temp;
    }
};
 
// Function to generate the secret
// back from the given points
// This function will use Lagrange Basis Polynomial
// Instead of finding the complete Polynomial
// We only required the poly[0] as our secret code,
// thus we can get rid of x terms
int Generate_Secret(int x[], int y[], int M)
{
 
    fraction ans(0, 1);
 
    // Loop to iterate through the given
    // points
    for (int i = 0; i < M; ++i) {
 
        // Initializing the fraction
        fraction l(y[i], 1);
        for (int j = 0; j < M; ++j) {
 
            // Computing the lagrange terms
            if (i != j) {
                fraction temp(-x[j], x[i] - x[j]);
                l = l * temp;
            }
        }
        ans = ans + l;
    }
 
    // Return the secret
    return ans.num;
}
 
// Function to encode and decode the
// given secret by using the above
// defined functions
void operation(int S, int N, int K)
{
 
    // Vector to store the points
    vector<pair<int, int> > points(N);
 
    // Sharing of secret Code in N parts
    secret_sharing(S, points, N, K);
 
    cout << "Secret is divided to " << N
         << " Parts - " << endl;
 
    for (int i = 0; i < N; ++i) {
        cout << points[i].first << " "
             << points[i].second << endl;
    }
 
    cout << "We can generate Secret from any of "
         << K << " Parts" << endl;
 
    // Input any M points from these
    // to get back our secret code.
    int M = 2;
 
    // M can be greater than or equal to threshold but
    // for this example we are taking for threshold
    if (M < K) {
        cout << "Points are less than threshold "
             << K << " Points Required" << endl;
    }
 
    int* x = new int[M];
    int* y = new int[M];
 
    // Input M points you will get the secret
    // Let these points are first M points from
    // the N points which we shared above
    // We can take any M points
 
    for (int i = 0; i < M; ++i) {
        x[i] = points[i].first;
        y[i] = points[i].second;
    }
 
    // Get back our result again.
    cout << "Our Secret Code is : "
         << Generate_Secret(x, y, M) << endl;
}
 
// Driver Code
int main()
{
    int S = 65;
    int N = 4;
    int K = 2;
 
    operation(S, N, K);
    return 0;
}