El método Uri.IsWellFormedOriginalString() se utiliza para mostrar si la string utilizada para construir este Uri estaba bien formada y no es necesario que se escape más.
Sintaxis: public bool IsWellFormedOriginalString();
Valor de retorno: este método devuelve verdadero si la string estaba bien formada; de lo contrario, es falso.
Los siguientes programas ilustran el uso del método Uri.IsWellFormedOriginalString() :
Ejemplo 1:
// C# program to demonstrate the
// Uri.IsWellFormedOriginalString()
// Method
using System;
using System.Globalization;
class GFG {
// Main Method
public static void Main()
{
// Declaring and initializing address
Uri address1 = new Uri("http://www.contoso.com/index.htm#search");
// Validating if Uri is well formed or not
// using IsWellFormedOriginalString() method
bool value = address1.IsWellFormedOriginalString();
// Displaying the result
if (value)
Console.WriteLine("uri is well formed");
else
Console.WriteLine("uri is not well formed");
}
}
Producción:
uri is well formed
Ejemplo 2:
// C# program to demonstrate the
// Uri.IsWellFormedOriginalString()
// Method
using System;
using System.Globalization;
class GFG {
// Main Method
public static void Main()
{
try {
// calling get() method
get(new Uri("http://www.contoso.com/path"));
// if The string is not correctly escaped.
get(new Uri("http://www.contoso.com/path???/file name"));
// The string is an absolute Uri
// that represents an implicit
// file Uri.
get(new Uri("c:\\directory\filename"));
// The string is an absolute URI that
// is missing a slash before the path.
get(new Uri("file://c:/directory/filename"));
// The parser for the Uri.Scheme indicates
// that the original string was not well-formed.
get(new Uri("xy11.z://www.contoso.com/path/file"));
// The string contains unescaped backslashes
// even if they are treated as forwarding slashes.
get(new Uri("http:\\host/path/file"));
// The string represents a hierarchical
// absolute Uri and does not contain "://".
get(new Uri("www.contoso.com/path/file"));
}
catch (UriFormatException e)
{
Console.Write("uri is so poorly formed that system thrown ");
Console.Write("{0}", e.GetType(), e.Message);
Environment.Exit(1);
}
}
// defining get() method
public static void get(Uri address)
{
// Validating if Uri is well formed or not
// using IsWellFormedOriginalString() method
bool value = address.IsWellFormedOriginalString();
// Displaying the result
if (value)
Console.WriteLine("uri is well formed");
else
Console.WriteLine("uri is poorly formed");
}
}
Producción:
uri is well formed uri is poorly formed uri is poorly formed uri is poorly formed uri is well formed uri is so poorly formed that system thrown System.UriFormatException
Referencia:
Publicación traducida automáticamente
Artículo escrito por RohitPrasad3 y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA