¿Cómo ordenar una array de fechas en C/C++?

// C++ program to sort an array of dates
#include<bits/stdc++.h>
using namespace std;
  
// Structure for date
struct Date
{
    int day, month, year;
};
  
// This is the compare function used by the in-built sort
// function to sort the array of dates.
// It takes two Dates as parameters (const is
// given to tell the compiler that the value won't be
// changed during the compare - this is for optimization..)
  
// Returns true if dates have to be swapped and returns
// false if not. Since we want ascending order, we return
// true if the first Date is less than the second date
bool compare(const Date &d1, const Date &d2)
{
    // All cases when true should be returned
    if (d1.year < d2.year)
        return true;
    if (d1.year == d2.year && d1.month < d2.month)
        return true;
    if (d1.year == d2.year && d1.month == d2.month &&
                              d1.day < d2.day)
        return true;
  
    // If none of the above cases satisfy, return false
    return false;
}
  
// Function to sort array arr[0..n-1] of dates
void sortDates(Date arr[], int n)
{
    // Calling in-built sort function.
    // First parameter array beginning,
    // Second parameter - array ending,
    // Third is the custom compare function
    sort(arr, arr+n, compare);
}
  
// Driver Program
int main()
{
    Date arr[] = {{20,  1, 2014},
                  {25,  3, 2010},
                  { 3, 12, 1676},
                  {18, 11, 1982},
                  {19,  4, 2015},
                  { 9,  7, 2015}};
    int n = sizeof(arr)/sizeof(arr[0]);
  
    sortDates(arr, n);
  
    cout << "Sorted dates are\n";
    for (int i=0; i<n; i++)
    {
        cout << arr[i].day << " " << arr[i].month
             << " " << arr[i].year;
        cout << endl;
    }
}