Compruebe si X puede dar cambio a cada persona en la cola

Dada una array de N enteros donde A i denota la moneda del billete que tiene la i-ésima persona. Las monedas posibles son 5, 10 y 20. Todas las N personas están haciendo cola esperando comprar un helado de X que cuesta Rs 5. Inicialmente, X tiene un saldo inicial de 0. Compruebe si X podrá dar cambio a todas las personas que están esperando para comprar helado.

Ejemplos:  

C++

// C++ program to check whether X can give change
// to every person in the Queue
#include <bits/stdc++.h>
using namespace std;
  
// Function to check if every person will
// get the change from X
int isChangeable(int notes[], int n)
{
    // To count the 5$ and 10& notes
    int fiveCount = 0;
    int tenCount = 0;
  
    // Serve the customer in order
    for (int i = 0; i < n; i++) {
  
        // Increase the number of 5$ note by one
        if (notes[i] == 5)
            fiveCount++;
        else if (notes[i] == 10) {
  
            // decrease the number of note 5$ and
            // increase 10$ note by one
            if (fiveCount > 0) {
                fiveCount--;
                tenCount++;
            }
            else
                return 0;
        }
        else {
  
            // decrease 5$ and 10$ note by one
            if (fiveCount > 0 && tenCount > 0) {
                fiveCount--;
                tenCount--;
            }
  
            // decrease 5$ note by three
            else if (fiveCount >= 3) {
                fiveCount -= 3;
            }
            else
                return 0;
        }
    }
  
    return 1;
}
// Driver Code
int main()
{
    // queue of customers with available notes.
    int a[] = { 5, 5, 5, 10, 20 };
    int n = sizeof(a) / sizeof(a[0]);
  
    // Calling function
    if (isChangeable(a, n))
        cout << "YES";
    else
        cout << "NO";
  
    return 0;
}

Java

// Java program to check 
// whether X can give 
// change to every person 
// in the Queue
import java.io.*;
  
class GFG 
{
      
// Function to check if
// every person will
// get the change from X
static int isChangeable(int notes[], 
                        int n)
{
    // To count the 5$
    // and 10& notes
    int fiveCount = 0;
    int tenCount = 0;
  
    // Serve the customer 
    // in order
    for (int i = 0; i < n; i++) 
    {
  
        // Increase the number
        // of 5$ note by one
        if (notes[i] == 5)
            fiveCount++;
        else if (notes[i] == 10) 
        {
  
            // decrease the number 
            // of note 5$ and 
            // increase 10$ note by one
            if (fiveCount > 0) 
            {
                fiveCount--;
                tenCount++;
            }
            else
                return 0;
        }
        else 
        {
  
            // decrease 5$ and 
            // 10$ note by one
            if (fiveCount > 0 && 
                tenCount > 0) 
            {
                fiveCount--;
                tenCount--;
            }
  
            // decrease 5$ 
            // note by three
            else if (fiveCount >= 3) 
            {
                fiveCount -= 3;
            }
            else
                return 0;
        }
    }
  
    return 1;
}
  
// Driver Code
public static void main (String[] args) 
{
      
// queue of customers 
// with available notes.
int a[] = {5, 5, 5, 10, 20};
int n = a.length;
  
// Calling function
if (isChangeable(a, n) > 0)
    System.out.print("YES");
else
    System.out.print("NO");
}
}
  
// This code is contributed 
// by anuj_67.

Python3

# Python program to check whether X can 
# give change to every person in the Queue
  
# Function to check if every person 
# will get the change from X
def isChangeable(notes, n):
      
    # To count the 5$ and 10& notes
    fiveCount = 0
    tenCount = 0
      
    # Serve the customer in order
    for i in range(n):
          
        # Increase the number of 5$ note by one
        if (notes[i] == 5):
            fiveCount += 1
        elif(notes[i] == 10):
              
            # decrease the number of note 5$ 
            # and increase 10$ note by one
            if (fiveCount > 0):
                fiveCount -= 1
                tenCount += 1
            else:
                return 0
        else:
              
            # decrease 5$ and 10$ note by one
            if (fiveCount > 0 and tenCount > 0):
                fiveCount -= 1
                tenCount -= 1
                  
            # decrease 5$ note by three
            elif (fiveCount >= 3):
                fiveCount -= 3
            else:
                return 0
    return 1
  
# Driver Code
  
# queue of customers with available notes.
a = [5, 5, 5, 10, 20 ]
n = len(a)
  
# Calling function
if (isChangeable(a, n)):
    print("YES")
else:
    print("NO")
  
# This code is contributed by PrinciRaj1992

C#

// C# program to check 
// whether X can give 
// change to every person 
// in the Queue
using System;
  
class GFG 
{
      
// Function to check if
// every person will
// get the change from X
static int isChangeable(int []notes, 
                        int n)
{
    // To count the 5$
    // and 10& notes
    int fiveCount = 0;
    int tenCount = 0;
  
    // Serve the customer 
    // in order
    for (int i = 0; i < n; i++) 
    {
  
        // Increase the number
        // of 5$ note by one
        if (notes[i] == 5)
            fiveCount++;
        else if (notes[i] == 10) 
        {
  
            // decrease the number 
            // of note 5$ and 
            // increase 10$ note by one
            if (fiveCount > 0) 
            {
                fiveCount--;
                tenCount++;
            }
            else
                return 0;
        }
        else
        {
  
            // decrease 5$ and 
            // 10$ note by one
            if (fiveCount > 0 && 
                tenCount > 0) 
            {
                fiveCount--;
                tenCount--;
            }
  
            // decrease 5$ 
            // note by three
            else if (fiveCount >= 3) 
            {
                fiveCount -= 3;
            }
            else
                return 0;
        }
    }
  
    return 1;
}
  
// Driver Code
public static void Main () 
{
      
// queue of customers 
// with available notes.
int []a = {5, 5, 5, 10, 20};
int n = a.Length;
  
// Calling function
if (isChangeable(a, n) > 0)
    Console.WriteLine("YES");
else
    Console.WriteLine("NO");
}
}
  
// This code is contributed 
// by anuj_67.

Javascript

<script>
    // Javascript program to check 
    // whether X can give 
    // change to every person 
    // in the Queue
      
    // Function to check if
    // every person will
    // get the change from X
    function isChangeable(notes, n)
    {
        // To count the 5$
        // and 10& notes
        let fiveCount = 0;
        let tenCount = 0;
  
        // Serve the customer 
        // in order
        for (let i = 0; i < n; i++) 
        {
  
            // Increase the number
            // of 5$ note by one
            if (notes[i] == 5)
                fiveCount++;
            else if (notes[i] == 10) 
            {
  
                // decrease the number 
                // of note 5$ and 
                // increase 10$ note by one
                if (fiveCount > 0) 
                {
                    fiveCount--;
                    tenCount++;
                }
                else
                    return 0;
            }
            else
            {
  
                // decrease 5$ and 
                // 10$ note by one
                if (fiveCount > 0 && 
                    tenCount > 0) 
                {
                    fiveCount--;
                    tenCount--;
                }
  
                // decrease 5$ 
                // note by three
                else if (fiveCount >= 3) 
                {
                    fiveCount -= 3;
                }
                else
                    return 0;
            }
        }
  
        return 1;
    }
      
    // queue of customers 
    // with available notes.
    let a = [5, 5, 5, 10, 20];
    let n = a.length;
  
    // Calling function
    if (isChangeable(a, n) > 0)
        document.write("YES");
    else
        document.write("NO");
      
</script>

Publicación traducida automáticamente

Artículo escrito por Sukanta_it y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA

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