Convierta números en representación binaria y agréguelos sin llevar

Dados dos números N y M . La tarea de convertir ambos números en forma binaria luego agrega los bits respectivos de ambos números binarios convertidos pero con una condición dada de que no hay ningún sistema de acarreo en esta adición. 
 

Input: N = 37, M = 12
Output: 41

Input: N = 456, M = 854
Output: 670

Acercarse: 
 

• Si no consideramos el acarreo, la suma binaria de dos bits será: 
   

    1 + 0 = 1
    0 + 1 = 1
    0 + 0 = 0
    1 + 1 = 0 (No carry)

• Si observa claramente, notará que esto es solo XOR bit a bit de dos números. 
   

A continuación se muestra la implementación del enfoque anterior. 
 

// C++ program to add two binary
// number without carry
#include<bits/stdc++.h>
using namespace std;
 
// Function returns sum of both
// the binary number without
// carry
int NoCarrySum(int N, int M)
{
    // XOR of N and M
    return N ^ M;
}
     
// Driver code
int main()
{
    int N = 37;
    int M = 12;
     
    cout << NoCarrySum(N, M);
    return 0;
}

// Java program to add two binary
// number without carry
import java.util.*;
 
class GFG{
 
// Function returns sum of both
// the binary number without
// carry
static int NoCarrySum(int N, int M)
{
    // XOR of N and M
    return N ^ M;
}
     
// Driver code
public static void main(String[] args)
{
    int N = 37;
    int M = 12;
    System.out.print(NoCarrySum(N, M));
}
}
 
// This code is contributed by amal kumar choubey

# Python3 program to add two binary
# number without carry
 
# Function returns sum of both
# the binary number without
# carry
def NoCarrySum(N, M):
 
    # XOR of N and M
    return N ^ M
 
# Driver code
N = 37
M = 12
print(NoCarrySum(N, M))
 
# This code is contributed by sayesha

// C# program to add two binary
// number without carry
using System;
 
class GFG{
 
// Function returns sum of both
// the binary number without
// carry
static int NoCarrySum(int N, int M)
{
     
    // XOR of N and M
    return N ^ M;
}
     
// Driver code
static public void Main(String[] args)
{
    int N = 37;
    int M = 12;
    Console.Write(NoCarrySum(N, M));
}
}
 
// This code is contributed by Rajput-Ji

<script>
 
// Javascript program to add two binary
// number without carry
 
// Function returns sum of both
// the binary number without
// carry
function NoCarrySum(N, M)
{
    // XOR of N and M
    return N ^ M;
}
     
// Driver code
    let N = 37;
    let M = 12;
     
    document.write(NoCarrySum(N, M));
 
</script>

41