Dada una lista doblemente enlazada que contiene N Nodes, la tarea es eliminar todos los Nodes de la lista que son divisibles por K.
Ejemplos:
Entrada: Lista = 15 <=> 16 <=> 6 <=> 7 <=> 17, K = 2
Salida: Lista final = 15 <=> 7 <=> 17Entrada: Lista = 5 <=> 3 <=> 4 <=> 2 <=> 9, K = 3
Salida: Lista final = 5 <=> 4 <=> 2
Enfoque: la idea es atravesar los Nodes de la lista doblemente enlazada uno por uno y obtener el puntero de los Nodes que son divisibles por K. Elimine esos Nodes siguiendo el enfoque utilizado en esta publicación.
A continuación se muestra la implementación de la idea anterior:
C++
// C++ implementation to delete all // from the doubly linked list which // are divisible by K #include <bits/stdc++.h> using namespace std; // Node of the doubly linked list struct Node { int data; Node *prev, *next; }; // function to insert a node at the beginning // of the Doubly Linked List void push(Node** head_ref, int new_data) { // allocate node Node* new_node = (Node*)malloc(sizeof(struct Node)); // put in the data new_node->data = new_data; // since we are adding at the beginning, // prev is always NULL new_node->prev = NULL; // link the old list off the new node new_node->next = (*head_ref); // change prev of head node to new node if ((*head_ref) != NULL) (*head_ref)->prev = new_node; // move the head to point to the new node (*head_ref) = new_node; } // function to delete a node in a Doubly Linked List. // head_ref --> pointer to head node pointer. // del --> pointer to node to be deleted void deleteNode(Node** head_ref, Node* del) { // base case if (*head_ref == NULL || del == NULL) return; // If node to be deleted is head node if (*head_ref == del) *head_ref = del->next; // Change next only if node to be // deleted is NOT the last node if (del->next != NULL) del->next->prev = del->prev; // Change prev only if node to be // deleted is NOT the first node if (del->prev != NULL) del->prev->next = del->next; // Finally, free the memory occupied by del free(del); return; } // function to delete all nodes from the // doubly linked list divisible by K void deleteDivisibleNodes(Node** head_ref, int K) { Node* ptr = *head_ref; Node* next; while (ptr != NULL) { next = ptr->next; // if true, delete node 'ptr' if (ptr->data % K == 0) deleteNode(head_ref, ptr); ptr = next; } } // function to print nodes in a // given doubly linked list void printList(Node* head) { while (head != NULL) { cout << head->data << " "; head = head->next; } } // Driver program int main() { // start with the empty list Node* head = NULL; // create the doubly linked list // 15 <-> 16 <-> 7 <-> 6 <-> 17 push(&head, 17); push(&head, 6); push(&head, 7); push(&head, 16); push(&head, 15); int K = 2; cout << "Original List: "; printList(head); deleteDivisibleNodes(&head, K); cout << "\nModified List: "; printList(head); }
Java
// Java implementation to delete all // from the doubly linked list which // are divisible by K class GFG { // Node of the doubly linked list static class Node { int data; Node prev, next; }; // function to insert a node at the beginning // of the Doubly Linked List static Node push(Node head_ref, int new_data) { // allocate node Node new_node = new Node(); // put in the data new_node.data = new_data; // since we are adding at the beginning, // prev is always null new_node.prev = null; // link the old list off the new node new_node.next = (head_ref); // change prev of head node to new node if ((head_ref) != null) (head_ref).prev = new_node; // move the head to point to the new node (head_ref) = new_node; return head_ref; } // function to delete a node in a Doubly Linked List. // head_ref -. pointer to head node pointer. // del -. pointer to node to be deleted static Node deleteNode(Node head_ref, Node del) { // base case if (head_ref == null || del == null) return null; // If node to be deleted is head node if (head_ref == del) head_ref = del.next; // Change next only if node to be // deleted is NOT the last node if (del.next != null) del.next.prev = del.prev; // Change prev only if node to be // deleted is NOT the first node if (del.prev != null) del.prev.next = del.next; return head_ref; } // function to delete all nodes from the // doubly linked list divisible by K static Node deleteDivisibleNodes(Node head_ref, int K) { Node ptr = head_ref; Node next; while (ptr != null) { next = ptr.next; // if true, delete node 'ptr' if (ptr.data % K == 0) deleteNode(head_ref, ptr); ptr = next; } return head_ref; } // function to print nodes in a // given doubly linked list static void printList(Node head) { while (head != null) { System.out.print( head.data + " "); head = head.next; } } // Driver code public static void main(String args[]) { // start with the empty list Node head = null; // create the doubly linked list // 15 <. 16 <. 7 <. 6 <. 17 head = push(head, 17); head = push(head, 6); head = push(head, 7); head = push(head, 16); head = push(head, 15); int K = 2; System.out.print( "Original List: "); printList(head); head=deleteDivisibleNodes(head, K); System.out.print( "\nModified List: "); printList(head); } } // This code is contributed by Arnab Kundu
Python3
# Python3 implementation to delete all # from the doubly linked list which # are divisible by K import math # Node of the doubly linked list class Node: def __init__(self,data): self.data = data self.next = None # function to insert a node at the # beginning of the Doubly Linked List def push(head_ref, new_data): # allocate node new_node = Node(new_data) # put in the data new_node.data = new_data # since we are adding at the beginning, # prev is always None new_node.prev = None # link the old list off the new node new_node.next = head_ref # change prev of head node to new node if (head_ref != None): head_ref.prev = new_node # move the head to point # to the new node head_ref = new_node return head_ref # function to delete a node # in a Doubly Linked List. # head_ref --> pointer to head node pointer. # del --> pointer to node to be deleted def deleteNode(head_ref, delete): # base case if (head_ref == None or delete == None): return # If node to be deleted is head node if (head_ref == delete): head_ref = delete.next # Change next only if node to be # deleted is NOT the last node if (delete.next != None): delete.next.prev = delete.prev # Change prev only if node to be # deleted is NOT the first node if (delete.prev != None): delete.prev.next = delete.next # Finally, free the memory # occupied by del, free(del) return # function to delete all nodes from the # doubly linked list divisible by K def deleteDivisibleNodes(head_ref, K): ptr = head_ref #next while (ptr != None) : next = ptr.next # if true, delete node 'ptr' if (ptr.data % K == 0): deleteNode(head_ref, ptr) ptr = next # function to print nodes in a # given doubly linked list def printList(head): while (head != None): print(head.data, end = " ") head = head.next # Driver Code if __name__=='__main__': # start with the empty list head = None # create the doubly linked list # 15 <- 16 <- 7 <- 6 <- 17 head = push(head, 17) head = push(head, 6) head = push(head, 7) head = push(head, 16) head = push(head, 15) K = 2 print("Original List: ", end = "") printList(head) deleteDivisibleNodes(head, K) print("\nModified List: ", end = "") printList(head) # This code is contributed by AbhiThakur
C#
// C# implementation to delete all // from the doubly linked list which // are divisible by K using System; class GFG { // Node of the doubly linked list public class Node { public int data; public Node prev, next; }; // function to insert a node at the beginning // of the Doubly Linked List static Node push(Node head_ref, int new_data) { // allocate node Node new_node = new Node(); // put in the data new_node.data = new_data; // since we are adding at the beginning, // prev is always null new_node.prev = null; // link the old list off the new node new_node.next = (head_ref); // change prev of head node to new node if ((head_ref) != null) (head_ref).prev = new_node; // move the head to point to the new node (head_ref) = new_node; return head_ref; } // function to delete a node in a Doubly Linked List. // head_ref -. pointer to head node pointer. // del -. pointer to node to be deleted static Node deleteNode(Node head_ref, Node del) { // base case if (head_ref == null || del == null) return null; // If node to be deleted is head node if (head_ref == del) head_ref = del.next; // Change next only if node to be // deleted is NOT the last node if (del.next != null) del.next.prev = del.prev; // Change prev only if node to be // deleted is NOT the first node if (del.prev != null) del.prev.next = del.next; return head_ref; } // function to delete all nodes from the // doubly linked list divisible by K static Node deleteDivisibleNodes(Node head_ref, int K) { Node ptr = head_ref; Node next; while (ptr != null) { next = ptr.next; // if true, delete node 'ptr' if (ptr.data % K == 0) deleteNode(head_ref, ptr); ptr = next; } return head_ref; } // function to print nodes in a // given doubly linked list static void printList(Node head) { while (head != null) { Console.Write( head.data + " "); head = head.next; } } // Driver code public static void Main(String []args) { // start with the empty list Node head = null; // create the doubly linked list // 15 <. 16 <. 7 <. 6 <. 17 head = push(head, 17); head = push(head, 6); head = push(head, 7); head = push(head, 16); head = push(head, 15); int K = 2; Console.Write( "Original List: "); printList(head); head = deleteDivisibleNodes(head, K); Console.Write( "\nModified List: "); printList(head); } } // This code contributed by Rajput-Ji
Javascript
<script> // javascript implementation to delete all // from the doubly linked list which // are divisible by K // Node of the doubly linked list class Node { constructor(val) { this.data = val; this.prev = null; this.next = null; } } // function to insert a node at the beginning // of the Doubly Linked List function push(head_ref , new_data) { // allocate node var new_node = new Node(); // put in the data new_node.data = new_data; // since we are adding at the beginning, // prev is always null new_node.prev = null; // link the old list off the new node new_node.next = (head_ref); // change prev of head node to new node if ((head_ref) != null) (head_ref).prev = new_node; // move the head to point to the new node (head_ref) = new_node; return head_ref; } // function to delete a node in a Doubly Linked List. // head_ref -. pointer to head node pointer. // del -. pointer to node to be deleted function deleteNode(head_ref, del) { // base case if (head_ref == null || del == null) return null; // If node to be deleted is head node if (head_ref == del) head_ref = del.next; // Change next only if node to be // deleted is NOT the last node if (del.next != null) del.next.prev = del.prev; // Change prev only if node to be // deleted is NOT the first node if (del.prev != null) del.prev.next = del.next; return head_ref; } // function to delete all nodes from the // doubly linked list divisible by K function deleteDivisibleNodes(head_ref , K) { var ptr = head_ref; var next; while (ptr != null) { next = ptr.next; // if true, delete node 'ptr' if (ptr.data % K == 0) deleteNode(head_ref, ptr); ptr = next; } return head_ref; } // function to print nodes in a // given doubly linked list function printList(head) { while (head != null) { document.write(head.data + " "); head = head.next; } } // Driver code // start with the empty list var head = null; // create the doubly linked list // 15 <. 16 <. 7 <. 6 <. 17 head = push(head, 17); head = push(head, 6); head = push(head, 7); head = push(head, 16); head = push(head, 15); var K = 2; document.write("Original List: "); printList(head); head = deleteDivisibleNodes(head, K); document.write("<br/>Modified List: "); printList(head); // This code is contributed by todaysgaurav </script>
Producción:
Original List: 15 16 7 6 17 Modified List: 15 7 17
Complejidad temporal: O(N), donde N es el número total de Nodes.