Escriba un programa para invertir los dígitos de un número entero.
C++
#include <bits/stdc++.h>
using namespace std;
/* Iterative function to reverse digits of num*/
int reverseDigits(int num)
{
int rev_num = 0;
while (num > 0) {
rev_num = rev_num * 10 + num % 10;
num = num / 10;
}
return rev_num;
}
/*Driver program to test reverseDigits*/
int main()
{
int num = 4562;
cout << "Reverse of no. is " << reverseDigits(num);
getchar();
return 0;
}
// This code is contributed
// by Akanksha Rai(Abby_akku)
C
#include <stdio.h>
/* Iterative function to reverse digits of num*/
int reverseDigits(int num)
{
int rev_num = 0;
while (num > 0) {
rev_num = rev_num * 10 + num % 10;
num = num / 10;
}
return rev_num;
}
/*Driver program to test reverseDigits*/
int main()
{
int num = 4562;
printf("Reverse of no. is %d", reverseDigits(num));
getchar();
return 0;
}
Java
// Java program to reverse a number
class GFG {
/* Iterative function to reverse
digits of num*/
static int reverseDigits(int num)
{
int rev_num = 0;
while (num > 0) {
rev_num = rev_num * 10 + num % 10;
num = num / 10;
}
return rev_num;
}
// Driver code
public static void main(String[] args)
{
int num = 4562;
System.out.println("Reverse of no. is "
+ reverseDigits(num));
}
}
// This code is contributed by Anant Agarwal.
Python
# Python program to reverse a number n = 4562 rev = 0 while(n > 0): a = n % 10 rev = rev * 10 + a n = n // 10 print(rev) # This code is contributed by Shariq Raza
C#
// C# program to reverse a number
using System;
class GFG {
// Iterative function to
// reverse digits of num
static int reverseDigits(int num)
{
int rev_num = 0;
while (num > 0) {
rev_num = rev_num * 10 + num % 10;
num = num / 10;
}
return rev_num;
}
// Driver code
public static void Main()
{
int num = 4562;
Console.Write("Reverse of no. is "
+ reverseDigits(num));
}
}
// This code is contributed by Sam007
PHP
<?php
// Iterative function to
// reverse digits of num
function reverseDigits($num)
{
$rev_num = 0;
while($num > 1)
{
$rev_num = $rev_num * 10 +
$num % 10;
$num = (int)$num / 10;
}
return $rev_num;
}
// Driver Code
$num = 4562;
echo "Reverse of no. is ",
reverseDigits($num);
// This code is contributed by aj_36
?>
Javascript
<script>
let num = 4562;
// Function to reverse digits of num
function reverseDigits(num) {
let rev_num = 0;
while(num > 0)
{
rev_num = rev_num * 10 + num % 10;
num = Math.floor(num / 10);
}
return rev_num;
}
// function call
document.write(reverseDigits(num));
// This code is contributed by Surbhi tyagi
</script>
C++
// C++ program to reverse digits of a number
#include <bits/stdc++.h>
using namespace std;
/* Recursive function to reverse digits of num*/
int reverseDigits(int num)
{
static int rev_num = 0;
static int base_pos = 1;
if (num > 0) {
reverseDigits(num / 10);
rev_num += (num % 10) * base_pos;
base_pos *= 10;
}
return rev_num;
}
// Driver Code
int main()
{
int num = 4562;
cout << "Reverse of no. is " << reverseDigits(num);
return 0;
}
// This code is contributed
// by Akanksha Rai(Abby_akku)
C
// C program to reverse digits of a number
#include <stdio.h>;
/* Recursive function to reverse digits of num*/
int reversDigits(int num)
{
static int rev_num = 0;
static int base_pos = 1;
if (num > 0) {
reversDigits(num / 10);
rev_num += (num % 10) * base_pos;
base_pos *= 10;
}
return rev_num;
}
/*Driver program to test reverse Digits*/
int main()
{
int num = 4562;
printf("Reverse of no. is %d", reversDigits(num));
getchar();
return 0;
}
Java
// Java program to reverse digits of a number
// Recursive function to
// reverse digits of num
class GFG {
static int rev_num = 0;
static int base_pos = 1;
static int reversDigits(int num)
{
if (num > 0) {
reversDigits(num / 10);
rev_num += (num % 10) * base_pos;
base_pos *= 10;
}
return rev_num;
}
// Driver Code
public static void main(String[] args)
{
int num = 4562;
System.out.println(reversDigits(num));
}
}
// This code is contributed by mits
Python3
# Python 3 program to reverse digits
# of a number
rev_num = 0
base_pos = 1
# Recursive function to reverse
# digits of num
def reversDigits(num):
global rev_num
global base_pos
if(num > 0):
reversDigits((int)(num / 10))
rev_num += (num % 10) * base_pos
base_pos *= 10
return rev_num
# Driver Code
num = 4562
print("Reverse of no. is ",
reversDigits(num))
# This code is contributed by Rajput-Ji
C#
// C# program to reverse digits of a number
// Recursive function to
// reverse digits of num
using System;
class GFG {
static int rev_num = 0;
static int base_pos = 1;
static int reversDigits(int num)
{
if (num > 0) {
reversDigits(num / 10);
rev_num += (num % 10) * base_pos;
base_pos *= 10;
}
return rev_num;
}
// Driver Code
public static void Main()
{
int num = 4562;
Console.WriteLine(reversDigits(num));
}
}
// This code is contributed
// by inder_verma
PHP
<?php
// PHP program to reverse digits of a number
$rev_num = 0;
$base_pos = 1;
/* Recursive function to
reverse digits of num*/
function reversDigits($num)
{
global $rev_num;
global $base_pos;
if($num > 0)
{
reversDigits((int)($num / 10));
$rev_num += ($num % 10) *
$base_pos;
$base_pos *= 10;
}
return $rev_num;
}
// Driver Code
$num = 4562;
echo "Reverse of no. is ",
reversDigits($num);
// This code is contributed by ajit
?>
Javascript
<script>
// Javascript program to reverse digits of a number
/* Recursive function to reverse digits of num*/
var rev_num = 0;
var base_pos = 1;
function reversDigits(num)
{
if(num > 0)
{
reversDigits(Math.floor(num/10));
rev_num += (num%10)*base_pos;
base_pos *= 10;
}
return rev_num;
}
// Driver Code
let num = 4562;
document.write("Reverse of no. is "
+ reversDigits(num));
// This code is contributed
// by Mayank Tyagi
</script>
C++
// C++ program to reverse a number
#include <bits/stdc++.h>
using namespace std;
int reverseDigits(int num)
{
// converting number to string
string strin = to_string(num);
// reversing the string
reverse(strin.begin(), strin.end());
// converting string to integer
num = stoi(strin);
// returning integer
return num;
}
int main()
{
int num = 4562;
cout << "Reverse of no. is " << reverseDigits(num);
return 0;
}
// This Code is contributed by ShubhamSingh10
Java
// Java program to reverse a number
public class GFG {
static int reversDigits(int num)
{
// converting number to string
StringBuffer string
= new StringBuffer(String.valueOf(num));
// reversing the string
string.reverse();
// converting string to integer
num = Integer.parseInt(String.valueOf(string));
// returning integer
return num;
}
public static void main(String[] args)
{
int num = 4562;
System.out.println("Reverse of no. is "
+ reversDigits(num));
}
}
Python3
# Python 3 program to reverse a number
def reversDigits(num):
# converting number to string
string = str(num)
# reversing the string
string = list(string)
string.reverse()
string = ''.join(string)
# converting string to integer
num = int(string)
# returning integer
return num
# Driver code
if __name__ == "__main__":
num = 4562
print("Reverse of no. is ", reversDigits(num))
# This code is contributed by ukasp.
C#
// C# program to reverse a number
using System;
public class GFG{
public static string ReverseString(string s)
{
char[] array = s.ToCharArray();
Array.Reverse(array);
return new string(array);
}
static int reversDigits(int num)
{
// converting number to string
string strin = num.ToString();
// reversing the string
strin = ReverseString(strin);
// converting string to integer
num = int.Parse(strin);
// returning integer
return num;
}
// Driver code
static public void Main ()
{
int num = 4562;
Console.Write("Reverse of no. is "
+ reversDigits(num));
}
}
// This Code is contributed by ShubhamSingh10
Javascript
<script>
// Javascript program to reverse a number
function reversDigits(num)
{
// converting number to string
let str
= num.toString().split("").reverse().join("");
// converting string to integer
num = parseInt(str);
// returning integer
return str;
}
// Driver Code
let num = 4562;
document.write("Reverse of no. is "
+ reversDigits(num));
</script>
C++
// C++ program for the above approach
#include <bits/stdc++.h>
using namespace std;
int reversDigits(int num){
// converting number to string
string str = to_string(num);
// reversing the string
reverse(str.begin(), str.end());
// converting string to integer
num = stoll(str);
// returning integer
return num;
}
// Driver Code
int main()
{
int num = 4562;
cout << "Reverse of no. is " << reversDigits(num) ;
return 0;
}
// This code is contributed by sanjoy_62.
Python3
# Python 3 program to reverse a number
def reversDigits(num):
# converting number to string
string = str(num)
# reversing the string
string = string[::-1]
# converting string to integer
num = int(string)
# returning integer
return num
# Driver code
if __name__ == "__main__":
num = 4562
print("Reverse of no. is ", reversDigits(num))
# This code is contributed by Susobhan Akhuli
C#
// C# program for the above approach
using System;
class GFG {
static int reversDigits(int num)
{
// converting number to string
string str = Convert.ToString(num);
// reversing the string
char[] charArray = str.ToCharArray();
Array.Reverse(charArray);
str = new string(charArray);
// converting string to integer
num = Convert.ToInt32(str);
// returning integer
return num;
}
// Driver Code
public static void Main(string[] args)
{
int num = 4562;
Console.Write("Reverse of no. is "
+ reversDigits(num));
}
}
// This code is contributed by phasing17
Javascript
// JavaScript program for the above approach
function reversDigits(num){
// converting number to string
let str = num.toString().split("");
// reversing the string
str.reverse();
// converting string to integer
num = parseInt(str.join(""))
// returning integer
return num;
}
// Driver Code
let num = 4562;
console.log("Reverse of no. is " + reversDigits(num));
// This code is contributed by phasing17
Java
// Java program for the above approach
import java.util.*;
class GFG {
static int reversDigits(int num)
{
// converting number to string
String str = String.valueOf(num);
// reversing the string
str = new StringBuilder(str).reverse().toString();
// converting string to integer
num = Integer.valueOf(str);
// returning integer
return num;
}
// Driver Code
public static void main(String[] args)
{
int num = 4562;
System.out.println("Reverse of no. is "
+ reversDigits(num));
}
}
// This code is contributed by phasing17
Publicación traducida automáticamente
Artículo escrito por GeeksforGeeks-1 y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA