El algoritmo Radix Sort
1) Haga lo siguiente para cada dígito i donde i varía del dígito menos significativo al dígito más significativo.
…………. a) Ordene la array de entrada utilizando la ordenación por conteo (o cualquier ordenación estable) de acuerdo con el i-ésimo dígito.
C/C++
// C++ implementation of Radix Sort #include<iostream> using namespace std; // A utility function to get maximum value in arr[] int getMax(int arr[], int n) { int mx = arr[0]; for (int i = 1; i < n; i++) if (arr[i] > mx) mx = arr[i]; return mx; } // A function to do counting sort of arr[] according to // the digit represented by exp. void countSort(int arr[], int n, int exp) { int output[n]; // output array int i, count[10] = {0}; // Store count of occurrences in count[] for (i = 0; i < n; i++) count[ (arr[i]/exp)%10 ]++; // Change count[i] so that count[i] now contains actual // position of this digit in output[] for (i = 1; i < 10; i++) count[i] += count[i - 1]; // Build the output array for (i = n - 1; i >= 0; i--) { output[count[ (arr[i]/exp)%10 ] - 1] = arr[i]; count[ (arr[i]/exp)%10 ]--; } // Copy the output array to arr[], so that arr[] now // contains sorted numbers according to current digit for (i = 0; i < n; i++) arr[i] = output[i]; } // The main function to that sorts arr[] of size n using // Radix Sort void radixsort(int arr[], int n) { // Find the maximum number to know number of digits int m = getMax(arr, n); // Do counting sort for every digit. Note that instead // of passing digit number, exp is passed. exp is 10^i // where i is current digit number for (int exp = 1; m/exp > 0; exp *= 10) countSort(arr, n, exp); } // A utility function to print an array void print(int arr[], int n) { for (int i = 0; i < n; i++) cout << arr[i] << " "; } // Driver program to test above functions int main() { int arr[] = {170, 45, 75, 90, 802, 24, 2, 66}; int n = sizeof(arr)/sizeof(arr[0]); radixsort(arr, n); print(arr, n); return 0; }
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Publicación traducida automáticamente
Artículo escrito por GeeksforGeeks-1 y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA