Programa de Python para la suma de números consecutivos con superposición en listas

Dada una Lista, realizar la suma de elementos consecutivos, por superposición.

Entrada : test_list = [4, 7, 3, 2] 
Salida : [11, 10, 5, 6] 
Explicación : 4 + 7 = 11, 7 + 3 = 10, 3 + 2 = 5 y 2 + 4 = 6 . 

Entrada : test_list = [4, 7, 3] 
Salida : [11, 10, 7] 
Explicación : 4+7=11, 7+3=10, 3+4=7. 
 

Método 1: usar la lista de comprensión + zip()

En esto, comprimimos la lista, con elementos consecutivos usando zip() y luego realizamos la suma usando el operador +. La parte de la iteración se realiza utilizando la comprensión de listas.

# initializing list
test_list = [4, 7, 3, 2, 9, 2, 1]
  
# printing original list
print("The original list is : " + str(test_list))
  
# using zip() to get pairing.
# last element is joined with first for pairing
res = [a + b for a, b in zip(test_list, test_list[1:] + [test_list[0]])]
  
# printing result
print("The Consecutive overlapping Summation : " + str(res))

The original list is : [4, 7, 3, 2, 9, 2, 1]
The Consecutive overlapping Summation : [11, 10, 5, 11, 11, 3, 5]

Método #2: Usando sum() + comprensión de lista + zip()

En esto, realizamos la tarea de obtener la suma usando sum() y todas las funcionalidades se mantienen de manera similar al método anterior.

# Python3 code to demonstrate working of 
# Consecutive overlapping Summation
# Using sum() + list comprehension + zip()
  
# initializing list
test_list = [4, 7, 3, 2, 9, 2, 1]
  
# printing original list
print("The original list is : " + str(test_list))
  
# using sum() to compute elements sum
# last element is joined with first for pairing
res = [sum(sub) for sub in zip(test_list, test_list[1:] + [test_list[0]])]  
  
# printing result 
print("The Consecutive overlapping Summation : " + str(res))

The original list is : [4, 7, 3, 2, 9, 2, 1]
The Consecutive overlapping Summation : [11, 10, 5, 11, 11, 3, 5]