Programa para hallar el punto medio de una recta

Dadas dos coordenadas de una línea que comienza en (x1,y1) y termina en (x2,y2), encuentre el punto medio de una línea. 
Ejemplos: 
 

Input  : x1 = –1, y1 = 2, 
         x2 = 3, y2 = –6
Output : 1,–2

Input  : x1 = 6.4, y1 = 3 
         x2 = –10.7, y2 = 4
Output : –2.15, 3.5

La fórmula del punto medio: El punto medio de dos puntos, (x1, y2) y (x2, y2) es el punto M encontrado por la siguiente fórmula: M = ((x ₁ +x ₂ )/2 , (y ₁ +y ₂ )/2)
 

// C++ program to find
// the midpoint of a line
#include<iostream>
using namespace std;
 
// function to find the
// midpoint of a line
void midpoint(int x1, int x2,
                int y1, int y2)
{
    cout << (float)(x1+x2)/2 <<
            " , "<< (float)(y1+y2)/2 ;
}
 
// Driver Function to test above
int main()
{
    int x1 =-1, y1 = 2  ;
    int x2 = 3, y2 = -6 ;   
    midpoint(x1, x2, y1, y2);   
    return 0;
}

// Java program to find
// the midpoint of a line
import java.io.*;
 
class GFG
{
    // function to find the
    // midpoint of a line
    static void midpoint(int x1, int x2,
                          int y1, int y2)
    {
        System.out.print((x1 + x2) / 2 +
                        " , " + (y1 + y2) / 2) ;
    }
 
    // Driver code
    public static void main (String[] args)
    {
        int x1 =-1, y1 = 2 ;
        int x2 = 3, y2 = -6 ;
        midpoint(x1, x2, y1, y2);
             
    }
}
 
// This code is contributed by vt_m.

# Python3 program to find
# the midpoint of a line
 
# Function to find the
# midpoint of a line
def midpoint(x1, x2, y1, y2):
 
    print((x1 + x2) // 2, " , ",
                 (y1 + y2) // 2)
  
# Driver Code
x1, y1, x2, y2 = -1, 2, 3, -6
midpoint(x1, x2, y1, y2)
 
# This code is contributed by Anant Agarwal.

// C# program to find
// the midpoint of a line
using System;
 
class GFG
{
    // function to find the
    // midpoint of a line
    static void midpoint(int x1, int x2,
                        int y1, int y2)
    {
        Console.WriteLine((x1 + x2) / 2 +
                        " , " + (y1 + y2) / 2) ;
    }
 
    // Driver code
    public static void Main ()
    {
        int x1 =-1, y1 = 2 ;
        int x2 = 3, y2 = -6 ;
         
        midpoint(x1, x2, y1, y2);
             
    }
}
 
// This code is contributed by vt_m.

<?php
// PHP program to find
// the midpoint of a line
 
// function to find the
// midpoint of a line
function midpoint($x1, $x2, $y1, $y2)
{
    echo((float)($x1 + $x2)/2 . " , " .
                (float)($y1 + $y2)/2) ;
}
 
// Driver Code
$x1 = -1; $y1 = 2 ;
$x2 = 3; $y2 = -6 ;    
midpoint($x1, $x2, $y1, $y2);
 
// This code is contributed by Ajit.
?>

<script>
 
// JavaScript program to find
// the midpoint of a line
 
// function to find the
    // midpoint of a line
    function midpoint(x1, x2,
                          y1, y2)
    {
        document.write((x1 + x2) / 2 +
                        " , " + (y1 + y2) / 2) ;
    }
 
// Driver code
         
        let x1 =-1, y1 = 2 ;
        let x2 = 3, y2 = -6 ;
        midpoint(x1, x2, y1, y2);
                   
</script>

Producción : 

1 , -2

Complejidad de tiempo: O(1) ya que realiza solo operaciones constantes

Espacio Auxiliar: O(1)