Programa para imprimir todos los números divisibles por 3 y 5 para un número dado

Dado el entero N, la tarea es imprimir todos los números menores que N, que son divisibles por 3 y 5.
Ejemplos: 
 

Input : 50
Output : 0 15 30 45 

Input : 100
Output : 0 15 30 45 60 75 90 

Enfoque: Por ejemplo, tomemos N = 20 como límite, luego el programa debe imprimir todos los números menores que 20 que son divisibles por 3 y 5. Para esto, divida cada número de 0 a N por 3 y 5 y verifique su resto. Si el resto es 0 en ambos casos, simplemente imprima ese número.
A continuación se muestra la implementación: 
 

// C++ program to print all the numbers
// divisible by 3 and 5 for a given number
#include <iostream>
using namespace std;
 
// Result function with N
void result(int N)
{    
    // iterate from 0 to N
    for (int num = 0; num < N; num++)
    {    
        // Short-circuit operator is used
        if (num % 3 == 0 && num % 5 == 0)
            cout << num << " ";
    }
}
 
// Driver code
int main()
{    
    // input goes here
    int N = 100;
     
    // Calling function
    result(N);
    return 0;
}
 
// This code is contributed by Manish Shaw
// (manishshaw1)

// Java program to print all the numbers
// divisible by 3 and 5 for a given number
 
class GFG{
     
    // Result function with N
    static void result(int N)
    {    
        // iterate from 0 to N
        for (int num = 0; num < N; num++)
        {    
            // Short-circuit operator is used
            if (num % 3 == 0 && num % 5 == 0)
                System.out.print(num + " ");
        }
    }
      
    // Driver code
    public static void main(String []args)
    {
        // input goes here
        int N = 100;
          
        // Calling function
        result(N);
    }
}

# Python program to print all the numbers
# divisible by 3 and 5 for a given number
 
# Result function with N
def result(N):
     
    # iterate from 0 to N
    for num in range(N):
         
            # Short-circuit operator is used
            if num % 3 == 0 and num % 5 == 0:
                print(str(num) + " ", end = "")
                 
            else:
                pass
 
# Driver code
if __name__ == "__main__":
     
    # input goes here
    N = 100
     
    # Calling function
    result(N)

// C# program to print all the numbers
// divisible by 3 and 5 for a given number
using System;
public class GFG{
     
    // Result function with N
    static void result(int N)
    {    
        // iterate from 0 to N
        for (int num = 0; num < N; num++)
        {    
            // Short-circuit operator is used
            if (num % 3 == 0 && num % 5 == 0)
                Console.Write(num + " ");
        }
    }
     
    // Driver code
    static public void Main (){
        // input goes here
        int N = 100;
        // Calling function
        result(N);
    }
//This code is contributed by ajit.   
}

<?php
// PHP program to print all the numbers
// divisible by 3 and 5 for a given number
 
// Result function with N
function result($N)
{
    // iterate from 0 to N
    for ($num = 0; $num < $N; $num++)
    {
        // Short-circuit operator is used
        if ($num % 3 == 0 && $num % 5 == 0)
            echo $num, " ";
    }
}
 
// Driver code
     
// input goes here
$N = 100;
 
// Calling function
result($N);
 
// This code is contributed by ajit
?>

<script>
 
// Javascript  program to
// print all the numbers
// divisible by 3 and 5
// for a given number
 
// Result function with N
function result(N)
{
    // iterate from 0 to N
    for (let num = 0; num < N; num++)
    {
        // Short-circuit operator is used
        if (num % 3 == 0 && num % 5 == 0)
            document.write( num+ " ");
    }
}
 
// Driver code
     
// input goes here
let N = 100;
 
// Calling function
result(N);
 
// This code is contributed by Bobby
 
</script>

Producción : 

0 15 30 45 60 75 90 

Método: Esto también se puede hacer verificando si el número es divisible por 15, ya que el MCM de 3 y 5 es 15 y cualquier número divisible por 15 es divisible por 3 y 5 y viceversa también. 

// C++ code to print numbers that
// are divisible by 3 and 5
#include <iostream>
using namespace std;
 
int main()
{
  int n = 50;
  for(int i = 0; i < 50; i++)
  {
 
    //lcm of 3 and 5 is 15
    if(i % 15 == 0){
      cout << i << " ";
    }
  }
  return 0;
}
 
// This code is contributed by laxmigangarajula03

# python code to print numbers that
# are divisible by 3 and 5
n=50
for i in range(0,n):
  # lcm of 3 and 5 is 15
  if i%15==0:
    print(i,end=" ")

0 15 30 45 

Complejidad de tiempo: O(n)

Espacio Auxiliar: O(1)