Dado un número, hallar la suma de sus dígitos.
Ejemplos:
C++
// C program to compute sum of digits in
// number.
#include <iostream>
using namespace std;
/* Function to get sum of digits */
class gfg {
public:
int getSum(int n)
{
int sum = 0;
while (n != 0) {
sum = sum + n % 10;
n = n / 10;
}
return sum;
}
};
// Driver code
int main()
{
gfg g;
int n = 687;
cout << g.getSum(n);
return 0;
}
// This code is contributed by Soumik
C
// C program to compute sum of digits in
// number.
#include <stdio.h>
/* Function to get sum of digits */
int getSum(int n)
{
int sum = 0;
while (n != 0) {
sum = sum + n % 10;
n = n / 10;
}
return sum;
}
// Driver code
int main()
{
int n = 687;
printf(" %d ", getSum(n));
return 0;
}
Java
// Java program to compute
// sum of digits in number.
import java.io.*;
class GFG {
/* Function to get sum of digits */
static int getSum(int n)
{
int sum = 0;
while (n != 0) {
sum = sum + n % 10;
n = n / 10;
}
return sum;
}
// Driver code
public static void main(String[] args)
{
int n = 687;
System.out.println(getSum(n));
}
}
// This code is contributed by Gitanjali
Python3
# Python 3 program to # compute sum of digits in # number. # Function to get sum of digits def getSum(n): sum = 0 while (n != 0): sum = sum + int(n % 10) n = int(n/10) return sum # Driver code n = 687 print(getSum(n))
C#
// C# program to compute
// sum of digits in number.
using System;
class GFG {
/* Function to get sum of digits */
static int getSum(int n)
{
int sum = 0;
while (n != 0) {
sum = sum + n % 10;
n = n / 10;
}
return sum;
}
// Driver code
public static void Main()
{
int n = 687;
Console.Write(getSum(n));
}
}
// This code is contributed by Sam007
PHP
<?php
// PHP Code to compute sum
// of digits in number.
// Function to get
// $sum of digits
function getsum($n)
{
$sum = 0;
while ($n != 0)
{
$sum = $sum + $n % 10;
$n = $n/10;
}
return $sum;
}
// Driver Code
$n = 687;
$res = getsum($n);
echo("$res");
// This code is contributed by
// Smitha Dinesh Semwal.
?>
Javascript
<script>
// Javascript program to compute sum of digits in
// number.
/* Function to get sum of digits */
function getSum(n)
{
var sum = 0;
while (n != 0) {
sum = sum + n % 10;
n = parseInt(n / 10);
}
return sum;
}
// Driver code
var n = 687;
document.write(getSum(n));
</script>
C++
#include <iostream>
using namespace std;
/* Function to get sum of digits */
class gfg {
public:
int getSum(int n)
{
int sum;
/* Single line that calculates sum */
for (sum = 0; n > 0; sum += n % 10, n /= 10)
;
return sum;
}
};
// Driver code
int main()
{
gfg g;
int n = 687;
cout << g.getSum(n);
return 0;
}
// This code is contributed by Soumik
C
#include <stdio.h>
/* Function to get sum of digits */
int getSum(int n)
{
int sum;
/* Single line that calculates sum */
for (sum = 0; n > 0; sum += n % 10, n /= 10)
;
return sum;
}
// Driver code
int main()
{
int n = 687;
printf(" %d ", getSum(n));
return 0;
}
Java
// Java program to compute
// sum of digits in number.
import java.io.*;
class GFG {
/* Function to get sum of digits */
static int getSum(int n)
{
int sum;
/* Single line that calculates sum */
for (sum = 0; n > 0; sum += n % 10, n /= 10)
;
return sum;
}
// Driver code
public static void main(String[] args)
{
int n = 687;
System.out.println(getSum(n));
}
}
// This code is contributed by Gitanjali
Python3
# Function to get sum of digits def getSum(n): sum = 0 # Single line that calculates sum while(n > 0): sum += int(n % 10) n = int(n/10) return sum # Driver code n = 687 print(getSum(n)) # This code is contributed by # Smitha Dinesh Semwal
C#
// C# program to compute
// sum of digits in number.
using System;
class GFG {
static int getSum(int n)
{
int sum;
/* Single line that calculates sum */
for (sum = 0; n > 0; sum += n % 10, n /= 10)
;
return sum;
}
// Driver code
public static void Main()
{
int n = 687;
Console.Write(getSum(n));
}
}
// This code is contributed by Sam007
PHP
<?php
// PHP Code for Sum the
// digits of a given number
// Function to get sum of digits
function getsum($n)
{
// Single line that calculates $sum
for ($sum = 0; $n > 0; $sum += $n % 10,
$n /= 10);
return $sum;
}
// Driver Code
$n = 687;
echo(getsum($n));
// This code is contributed by
// Smitha Dinesh Semwal.
?>
Javascript
<script>
// Javascript program to compute
// sum of digits in number.
// Function to get sum of digits
function getSum(n)
{
let sum;
// Single line that calculates sum
for(sum = 0; n > 0;
sum += n % 10,
n = parseInt(n / 10))
;
return sum;
}
// Driver code
let n = 687;
document.write(getSum(n));
// This code is contributed by subhammahato348
</script>
C++
// C++ program to compute
// sum of digits in number.
#include <iostream>
using namespace std;
class gfg {
public:
int sumDigits(int no)
{
if(no == 0){
return 0 ;
}
return (no % 10) + sumDigits(no / 10) ;
}
};
// Driver code
int main(void)
{
gfg g;
cout << g.sumDigits(687);
return 0;
}
C
// C program to compute
// sum of digits in number.
#include <stdio.h>
int sumDigits(int no)
{
if(no == 0){
return 0 ;
}
return (no % 10) + sumDigits(no / 10) ;
}
int main()
{
printf("%d", sumDigits(687));
return 0;
}
Java
// Java program to compute
// sum of digits in number.
import java.io.*;
class GFG {
/* Function to get sum of digits */
static int sumDigits(int no)
{
if(no == 0){
return 0 ;
}
return (no % 10) + sumDigits(no / 10) ;
}
// Driver code
public static void main(String[] args)
{
System.out.println(sumDigits(687));
}
}
// This code is contributed by Gitanjali
Python3
# Python program to compute # sum of digits in number. def sumDigits(no): return 0 if no == 0 else int(no % 10) + sumDigits(int(no/10)) # Driver code print(sumDigits(687)) # This code is contributed by # Smitha Dinesh Semwal
C#
// C# program to compute
// sum of digits in number.
using System;
class GFG {
/* Function to get sum of digits */
static int sumDigits(int no)
{
return no == 0 ? 0 : no % 10 + sumDigits(no / 10);
}
// Driver code
public static void Main()
{
Console.Write(sumDigits(687));
}
}
// This code is contributed by Sam007
PHP
<?php
// PHP program to compute
// sum of digits in number.
function sumDigits($no)
{
return $no == 0 ? 0 : $no % 10 +
sumDigits($no / 10) ;
}
// Driver Code
echo sumDigits(687);
// This code is contributed by aj_36
?>
Javascript
<script>
// Program to compute
// sum of digits in number
// Function to get sum of digits
function sumDigits(no)
{
if(no == 0){
return 0 ;
}
return (no % 10) + sumDigits(parseInt(no/10)) ;
}
// Driver code
document.write(sumDigits(687));
// This is code is contributed by simranarora5sos
</script>
C++14
// C++ implementation of the above approach
#include <iostream>
using namespace std;
int getSum(string str)
{
int sum = 0;
// Traversing through the string
for (int i = 0; i < str.length(); i++) {
// Since ascii value of
// numbers starts from 48
// so we subtract it from sum
sum = sum + str[i] - 48;
}
return sum;
}
// Driver Code
int main()
{
string st = "123456789123456789123422";
cout << getSum(st);
return 0;
}
Java
// Java implementation of the above approach
import java.io.*;
class GFG {
static int getSum(String str)
{
int sum = 0;
// Traversing through the string
for (int i = 0; i < str.length(); i++) {
// Since ascii value of
// numbers starts from 48
// so we subtract it from sum
sum = sum + str.charAt(i) - 48;
}
return sum;
}
// Driver Code
public static void main(String[] args)
{
String st = "123456789123456789123422";
System.out.print(getSum(st));
}
}
// This code is contributed by Dharanendra L V.
Python3
# Python implementation of the above approach def getSum(n): # Initializing sum to 0 sum = 0 # Traversing through string for i in n: # Converting char to int sum = sum + int(i) return sum n = "123456789123456789123422" print(getSum(n))
C#
// C# implementation of the above approach
using System;
public class GFG {
static int getSum(String str)
{
int sum = 0;
// Traversing through the string
for (int i = 0; i < str.Length; i++) {
// Since ascii value of
// numbers starts from 48
// so we subtract it from sum
sum = sum + str[i] - 48;
}
return sum;
}
// Driver Code
static public void Main()
{
String st = "123456789123456789123422";
Console.Write(getSum(st));
}
}
// This code is contributed by Dharanendra L V.
Javascript
<script>
// Javascript implementation of the above approach
function getSum(str)
{
let sum = 0;
// Traversing through the string
for (let i = 0; i < str.length; i++)
{
// Since ascii value of
// numbers starts from 48
// so we subtract it from sum
sum = sum + parseInt(str[i]);
}
return sum;
}
// Driver Code
let st = "123456789123456789123422";
document.write(getSum(st));
// This code is contributed by subhammahato348.
</script>
C++
// C++ program for the above approach
#include <iostream>
using namespace std;
// Function to check sum
// of digit using tail recursion
int sum_of_digit(int n, int val)
{
if (n < 10)
{
val = val + n;
return val;
}
return sum_of_digit(n / 10, (n % 10) + val);
}
// Driver code
int main()
{
int num = 12345;
int result = sum_of_digit(num, 0);
cout << "Sum of digits is " << result;
return 0;
}
// This code is contributed by subhammahato348
Java
// Java program for the above approach
import java.io.*;
import java.lang.*;
import java.util.*;
class sum_of_digits {
// Function to check sum
// of digit using tail recursion
static int sum_of_digit(int n, int val)
{
if (n < 10) {
val = val + n;
return val;
}
return sum_of_digit(n / 10, (n % 10) + val);
}
// Driven Program to check above
public static void main(String args[])
{
int num = 12345;
int result = sum_of_digit(num, 0);
System.out.println("Sum of digits is " + result);
}
}
Python3
# Python3 program for the above approach
# Function to check sum
# of digit using tail recursion
def sum_of_digit(n, val):
if (n < 10):
val = val + n
return val
return sum_of_digit(n // 10, (n % 10) + val)
# Driver code
num = 12345
result = sum_of_digit(num, 0)
print("Sum of digits is", result)
# This code is contributed by subhammahato348
C#
// C# program for the above approach
using System;
class GFG{
// Function to check sum
// of digit using tail recursion
static int sum_of_digit(int n, int val)
{
if (n < 10)
{
val = val + n;
return val;
}
return sum_of_digit(n / 10, (n % 10) + val);
}
// Driver code
public static void Main()
{
int num = 12345;
int result = sum_of_digit(num, 0);
Console.Write("Sum of digits is " + result);
}
}
// This code is contributed by subhammahato348
Javascript
<script>
// Javascript program for the above approach
// Function to check sum
// of digit using tail recursion
function sum_of_digit(n, val)
{
if (n < 10)
{
val = val + n;
return val;
}
return sum_of_digit(parseInt(n / 10),
(n % 10) + val);
}
// Driver code
let num = 12345;
let result = sum_of_digit(num, 0);
document.write("Sum of digits is " + result);
// This code is contributed by subhammahato348
</script>
Publicación traducida automáticamente
Artículo escrito por GeeksforGeeks-1 y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA