Dada una lista de diccionarios, la tarea es convertirla en un solo diccionario, es decir, aplanar una lista de diccionarios.
A continuación se presentan algunos métodos para resolver la tarea dada.
Método n.º 1: uso del método ingenuo
Python3
# Python code to demonstrate
# to flatten list of dictionaries
# Initialising dictionary
ini_dict = [{'a':1}, {'b':2}, {'c':3}]
# printing initial dictionary
print ("initial dictionary", str(ini_dict))
# code to flatten list of dictionary
res = {}
for d in ini_dict:
res.update(d)
# printing result
print ("result", str(res))
Producción:
initial dictionary [{'a': 1}, {'b': 2}, {'c': 3}]
result {'b': 2, 'a': 1, 'c': 3}
Método #2: Usar la comprensión de dictado
Python3
# Python code to demonstrate
# to flatten list of dictionaries
# Initialising dictionary
ini_dict = [{'a':1}, {'b':2}, {'c':3}]
# printing initial dictionary
print ("initial dictionary", str(ini_dict))
# code to flatten list of dictionary
res = {k: v for d in ini_dict for k, v in d.items()}
# printing result
print ("result", str(res))
Producción:
initial dictionary [{'a': 1}, {'b': 2}, {'c': 3}]
result {'a': 1, 'c': 3, 'b': 2}
Método #3: Usar reducir
Python3
# Python code to demonstrate
# to flatten list of dictionaries
from functools import reduce
# Initialising dictionary
ini_dict = [{'a':1}, {'b':2}, {'c':3}]
# printing initial dictionary
print ("initial dictionary", str(ini_dict))
# code to flatten list of dictionary
res = reduce(lambda d, src: d.update(src) or d, ini_dict, {})
# printing result
print ("result", str(res))
Producción:
initial dictionary [{'a': 1}, {'b': 2}, {'c': 3}]
result {'a': 1, 'c': 3, 'b': 2}
Método #4: Usarcollections.ChainMap
Python3
# Python code to demonstrate
# to flatten list of
# dictionaries
from collections import ChainMap
# Initialising dictionary
ini_dict = [{'a':1}, {'b':2}, {'c':3}]
# printing initial dictionary
print ("initial dictionary", str(ini_dict))
# code to flatten list of dictionary
res = ChainMap(*ini_dict)
# printing result
print ("result", str(res))
Producción:
initial dictionary [{'a': 1}, {'b': 2}, {'c': 3}]
result ChainMap({'a': 1}, {'b': 2}, {'c': 3})
Publicación traducida automáticamente
Artículo escrito por garg_ak0109 y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA