Python | Encuentra el elemento que no coincide en el mismo índice en dos listas

Dadas dos listas de enteros, la tarea es encontrar el índice en el que el elemento de dos listas no coincide. 
 

Input:
Input1 = [1, 2, 3, 4]
Input2 = [1, 5, 3, 6]

Output: [1, 3]
Explanation:
At index=1 we have 2 and 5 and at index=3
we have 4 and 6 which mismatches.

  
A continuación se presentan algunas formas de lograr esta tarea.
Método #1: Usar la iteración 
 

# Python code to find the index at which the
# element of two list doesn't match.
 
# List initialisation
Input1 = [1, 2, 3, 4]
Input2 = [1, 5, 3, 6]
 
# Index initialisation
y = 0
 
# Output list initialisation
Output = []
 
# Using iteration to find
for x in Input1:
    if x != Input2[y]:
        Output.append(y)
    y = y + 1
 
# Printing output
print(Output)

[1, 3]

Método #2: Usar lista de comprensión y zip 
 

# Python code to find the index at which the
# element of two list doesn't match.
 
# List initialisation
Input1 = [1, 2, 3, 4]
Input2 = [1, 5, 3, 6]
 
# Using list comprehension and zip
Output = [Input2.index(y) for x, y in
       zip(Input1, Input2) if y != x]
 
# Printing output
print(Output)

[1, 3]

Método #3: Usando Enumerar 
 

# Python code to find the index at which the
# element of two list doesn't match.
 
# List initialisation
Input1 = [1, 2, 3, 4]
Input2 = [1, 5, 3, 6]
 
# Using list comprehension and enumerate
Output = [index for index, elem in enumerate(Input2)
                           if elem != Input1[index]]
 
# Printing output
print(Output)

[1, 3]