Declaración del problema:
haga una lista de compras para compras en el supermercado con nombre, precio y cantidad; si la lista ya contiene un artículo, solo actualice el precio y la cantidad, no debe agregar el nombre del artículo nuevamente. Pregúntele al usuario su presupuesto inicialmente
y menos el presupuesto después de agregar un nuevo elemento en la lista. Si los presupuestos son cero/0, entonces no se pueden comprar más artículos y si queda algo de dinero y el usuario agrega un artículo mayor que el presupuesto restante, informe «precio excesivo» o cualquier otro mensaje. Después de hacer la lista, cualquier dinero que quede en el presupuesto debe mostrar un artículo dentro del presupuesto de la lista hecha.
La VALIDACIÓN es imprescindible.
Ejemplos:
User GO with following question Enter Your budget : 500 1.Add an item 2.Exit Enter your choice : 1 Enter product : corn flour Enter quantity : 1.5 kg Enter Price : 100 Amount left : 400 1.Add an item 2.Exit Enter your choice : 1 Enter product : wheat Enter quantity : 2 kg Enter Price : 100 Amount left : 300 1.Add an item 2.Exit Enter your choice : 1 Enter product : corn flour Enter quantity : 2 kg Enter Price : 250 Amount left : 150 1.Add an item 2.Exit Enter your choice : 1 Enter product : rice Enter quantity : 5 kg Enter Price : 300 Can't Buy the product ###(because budget left is 150) 1.Add an item 2.Exit Enter your choice : 1 Enter product : xyz Enter quantity : 1 kg Enter Price : 50 Amount left : 100 1.Add an item 2.Exit Enter your choice : 2 Amount left can buy you wheat GROCERY LIST is: Product name Quantity Price corn flour 2 kg 250 wheat 2 kg 100 xyz 1 kg 50
Intente comprender la declaración del problema anterior y la explicación de salida y pruébelo usted mismo antes de ir a la solución.
Código: código de Python para consultar la lista de la compra
Python3
# This loop will go on until the budget is integer or float
while True:
try:
bg = float(input("Enter your budget : "))
# if budget is integer or float it will be stored
# temporarily in variable 's'
s = bg
except ValueError:
print("PRINT NUMBER AS A AMOUNT")
continue
else:
break
# dictionary to store product("name"), quantity("quant"),
# price("price") with empty list as their values
a ={"name":[], "quant":[], "price":[]}
# converting dictionary to list for further updation
b = list(a.values())
# variable na value of "name" from dictionary 'a'
na = b[0]
# variable qu value of "quant" from dictionary 'a'
qu = b[1]
# variable pr value of "price" from dictionary 'a'
pr = b[2]
# This loop terminates when user select 2.EXIT option when asked
# in try it will ask user for an option as an integer (1 or 2)
# if correct then proceed else continue asking options
while True:
try:
ch = int(input("1.ADD\n2.EXIT\nEnter your choice : "))
except ValueError:
print("\nERROR: Choose only digits from the given option")
continue
else:
# check the budget is greater than zero and option selected
# by user is 1 i.e. to add an item
if ch == 1 and s>0:
# input products name
pn = input("Enter product name : ")
# input quantity of product
q = input("Enter quantity : ")
# input price of the product
p = float(input("Enter price of the product : "))
if p>s:
# checks if price is less than budget
print("\nCAN, T BUT THE PRODUCT")
continue
else:
# checks if product name already in list
if pn in na:
# find the index of that product
ind = na.index(pn)
# remove quantity from "quant" index of the product
qu.remove(qu[ind])
# remove price from "price" index of the product
pr.remove(pr[ind])
# insert new value given by user earlier
qu.insert(ind, q)
# insert new value given by user earlier
pr.insert(ind, p)
# subtracting the price from the budget and assign
# it to 's' sum(pr) is because pr = [100, 200] if
# budget is 500 then s = bg-sum(pr) = 200
# after updating for same product at index 0 let
# pr = [200, 200] so s = 100
s = bg-sum(pr)
print("\namount left", s)
else:
# append value of in "name", "quantity", "price"
na.append(pn)
# as na = b[0] it will append all the value in the
# list eg: "name":["rice"]
qu.append(q)
# same for quantity and price
pr.append(p)
# after appending new value the sum in price
# as to be calculated
s = bg-sum(pr)
print("\namount left", s)
# if budget goes zero print "NO BUDGET"
elif s<= 0:
print("\nNO BUDGET")
else:
break
# will print amount left in variable 's'
print("\nAmount left : Rs.", s)
# if the amount left equals to any amount in price list
if s in pr:
# then printing the name of the product which can buy
print("\nAmount left can buy you a", na[pr.index(s)])
print("\n\n\nGROCERY LIST")
# print final grocery list
for i in range(len(na)):
print(na[i], qu[i], pr[i])
Publicación traducida automáticamente
Artículo escrito por dpkjha5337 y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA