Python | Programa para aceptar las strings que contienen todas las vocales

Dada una string, la tarea es verificar si todas las vocales están presentes o no. Consideramos que una vocal está presente si está en mayúsculas o minúsculas. es decir, ‘a’, ‘e’, ​​’i’, ‘o’, ‘u’ o ‘A’, ‘E’, ‘I’, ‘O’, ‘U’. 
Ejemplos: 

Input : geeksforgeeks
Output : Not Accepted
All vowels except 'a','i','u' are not present

Input : ABeeIghiObhkUul
Output : Accepted
All vowels are present

Enfoque: en primer lugar, cree un conjunto de vocales usando la función set(). Verifique que cada carácter de la string sea vocal o no, si es vocal, agréguelo al conjunto s. Después de salir del ciclo, verifique la longitud del conjunto s, si la longitud del conjunto s es igual a la longitud del conjunto de vocales, entonces se acepta la string; de lo contrario, no. 
A continuación se muestra la implementación: 

# Python program to accept the strings
# which contains all the vowels
  
# Function for check if string
# is accepted or not
def check(string) :
  
    string = string.lower()
  
    # set() function convert "aeiou"
    # string into set of characters
    # i.e.vowels = {'a', 'e', 'i', 'o', 'u'}
    vowels = set("aeiou")
  
    # set() function convert empty 
    # dictionary into empty set
    s = set({})
  
    # looping through each
    # character of the string
    for char in string :
  
        # Check for the character is present inside
        # the vowels set or not. If present, then
        # add into the set s by using add method
        if char in vowels :
            s.add(char)
        else:
            pass
              
    # check the length of set s equal to length 
    # of vowels set or not. If equal, string is  
    # accepted otherwise not
    if len(s) == len(vowels) :
        print("Accepted")
    else :
        print("Not Accepted")
  
  
# Driver code
if __name__ == "__main__" :
      
    string = "SEEquoiaL"
  
    # calling function
    check(string)

Accepted

Implementación alternativa:

def check(string):
    string = string.replace(' ', '')
    string = string.lower()
    vowel = [string.count('a'), string.count('e'), string.count(
        'i'), string.count('o'), string.count('u')]
  
    # If 0 is present int vowel count array
    if vowel.count(0) > 0:
        return('not accepted')
    else:
        return('accepted')
  
  
# Driver code
if __name__ == "__main__":
  
    string = "SEEquoiaL"
  
    print(check(string))

accepted

Implementación alternativa 2.0: 

# Python program for the above approach
def check(string):
    if len(set(string.lower()).intersection("aeiou")) >= 5:
        return ('accepted')
    else:
        return ("not accepted")
  
  
# Driver code
if __name__ == "__main__":
    string = "geeksforgeeks"
    print(check(string))

not accepted

Implementación alternativa 3.0 (usando expresiones regulares):

Compile una expresión regular usando compile() para «el carácter no es a, e, i, o y u».
Use re.findall() para obtener las strings que satisfacen la expresión regular anterior.
Imprimir salida basada en el resultado.

#import library
import re
  
sampleInput = "aeioAEiuioea"
  
# regular expression to find the strings
# which have characters other than a,e,i,o and u
c = re.compile('[^aeiouAEIOU]')
  
# use findall() to get the list of strings
# that have characters other than a,e,i,o and u.
if(len(c.findall(sampleInput))):
    print("Not Accepted")  # if length of list > 0 then it is not accepted
else:
    print("Accepted")  # if length of list = 0 then it is accepted

Accepted

Implementación alternativa 4.0 (usando estructuras de datos):

# Python | Program to accept the strings which contains all vowels
  
  
def all_vowels(str_value):
  
    new_list = [char for char in str_value.lower() if char in 'aeiou']
  
    if new_list:
  
        dic, lst = {}, []
  
        for char in new_list:
            dic['a'] = new_list.count('a')
            dic['e'] = new_list.count('e')
            dic['i'] = new_list.count('i')
            dic['o'] = new_list.count('o')
            dic['u'] = new_list.count('u')
  
        for i, j in dic.items():
            if j == 0:
                lst.append(i)
  
        if lst:
            return f"All vowels except {','.join(lst)} are not present"
        else:
            return 'All vowels are present'
  
    else:
        return "No vowels present"
  
  
# function-call
str_value = "geeksforgeeks"
print(all_vowels(str_value))
  
str_value = "ABeeIghiObhkUul"
print(all_vowels(str_value))
  
# contribute by saikot

All vowels except a,i,u are not present
All vowels are present