Python – Conteo de palabras con letra específica

Dada una string de palabras, extraiga el recuento de palabras con letras específicas.

Entrada : test_str = ‘geeksforgeeks es lo mejor para los geeks’, letra = “g” Salida : 2 Explicación : “g” aparece en 2 palabras. Entrada : test_str = ‘geeksforgeeks es lo mejor para los geeks’, letra = “s” Salida : s Explicación : “s” ocurre en 4 palabras.

Método n.º 1: usar la comprensión de listas + len() + split()

Esta es una de las formas en que se puede realizar esta tarea. En esto, realizamos la tarea de extraer palabras de una string usando split() y loop se usa para iterar palabras para verificar la existencia de letras y len() se usa para obtener el número de palabras con letra.

# Python3 code to demonstrate working of
# Count of Words with specific letter
# Using list comprehension + len() + split()
 
# initializing string
test_str = 'geeksforgeeks is best for geeks'
 
# printing original string
print("The original string is : " + str(test_str))
 
# initializing letter
letter = "e"
 
# extracting desired count using len()
# list comprehension is used as shorthand
res = len([ele for ele in test_str.split() if letter in ele])
 
# printing result
print("Words count : " + str(res))

The original string is : geeksforgeeks is best for geeks
Words count : 3

Método #2: Usando filter() + lambda + len() + split()

Esta es otra forma más en la que se puede realizar esta tarea. En este, realizamos la tarea de filtrar usando filter() + lambda.

# Python3 code to demonstrate working of
# Count of Words with specific letter
# Using filter() + lambda + len() + split()
 
# initializing string
test_str = 'geeksforgeeks is best for geeks'
 
# printing original string
print("The original string is : " + str(test_str))
 
# initializing letter
letter = "e"
 
# extracting desired count using len()
# filter() used to check for letter existence
res = len(list(filter(lambda ele : letter in ele, test_str.split())))
 
# printing result
print("Words count : " + str(res))

The original string is : geeksforgeeks is best for geeks
Words count : 3

Método #3: Usar len() + for loop

Usamos len() y for loop para iterar sobre la string para resolver el problema.

# Python3 code to get count of Words with specific letter
 
# initializing string
test_str = 'geeksforgeeks is best for geeks'
 
# printing original string
print("The original string is : " + str(test_str))
 
# initializing letter
letter = "e"
""" As we have to only count one letter per word we have to
    check if we have checked that word or not and to do so
    we use variable word_count that become odd if we founded the letter
    in the word and even when not"""
word_count = 0
 
# count of words with specific letter
word = 0
 
# For loop to iterate over string
for i in range(len(test_str)):
    if word_count % 2 == 0 and test_str[i] == letter:
        word += 1
        word_count = 1
        # set word_count an odd number so we know to not check the current word.
    elif test_str[i] == " ":
        """    New word starts with " "  """
        word_count = 0
        # set word_count an even number so we know to check the current word.
print("Words count :", word)
# This code is contributed by Shivesh Kumar Dwivedi

The original string is : geeksforgeeks is best for geeks
Words count : 3

Método #4: Usando split() y find()

# Python3 code to demonstrate working of
# Count of Words with specific letter
# Using split() and find()
 
# initializing string
test_str = 'geeksforgeeks is best for geeks'
 
# printing original string
print("The original string is : " + str(test_str))
 
# initializing letter
letter = "e"
 
# extracting words with specific letter
res=0
x=test_str.split()
for i in x:
    if(i.find(letter)!=-1):
        res+=1
 
# printing result
print("Words count : " + str(res))

The original string is : geeksforgeeks is best for geeks
Words count : 3