Python: suma de tuplas anidadas sesgadas

Dada una tupla anidada en la 2.ª posición, devuelve la suma de los 1.er elementos.

Entrada : test_tup = (5, (6, (1, (9, Ninguno))))
Salida : 21
Explicación : 9 + 6 + 5 + 1 = 21.

Entrada : test_tup = (5, (6, (1, Ninguno)))
Salida : 12
Explicación : 1 + 6 + 5 = 12.

Método #1: Usar bucle infinito

En esto, realizamos entrar en la estructura sesgada mientras sumamos usando un ciclo infinito y rompemos cuando alcanzamos el valor Ninguno.

# Python3 code to demonstrate working of 
# Skew Nested Tuple Summation
# Using infinite loop
  
# initializing tuple
test_tup = (5, (6, (1, (9, (10, None)))))
  
# printing original tuple
print("The original tuple is : " + str(test_tup))
  
res = 0
while test_tup:
    res += test_tup[0]
      
    # assigning inner tuple as original
    test_tup = test_tup[1]
  
# printing result 
print("Summation of 1st positions : " + str(res)) 

The original tuple is : (5, (6, (1, (9, (10, None)))))
Summation of 1st positions : 31

Método #2: Usar recursividad

En esto, realizamos la suma y recurrimos para el segundo elemento de la tupla, regresamos a Ninguno.

# Python3 code to demonstrate working of 
# Skew Nested Tuple Summation
# Using recursion
  
# helper function to perform task
def tup_sum(test_tup):
      
    # return on None 
    if not test_tup:
        return 0
    else:
        return test_tup[0] + tup_sum(test_tup[1])
  
# initializing tuple
test_tup = (5, (6, (1, (9, (10, None)))))
  
# printing original tuple
print("The original tuple is : " + str(test_tup))
  
# calling fnc.
res = tup_sum(test_tup)
  
# printing result 
print("Summation of 1st positions : " + str(res)) 

The original tuple is : (5, (6, (1, (9, (10, None)))))
Summation of 1st positions : 31