Ha dado una lista de diccionarios, la tarea es devolver un solo diccionario con valores de suma con la misma clave.
Vamos a discutir diferentes métodos para hacer la tarea.
Método #1: Usarreduce() + operator
# Python code to demonstrate
# return the sum of values of dictionary
# with same keys in list of dictionary
import collections, functools, operator
# Initialising list of dictionary
ini_dict = [{'a':5, 'b':10, 'c':90},
{'a':45, 'b':78},
{'a':90, 'c':10}]
# printing initial dictionary
print ("initial dictionary", str(ini_dict))
# sum the values with same keys
result = dict(functools.reduce(operator.add,
map(collections.Counter, ini_dict)))
print("resultant dictionary : ", str(result))
diccionario inicial [{‘b’: 10, ‘a’: 5, ‘c’: 90}, {‘b’: 78, ‘a’: 45}, {‘a’: 90, ‘c’: 10} ]
diccionario resultante: {‘b’: 88, ‘a’: 140, ‘c’: 100}
Método #2: Usar el contador
# Python code to demonstrate
# return the sum of values of dictionary
# with same keys in list of dictionary
import collections
# Initialising list of dictionary
ini_dict = [{'a':5, 'b':10, 'c':90},
{'a':45, 'b':78},
{'a':90, 'c':10}]
# printing initial dictionary
print ("initial dictionary", str(ini_dict))
# sum the values with same keys
counter = collections.Counter()
for d in ini_dict:
counter.update(d)
result = dict(counter)
print("resultant dictionary : ", str(counter))
diccionario inicial [{‘c’: 90, ‘a’: 5, ‘b’: 10}, {‘a’: 45, ‘b’: 78}, {‘a’: 90, ‘c’: 10} ]
diccionario resultante: contador ({‘a’: 140, ‘c’: 100, ‘b’: 88})
Método #3: Método Ingenuo
# Python code to demonstrate
# return the sum of values of dictionary
# with same keys in list of dictionary
from operator import itemgetter
# Initialising list of dictionary
ini_dict = [{'a':5, 'b':10, 'c':90},
{'a':45, 'b':78},
{'a':90, 'c':10}]
# printing initial dictionary
print ("initial dictionary", str(ini_dict))
# sum the values with same keys
result = {}
for d in ini_dict:
for k in d.keys():
result[k] = result.get(k, 0) + d[k]
print("resultant dictionary : ", str(result))
diccionario inicial [{‘b’: 10, ‘c’: 90, ‘a’: 5}, {‘b’: 78, ‘a’: 45}, {‘c’: 10, ‘a’: 90} ]
diccionario resultante: {‘b’: 88, ‘c’: 100, ‘a’: 140}
Publicación traducida automáticamente
Artículo escrito por garg_ak0109 y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA