Suma de los valores alfabéticos de los caracteres de una string

Se le da una array de strings str , la tarea es encontrar la puntuación de una string dada de la array. La puntuación de una string se define como el producto de la suma de los valores alfabéticos de sus caracteres con la posición de la string en la array.
Ejemplos: 
 

Entrada: str[] = {“sahil”, “shashanak”, “sanjit”, “abhinav”, “mohit”}, s = “abhinav” 
Salida: 228 
Suma de valores alfabéticos de “abhinav” = 1 + 2 + 8 + 9 + 14 + 1 + 22 = 57 
La posición de “abhinav” en str es 4, 57 x 4 = 228 
Entrada: str[] = {“geeksforgeeks”, “algorithms”, “stack”}, s = “algorithms” 
Salida: 244 
 

Acercarse: 
 

• Encuentre la string dada en la array y almacene la posición de la string.
• Luego calcule la suma de los valores alfabéticos de la string dada.
• Multiplique la posición de la string en la array dada por el valor calculado en el paso anterior e imprima el resultado.

A continuación se muestra la implementación del enfoque anterior: 
 

// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
 
// Function to find string score
int strScore(string str[], string s, int n)
{
    int score = 0, index;
    for (int i = 0; i < n; i++) {
        if (str[i] == s) {
            for (int j = 0; j < s.length(); j++)
                score += s[j] - 'a' + 1;
            index = i + 1;
            break;
        }
    }
 
    score = score * index;
    return score;
}
 
// Driver code
int main()
{
    string str[] = { "sahil", "shashanak"
                      , "sanjit", "abhinav", "mohit" };
    string s = "abhinav";
    int n = sizeof(str) / sizeof(str[0]);
    int score = strScore(str, s, n);
    cout << score << endl;
 
    return 0;
}

//  Java implementation of the approach
import java.io.*;
 
class GFG {
 
 
// Function to find string score
static int strScore(String str[], String s, int n)
{
    int score = 0, index=0;
    for (int i = 0; i < n; i++) {
        if (str[i] == s) {
            for (int j = 0; j < s.length(); j++)
                score += s.charAt(j) - 'a' + 1;
            index = i + 1;
            break;
        }
    }
 
    score = score * index;
    return score;
}
 
// Driver code
 
 
    public static void main (String[] args) {
            String str[] = { "sahil", "shashanak"
                    , "sanjit", "abhinav", "mohit" };
    String s = "abhinav";
    int n = str.length;
    int score = strScore(str, s, n);
    System.out.println( score);
    }
}
// This code is contributed by anuj_67..

# Python3 implementation of the approach
# Function to find string score
def strScore(str, s, n):
    score = 0
    index = 0
    for i in range(n):
        if (str[i] == s):
            for j in range(len(s)):
                score += (ord(s[j]) -
                          ord('a') + 1)
            index = i + 1
            break
    score = score * index
    return score
 
# Driver code
str = ["sahil", "shashanak", "sanjit",
                  "abhinav", "mohit" ]
s = "abhinav"
n = len(str)
score = strScore(str, s, n);
print(score)
 
# This code is contributed
# by sahishelangia

// C# implementation of the approach
using System;
 
class GFG
{
 
// Function to find string score
static int strScore(String []str,
                    String s, int n)
{
    int score = 0, index = 0;
    for (int i = 0; i < n; i++)
    {
        if (str[i] == s)
        {
            for (int j = 0; j < s.Length; j++)
                score += s[j] - 'a' + 1;
            index = i + 1;
            break;
        }
    }
 
    score = score * index;
    return score;
}
 
// Driver code
public static void Main (String[] args)
{
    String []str = { "sahil", "shashanak", "sanjit",
                     "abhinav", "mohit" };
    String s = "abhinav";
    int n = str.Length;
    int score = strScore(str, s, n);
    Console.Write( score);
}
}
 
// This code is contributed by 29AjayKumar

<?php
 
// Function to find string score
function strScore($str, $s, $n)
{
    $score = 0;
    $index;
    for ($i = 0; $i < $n; $i++)
    {
        if ($str[$i] == $s)
        {
            for ($j = 0; $j < strlen($s); $j++)
                $score += (ord($s[$j]) - ord('a')) + 1;
            $index = ($i + 1);
            break;
        }
    }
 
    $score = $score * $index;
    return $score;
}
 
// Driver code
$str = array( "sahil", "shashanak",
              "sanjit", "abhinav", "mohit" );
$s = "abhinav";
$n = sizeof($str);
$score = strScore($str, $s, $n);
echo $score, "\n";
 
// This code is contributed by jit_t
?>

<script>
 
 //  javascript implementation of the approach
 
// Function to find string score
function strScore(str, s , n)
{
    var score = 0, index=0;
    for (i = 0; i < n; i++) {
        if (str[i] == s) {
            for (j = 0; j < s.length; j++){
                 
                score += s.charAt(j).charCodeAt(0) - ('a').charCodeAt(0) + 1;
                }
            index = i + 1;
            break;
        }
    }
 
    score = score * index;
    return score;
}
 
// Driver code
str = [ "sahil", "shashanak"
                    , "sanjit", "abhinav", "mohit" ];
    s = "abhinav";
    var n = str.length;
    var score = strScore(str, s, n);
    document.write( score);
 
// This code contributed by shikhasingrajput
</script>

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