Dada una string S de longitud N , la tarea es encontrar el valor hash SHA-512 de la string S dada .
Ejemplos:
Entrada: S = «GeeksforGeeks»
Salida: acc10c4e0b38617f59e88e49215e2e894afaee5ec948c2af6f44039f03c9fe47a9210e01d5cd926c142bdc9179c2ad30f927a8faf69421ff60a5eaddcf8cb5eaddcf8cb5Entrada: S = «hola mundo»
Salida:
309ecc489c12d6eb4cc40f50c902f2b4d0ed77ee511a7c7a9bcd3ca86d4cd86f989dd35bc5ff499670da34255b45b0cfd830e81f605dcf7dc5542e93ae9cd76f
Enfoque: siga los pasos a continuación para resolver el problema:
- Convierte la string dada a la forma binaria .
- Agregue ‘1’ a la string y luego ‘0’ continuamente hasta que la longitud de la string sea < (N%(1024 – 128)) .
- Agregue la representación binaria de 128 bits de N en la string S .
- Encuentra el número de trozos del tamaño de 1024 y guárdalo en una variable, digamos trozos como N/1024 .
- Divida la string S en 16 partes de 64 caracteres.
- Amplíe el número de fragmentos a 80 realizando las siguientes operaciones:
- Itere sobre el rango [16, 80] y luego encuentre 4 valores, digamos WordA, WordB, WordC, WordD como:
- PalabraA = rotar_derecha(Mensaje[g – 2], 19) ^ rotar_derecha(Mensaje[g – 2], 61) ^ shift_derecha(Mensaje[g – 2], 6) .
- PalabraB = Mensaje[g – 7] .
- WordC = rotar_derecha(Mensaje[g – 15], 1) ^ rotar_derecha(Mensaje[g – 15], 8) ^ shift_derecha(Mensaje[g – 15], 7) .
- PalabraD = Mensaje[g – 16] .
- Actualice el valor de Message[g] como (WordA + WordB + WordC+ WordD) .
- Itere sobre el rango [16, 80] y luego encuentre 4 valores, digamos WordA, WordB, WordC, WordD como:
- Inicialice 8 variables, digamos A , B , C , D , E , F , G , H de tipo 64 bits para almacenar el valor hash final de la string dada S .
- Atraviese la array Block[] y realice los siguientes pasos:
- Actualice el valor de A , B , C , D , E , F , G , H usando la función Hash hasta 80 iteraciones girando una por una.
- Ahora, actualice el valor de A , B , C , D , E , F , G , H mediante la suma de los valores anteriores de A , B , C , D , E , F , G , H y el valor recién actualizado de A , B , C , D , E , F , G , H .
- Después de completar los pasos anteriores, imprima los valores hexadecimales de A , B , C , D , E , F , G , H para obtener el valor hash de la string dada.
A continuación se muestra la implementación del enfoque anterior:
C++14
// C++ program for the above approach #include <bits/stdc++.h> using namespace std; typedef unsigned long long int int64; int64 Message[80]; // Stores the hexadecimal values for // calculating hash values const int64 Constants[80] = { 0x428a2f98d728ae22, 0x7137449123ef65cd, 0xb5c0fbcfec4d3b2f, 0xe9b5dba58189dbbc, 0x3956c25bf348b538, 0x59f111f1b605d019, 0x923f82a4af194f9b, 0xab1c5ed5da6d8118, 0xd807aa98a3030242, 0x12835b0145706fbe, 0x243185be4ee4b28c, 0x550c7dc3d5ffb4e2, 0x72be5d74f27b896f, 0x80deb1fe3b1696b1, 0x9bdc06a725c71235, 0xc19bf174cf692694, 0xe49b69c19ef14ad2, 0xefbe4786384f25e3, 0x0fc19dc68b8cd5b5, 0x240ca1cc77ac9c65, 0x2de92c6f592b0275, 0x4a7484aa6ea6e483, 0x5cb0a9dcbd41fbd4, 0x76f988da831153b5, 0x983e5152ee66dfab, 0xa831c66d2db43210, 0xb00327c898fb213f, 0xbf597fc7beef0ee4, 0xc6e00bf33da88fc2, 0xd5a79147930aa725, 0x06ca6351e003826f, 0x142929670a0e6e70, 0x27b70a8546d22ffc, 0x2e1b21385c26c926, 0x4d2c6dfc5ac42aed, 0x53380d139d95b3df, 0x650a73548baf63de, 0x766a0abb3c77b2a8, 0x81c2c92e47edaee6, 0x92722c851482353b, 0xa2bfe8a14cf10364, 0xa81a664bbc423001, 0xc24b8b70d0f89791, 0xc76c51a30654be30, 0xd192e819d6ef5218, 0xd69906245565a910, 0xf40e35855771202a, 0x106aa07032bbd1b8, 0x19a4c116b8d2d0c8, 0x1e376c085141ab53, 0x2748774cdf8eeb99, 0x34b0bcb5e19b48a8, 0x391c0cb3c5c95a63, 0x4ed8aa4ae3418acb, 0x5b9cca4f7763e373, 0x682e6ff3d6b2b8a3, 0x748f82ee5defb2fc, 0x78a5636f43172f60, 0x84c87814a1f0ab72, 0x8cc702081a6439ec, 0x90befffa23631e28, 0xa4506cebde82bde9, 0xbef9a3f7b2c67915, 0xc67178f2e372532b, 0xca273eceea26619c, 0xd186b8c721c0c207, 0xeada7dd6cde0eb1e, 0xf57d4f7fee6ed178, 0x06f067aa72176fba, 0x0a637dc5a2c898a6, 0x113f9804bef90dae, 0x1b710b35131c471b, 0x28db77f523047d84, 0x32caab7b40c72493, 0x3c9ebe0a15c9bebc, 0x431d67c49c100d4c, 0x4cc5d4becb3e42b6, 0x597f299cfc657e2a, 0x5fcb6fab3ad6faec, 0x6c44198c4a475817 }; // Function to convert a binary string // to hexa-decimal value string gethex(string bin) { if (bin == "0000") return "0"; if (bin == "0001") return "1"; if (bin == "0010") return "2"; if (bin == "0011") return "3"; if (bin == "0100") return "4"; if (bin == "0101") return "5"; if (bin == "0110") return "6"; if (bin == "0111") return "7"; if (bin == "1000") return "8"; if (bin == "1001") return "9"; if (bin == "1010") return "a"; if (bin == "1011") return "b"; if (bin == "1100") return "c"; if (bin == "1101") return "d"; if (bin == "1110") return "e"; if (bin == "1111") return "f"; } // Function to convert a decimal value // to hexa decimal value string decimaltohex(int64 deci) { // Stores the value as string string EQBIN = bitset<64>(deci).to_string(); // Stores the equivalent hexa decimal string hexstring = ""; string temp; // Traverse the string EQBIN for (unsigned int i = 0; i < EQBIN.length(); i += 4) { temp = EQBIN.substr(i, 4); hexstring += gethex(temp); } // Return the hexstring return hexstring; } // Function to convert a binary // string to decimal value int64 BintoDec(string bin) { int64 value = bitset<64>(bin) .to_ullong(); return value; } // Function to right rotate x by n bits int64 rotate_right(int64 x, int n) { return (x >> n) | (x << (64 - n)); } // Function to right shift x by n bits int64 shift_right(int64 x, int n) { return (x >> n); } // Function to divide the string // into chunks void separator(string getBlock) { // Stores the size of chunks int chunknum = 0; // Traverse the string S for (unsigned int i = 0; i < getBlock.length(); i += 64, ++chunknum) { // Update the Message[chunknum] Message[chunknum] = BintoDec(getBlock.substr(i, 64)); } // Iterate over the range [16, 80] for (int g = 16; g < 80; ++g) { // Find the WordA int64 WordA = rotate_right(Message[g - 2], 19) ^ rotate_right(Message[g - 2], 61) ^ shift_right(Message[g - 2], 6); // Find the WordB int64 WordB = Message[g - 7]; // Find the WordC int64 WordC = rotate_right(Message[g - 15], 1) ^ rotate_right(Message[g - 15], 8) ^ shift_right(Message[g - 15], 7); // Find the WordD int64 WordD = Message[g - 16]; // Find the resultant code int64 T = WordA + WordB + WordC + WordD; // Return the resultant Hash Code Message[g] = T; } } // Function to find the major of a, b, c int64 maj(int64 a, int64 b, int64 c) { return (a & b) ^ (b & c) ^ (c & a); } // Function to find the ch value of a, // b, and c int64 Ch(int64 e, int64 f, int64 g) { return (e & f) ^ (~e & g); } // Function to find the Bitwise XOR with // the right rotate over 14, 18, and 41 int64 sigmaE(int64 e) { // Return the resultant value return rotate_right(e, 14) ^ rotate_right(e, 18) ^ rotate_right(e, 41); } // Function to find the Bitwise XOR with // the right rotate over 28, 34, and 39 int64 sigmaA(int64 a) { // Return the resultant value return rotate_right(a, 28) ^ rotate_right(a, 34) ^ rotate_right(a, 39); } // Function to generate the hash code void Func(int64 a, int64 b, int64 c, int64& d, int64 e, int64 f, int64 g, int64& h, int K) { // Find the Hash Code int64 T1 = h + Ch(e, f, g) + sigmaE(e) + Message[K] + Constants[K]; int64 T2 = sigmaA(a) + maj(a, b, c); d = d + T1; h = T1 + T2; } // Function to convert the hash value // of a given string string SHA512(string myString) { // Stores the 8 blocks of size 64 int64 A = 0x6a09e667f3bcc908; int64 B = 0xbb67ae8584caa73b; int64 C = 0x3c6ef372fe94f82b; int64 D = 0xa54ff53a5f1d36f1; int64 E = 0x510e527fade682d1; int64 F = 0x9b05688c2b3e6c1f; int64 G = 0x1f83d9abfb41bd6b; int64 H = 0x5be0cd19137e2179; int64 AA, BB, CC, DD, EE, FF, GG, HH; stringstream fixedstream; // Traverse the string S for (int i = 0; i < myString.size(); ++i) { // Add the character to stream fixedstream << bitset<8>(myString[i]); } // Stores string of size 1024 string s1024; // Stores the string in the // fixedstream s1024 = fixedstream.str(); // Stores the length of string int orilen = s1024.length(); int tobeadded; // Find modded string length int modded = s1024.length() % 1024; // If 1024-128 is greater than modded if (1024 - modded >= 128) { tobeadded = 1024 - modded; } // Else if 1024-128 is less than modded else if (1024 - modded < 128) { tobeadded = 2048 - modded; } // Append 1 to string s1024 += "1"; // Append tobeadded-129 zeros // in the string for (int y = 0; y < tobeadded - 129; y++) { s1024 += "0"; } // Stores the binary representation // of string length string lengthbits = std::bitset<128>(orilen).to_string(); // Append the lengthbits to string s1024 += lengthbits; // Find the count of chunks of // size 1024 each int blocksnumber = s1024.length() / 1024; // Stores the numbering of chunks int chunknum = 0; // Stores hash value of each blocks string Blocks[blocksnumber]; // Traverse the string s1024 for (int i = 0; i < s1024.length(); i += 1024, ++chunknum) { Blocks[chunknum] = s1024.substr(i, 1024); } // Traverse tha array Blocks[] for (int letsgo = 0; letsgo < blocksnumber; ++letsgo) { // Divide the current string // into 80 blocks size 16 each separator(Blocks[letsgo]); AA = A; BB = B; CC = C; DD = D; EE = E; FF = F; GG = G; HH = H; int count = 0; // Find hash values for (int i = 0; i < 10; i++) { // Find the Hash Values Func(A, B, C, D, E, F, G, H, count); count++; Func(H, A, B, C, D, E, F, G, count); count++; Func(G, H, A, B, C, D, E, F, count); count++; Func(F, G, H, A, B, C, D, E, count); count++; Func(E, F, G, H, A, B, C, D, count); count++; Func(D, E, F, G, H, A, B, C, count); count++; Func(C, D, E, F, G, H, A, B, count); count++; Func(B, C, D, E, F, G, H, A, count); count++; } // Update the value of A, B, C, // D, E, F, G, H A += AA; B += BB; C += CC; D += DD; E += EE; F += FF; G += GG; H += HH; } stringstream output; // Print the hexadecimal value of // strings as the resultant SHA-512 output << decimaltohex(A); output << decimaltohex(B); output << decimaltohex(C); output << decimaltohex(D); output << decimaltohex(E); output << decimaltohex(F); output << decimaltohex(G); output << decimaltohex(H); // Return the string return output.str(); } // Driver Code int main() { // Input string S = "GeeksForGeeks"; // Function Call cout << S << ": " << SHA512(S); return 0; }
GeeksForGeeks: 0acc10c4e0b38617f59e88e49215e2e894afaee5ec948c2af6f44039f03c9fe47a9210e01d5cd926c142bdc9179c2ad30f927a8faf69421ff60a5eaddcf8cb9c
Complejidad temporal: O(N)
Espacio auxiliar: O(1)
Publicación traducida automáticamente
Artículo escrito por therain0605 y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA