Hora en la que el minutero y el horario coinciden

Dado el tiempo en horas, encuentre el tiempo en minutos en el que el minutero y el horario coinciden en la siguiente hora.
Ejemplos: 
 

Input : 3 
Output : (180/11) minutes

Input :7
Output : (420/11) minutes

Enfoque: 
1. Tome dos variables para la hora «h1 y h2» y luego encuentre el ángulo «theta» [theta = (30 * h1)] y luego divídalo por «11» para encontrar el tiempo en minutos (m). Estamos dividiendo con 11, porque las manecillas de un reloj coinciden 11 segundos en 12 horas y 22 veces en 24 horas:
Fórmula: Esto se puede calcular usando la fórmula para el tiempo h1 a h2 significa [11m / 2 – 30 (h1)] 
esto implica [m = ((30 * h1) * 2) / 11 ] ] 
[ m = (theta * 2) / 11 ] 
donde [theta = (30 * h1) ]
donde A y B son horas, es decir, si la hora dada es (2, 3) entonces A = 2 y B = 3 .
 

// CPP code to find the minute at which
// the minute hand and hour hand coincide
#include <bits/stdc++.h>
using namespace std;
 
// function to find the minute
void find_time(int h1)
{
  // finding the angle between minute
  // hand and the first hour hand
  int theta = 30 * h1;
  cout << "(" << (theta * 2) << "/"
       << "11"
       << ")"
       << " minutes";
}
 
// Driver code
int main() {
  int h1 = 3; 
  find_time(h1); 
  return 0;
}

// Java code to find the minute 
// at which the minute hand and
// hour hand coincide
import java.io.*;
 
class GFG
{
     
    // function to find the minute
    static void find_time(int h1)
    {
     
    // finding the angle between
    // minute hand and the first
    // hour hand
    int theta = 30 * h1;
    System.out.println("(" + theta *
                           2 + "/" +
                   " 11 ) minutes");
    }
     
    //Driver Code
    public static void main (String[] args)
    {
        int h1 = 3;
        find_time(h1);    
    }
}
 
// This code is contributed by
// upendra singh bartwal

# Python3 code to find the
# minute at which the minute
# hand and hour hand coincide
 
# Function to find the minute
def find_time(h1):
 
    # Finding the angle between
    # minute hand and the first
    # hour hand
    theta = 30 * h1
    print("(", end = "")
    print((theta * 2),"/ 11) minutes")
 
# Driver code
h1 = 3
find_time(h1)
 
# This code is contributed by
# Smitha Dinesh Semwal

// C# code to find the minute
// at which the minute hand
// and hour hand coincide
using System;
 
class GFG
{
     
    // function to find the minute
    static void find_time(int h1)
    {
     
        // finding the angle between minute
        // hand and the first hour hand
        int theta = 30 * h1;
        Console.WriteLine("(" + theta * 2 +
                     "/" + " 11 )minutes");
    }
     
    //Driver Code
    public static void Main()
    {
        int h1 = 3;
         
        find_time(h1);
    }
}
 
// This code is contributed by vt_m.

<?php
// PHP code to find the minute
// at which the minute hand and
// hour hand coincide
 
// function to find the minute
function find_time($h1)
{
    // finding the angle between
    // minute hand and the first
    // hour hand
    $theta = 30 * $h1;
    echo("(" . ($theta * 2) .
           "/" . "11" . ")" .
                 " minutes");
}
 
// Driver code
$h1 = 3;
find_time($h1);
 
// This code is contributed by Ajit.
?>

<script>
 
// JavaScript code to find the minute at which
// the minute hand and hour hand coincide
 
// function to find the minute
function find_time(h1)
{
// finding the angle between minute
// hand and the first hour hand
theta = 30 * h1;
document.write("(" + (theta * 2) + "/"
    + "11"
    + ")"
    + " minutes");
}
 
// Driver code
h1 = 3;
find_time(h1);
 
// This code is contributed by Surbhi Tyagi.
 
</script>

(180/11) minutes