Dados dos números enteros A y B , la tarea es verificar si ambos números tienen el mismo número de dígitos.
Ejemplos:
Entrada: A = 12, B = 1
Salida: No
Entrada: A = 20, B = 99
Salida: Sí
Enfoque: Si bien ambos números son > 0, siga dividiendo ambos números por 10. Finalmente, verifique si ambos números son 0. Si alguno de ellos no es 0, entonces tenían un número desigual de dígitos.
A continuación se muestra la implementación del enfoque anterior:
C++
// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
// Function that return true if A and B
// have same number of digits
bool sameLength(int A, int B)
{
while (A > 0 && B > 0) {
A = A / 10;
B = B / 10;
}
// Both must be 0 now if
// they had same lengths
if (A == 0 && B == 0)
return true;
return false;
}
// Driver code
int main()
{
int A = 21, B = 1;
if (sameLength(A, B))
cout << "Yes";
else
cout << "No";
return 0;
}
Java
// Java implementation of the approach
import java.io.*;
class GFG
{
// Function that return true if A and B
// have same number of digits
static boolean sameLength(int A, int B)
{
while ((A > 0) && (B > 0))
{
A = A / 10;
B = B / 10;
}
// Both must be 0 now if
// they had same lengths
if ((A == 0 )&& (B == 0))
return true;
return false;
}
// Driver code
public static void main (String[] args)
{
int A = 21, B = 1;
if (sameLength(A, B))
System.out.println ("Yes");
else
System.out.println("No");
}
}
// This code is contributed by @tushil.
Python3
# Python implementation of the approach
# Function that return true if A and B
# have same number of digits
def sameLength(A, B):
while (A > 0 and B > 0):
A = A / 10;
B = B / 10;
# Both must be 0 now if
# they had same lengths
if (A == 0 and B == 0):
return True;
return False;
# Driver code
A = 21; B = 1;
if (sameLength(A, B)):
print("Yes");
else:
print("No");
# This code contributed by PrinciRaj1992
C#
// C# implementation of the approach
using System;
class GFG
{
// Function that return true if A and B
// have same number of digits
static bool sameLength(int A, int B)
{
while ((A > 0) && (B > 0))
{
A = A / 10;
B = B / 10;
}
// Both must be 0 now if
// they had same lengths
if ((A == 0 )&& (B == 0))
return true;
return false;
}
// Driver code
static public void Main ()
{
int A = 21, B = 1;
if (sameLength(A, B))
Console.WriteLine("Yes");
else
Console.WriteLine("No");
}
}
// This code is contributed by ajit..
Javascript
<script>
// Javascript implementation of the approach
// Function that return true if A and B
// have same number of digits
function sameLength(A, B)
{
while (A > 0 && B > 0) {
A = parseInt(A / 10);
B = parseInt(B / 10);
}
// Both must be 0 now if
// they had same lengths
if (A == 0 && B == 0)
return true;
return false;
}
// Driver code
let A = 21, B = 1;
if (sameLength(A, B))
document.write("Yes");
else
document.write("No");
</script>
Producción:
No
Complejidad del tiempo: O(log 10 (min(A, B)))
Espacio Auxiliar: O(1)