Haga que A, B y C sean iguales al agregarles el valor total N

Dados 3 números enteros A, B y C , y un número entero N , la tarea es distribuir N entre los otros 3 números de modo que al final A = B = C . Si la distribución es posible, imprima «Sí», de lo contrario, emita «No».
Ejemplos:
 

Entrada: A = 5, B = 3, C = 2, N = 8 
Salida: Sí 
Explicación: 
Podemos distribuir N = 8 sumando 1 a A, 3 a B y 4 a C para obtener todos ellos como 6. Por lo tanto la distribución es posible.
Entrada: A = 10, B = 20, C = 15, N = 14 
Salida: No 
Explicación: 
No es posible distribuir N entre los tres enteros para que sean iguales. 
 

Enfoque: 
Para resolver el problema mencionado anteriormente, debemos seguir los pasos que se detallan a continuación: 
 

• Encuentre el máximo de los tres enteros A, B y C. Sea el entero K
• Multiplique el entero K por 3 y luego réstelo por la suma de los tres enteros.
• Comprueba si la diferencia de ese número y N es divisible por 3 o no.
• Si es así, la salida es «Sí», de lo contrario, no es posible distribuir el número.

A continuación se muestra la implementación del enfoque anterior:
 

// C++ program to distribute integer N
// among A, B, C such that they become equal
#include<bits/stdc++.h>
using namespace std;
 
void distributeN(int A, int B, int C, int n)
{
    // Find maximum among the three elements
    int max1 = max(A, B);
    int max2 = max(B, C);
    int maximum = max(max1, max2);
     
    // Summation of three elements
    int sum = A + B + C;
    int p = (3 * maximum) - sum;
    int diff = n - p;
     
    // Check if difference is divisible by 3
    if (diff < 0 || diff % 3)
        cout << "No";
    else
        cout << "Yes";
}
         
// Driver code
int main()
{
    int A = 10, B = 20;
    int C = 15, n = 14;
     
    distributeN(A, B, C, n);
    return 0;
}
 
// This code is contributed by PratikBasu

// Java program to distribute integer N
// among A, B, C such that they become equal
class GFG{
 
static void distributeN(int A, int B, int C,
                        int n)
{
     
    // Find maximum among the three elements
    int max1 = Math.max(A, B);
    int max2 = Math.max(B, C);
    int maximum = Math.max(max1, max2);
     
    // Summation of three elements
    int sum = A + B + C;
    int p = (3 * maximum) - sum;
    int diff = n - p;
     
    // Check if difference is divisible by 3
    if (diff < 0 || diff % 3 == 0)
        System.out.print("No");
    else
        System.out.print("Yes");
}
         
// Driver code
public static void main(String[] args)
{
    int A = 10, B = 20;
    int C = 15, n = 14;
     
    distributeN(A, B, C, n);
}
}
 
// This code is contributed by Rajput-Ji

# Python3 Program to Distribute integer N
# among A, B, C such that they become equal
 
def distributeN(A, B, C, n):
     
    # find maximum among the three elements
    maximum = max(A, B, C)
     
    # summation of three elements
    sum = A + B+C
     
     
    p = (3 * maximum)-sum
     
    diff = n-p
     
    # check if difference is divisible by 3
    if diff < 0 or diff % 3:
        print "No"
    else:
        print "Yes"
         
         
# Driver code
A = 10
B = 20
C = 15
n = 14
distributeN(A, B, C, n)

// C# program to distribute integer N
// among A, B, C such that they become equal
using System;
 
class GFG{
 
static void distributeN(int A, int B, int C,
                        int n)
{
     
    // Find maximum among the three elements
    int max1 = Math.Max(A, B);
    int max2 = Math.Max(B, C);
    int maximum = Math.Max(max1, max2);
     
    // Summation of three elements
    int sum = A + B + C;
    int p = (3 * maximum) - sum;
    int diff = n - p;
     
    // Check if difference is divisible by 3
    if (diff < 0 || diff % 3 == 0)
        Console.Write("No");
    else
        Console.Write("Yes");
}
         
// Driver code
public static void Main(String[] args)
{
    int A = 10, B = 20;
    int C = 15, n = 14;
     
    distributeN(A, B, C, n);
}
}
 
// This code is contributed by Rajput-Ji

<script>
 
// JavaScript program to distribute integer N
// among A, B, C such that they become equal
 
function distributeN(A, B, C, n)
{
    // Find maximum among the three elements
    let max1 = Math.max(A, B);
    let max2 = Math.max(B, C);
    let maximum = Math.max(max1, max2);
     
    // Summation of three elements
    let sum = A + B + C;
    let p = (3 * maximum) - sum;
    let diff = n - p;
     
    // Check if difference is divisible by 3
    if (diff < 0 || diff % 3)
        document.write("No");
    else
        document.write("Yes");
}
         
// Driver code
    let A = 10, B = 20;
    let C = 15, n = 14;
     
    distributeN(A, B, C, n);
 
 
// This code is contributed by Surbhi Tyagi.
 
</script>

No

Complejidad de tiempo: O(1)