Dado un número N. La tarea es verificar si la suma de los dígitos del número dado divide el número o no. Si lo divide, imprima SÍ; de lo contrario, imprima NO.
Ejemplos :
Input : N = 12 Output : YES Sum of digits = 1+2 =3 and 3 divides 12. So, print YES. Input : N = 15 Output : NO
Extraiga dígitos del número y calcule la suma de todos sus dígitos y verifique si la suma de dígitos se sumerge en N o no.
A continuación se muestra la implementación del enfoque anterior:
C++
// C++ program to check if sum of
// digits of a number divides it
#include <iostream>
using namespace std;
// Function to check if sum of
// digits of a number divides it
int isSumDivides(int N)
{
int temp = N;
int sum = 0;
// Calculate sum of all of digits of N
while (temp) {
sum += temp % 10;
temp /= 10;
}
if (N % sum == 0)
return 1;
else
return 0;
}
// Driver Code
int main()
{
int N = 12;
if (isSumDivides(N))
cout << "YES";
else
cout << "NO";
return 0;
}
Java
// Java program to check if sum of
// digits of a number divides it
import java.util.*;
import java.lang.*;
class GFG
{
// Function to check if sum of
// digits of a number divides it
static int isSumDivides(int N)
{
int temp = N;
int sum = 0;
// Calculate sum of all of digits of N
while (temp > 0)
{
sum += temp % 10;
temp /= 10;
}
if (N % sum == 0)
return 1;
else
return 0;
}
// Driver Code
public static void main(String args[])
{
int N = 12;
if (isSumDivides(N) == 1)
System.out.print("YES");
else
System.out.print("NO");
}
}
// This code is contributed
// by Akanksha Rai(Abby_akku)
Python3
# Python3 program to check if sum of
# digits of a number divides it
# Function to check if sum of
# digits of a number divides it
def isSumDivides(N):
temp = N
sum = 0
# Calculate sum of all of
# digits of N
while (temp):
sum += temp % 10
temp = int(temp / 10)
if (N % sum == 0):
return 1
else:
return 0
# Driver Code
if __name__=='__main__':
N = 12
if (isSumDivides(N)):
print("YES")
else:
print("NO")
# This code is contributed by
# mits
C#
// C# program to check if sum of
// digits of a number divides it
using System;
// Function to check if sum of
// digits of a number divides it
class GFG
{
public int isSumDivides(int N)
{
int temp = N, sum = 0;
// Calculate sum of all of
// digits of N
while (temp > 0)
{
sum += temp % 10;
temp /= 10;
}
if (N % sum == 0)
return 1;
else
return 0;
}
// Driver Code
public static void Main()
{
GFG g = new GFG();
int N = 12;
if (g.isSumDivides(N) > 0)
Console.WriteLine("YES");
else
Console.WriteLine("NO");
}
}
// This code is contributed by Soumik
PHP
<?php
// PHP program to check if sum of
// digits of a number divides it
// Function to check if sum of
// digits of a number divides it
function isSumDivides($N)
{
$temp = $N;
$sum = 0;
// Calculate sum of all of
// digits of N
while ($temp)
{
$sum += $temp % 10;
$temp = (int)$temp / 10;
}
if ($N % $sum == 0)
return 1;
else
return 0;
}
// Driver Code
$N = 12;
if (isSumDivides($N))
echo "YES";
else
echo "NO";
// This code is contributed by ajit
?>
Javascript
<script>
// javascript program to check if sum of
// digits of a number divides it
// Function to check if sum of
// digits of a number divides it
function isSumDivides(N) {
var temp = N;
var sum = 0;
// Calculate sum of all of digits of N
while (temp > 0) {
sum += temp % 10;
temp = parseInt(temp/10);
}
if (N % sum == 0)
return 1;
else
return 0;
}
// Driver Code
var N = 12;
if (isSumDivides(N) == 1)
document.write("YES");
else
document.write("NO");
// This code contributed by aashish1995
</script>
Producción:
YES
Complejidad de tiempo : O (logn)
Espacio Auxiliar: O(1)