Comprobar el desbordamiento de enteros en la multiplicación

Dados dos enteros a y b, encuentre si su producto (axb) excede el entero de 64 bits con signo o no. Si excede, escriba Sí, de lo contrario, escriba No. 
Ejemplos: 
 

Input : a = 100, b = 200 
Output : No

Input : a = 10000000000,
        b = -10000000000
Output : Yes

Acercarse : 
 

  1. Si cualquiera de los números es 0, entonces nunca excederá el rango.
  2. De lo contrario, si el producto de los dos dividido por uno es igual al otro, entonces también estará dentro del rango.
  3. En cualquier otro caso, se producirá un desbordamiento.

C++

// CPP program to check for integer
// overflow on multiplication
#include <iostream>
using namespace std;
 
// Function to check whether there is
// overflow in a * b or not. It returns
// true if there is overflow.
bool isOverflow(long long a, long long b)
{
    // Check if either of them is zero
    if (a == 0 || b == 0)
        return false;
     
    long long result = a * b;
    if (a == result / b)
        return false;
    else
        return true;
}
 
// Driver code
int main()
{
    long long a = 10000000000, b = -10000000000;
    if (isOverflow(a, b))
        cout << "Yes";
    else
        cout << "No";
    return 0;
}

Java

// Java program to check for integer
// overflow on multiplication
import java.util.*;
import java.lang.*;
 
public class GfG{
     
    // Function to check whether there is
    // overflow in a * b or not. It
    // returns true if there is overflow.
    static Boolean isOverflow( long a, long b)
    {
        // Check if either of them is zero
        if (a == 0 || b == 0)
            return false;
     
        long result = a * b;
        if (a == result / b)
            return false;
        else
            return true;
    }
     
    // driver function
    public static void main(String argc[])
    {
        long a = Long.parseLong("10000000000");
        long b = Long.parseLong("-10000000000");
         
        if (isOverflow(a, b))
        System.out.print("Yes");
    else
        System.out.print("No");
    }
}
 
// This code is contributed by Prerna Saini

Python3

# Python program to check for integer
# overflow on multiplication
 
# Function to check whether there is
# overflow in a * b or not. It returns
# true if there is overflow.
def isOverflow(a, b):
 
    # Check if either of them is zero
    if (a == 0 or b == 0) :
        return False
 
    result = a * b
    if (result >= 9223372036854775807 or
        result <= -9223372036854775808):
        result=0
    if (a == (result // b)):
        print(result // b)
        return False
    else:
        return True
 
# Driver code
if __name__ =="__main__":
    a = 10000000000
    b = -10000000000
    if (isOverflow(a, b)):
        print( "Yes")
    else:
        print( "No")
         
# This code is contributed
# Shubham Singh(SHUBHAMSINGH10)

C#

// C# program to check for integer
// overflow on multiplication
using System;
 
public class GfG
{
     
    // Function to check whether there is
    // overflow in a * b or not. It
    // returns true if there is overflow.
    static bool isOverflow( long a, long b)
    {
        // Check if either of them is zero
        if (a == 0 || b == 0)
            return false;
     
        long result = a * b;
        if (a == result / b)
            return false;
        else
            return true;
    }
     
    // Driver function
    public static void Main()
    {
        long a = 10000000000;
        long b = -10000000000 ;
         
        if (isOverflow(a, b))
            Console.WriteLine("Yes");
        else
            Console.WriteLine("No");
    }
}
 
// This code is contributed by vt_m

PHP

<?php
// PHP program to check for integer
// overflow on multiplication
 
// Function to check whether there is
// overflow in a * b or not. It returns
// true if there is overflow.
function isOverflow($a, $b)
{
    // Check if either of them is zero
    if ($a == 0 || $b == 0)
        return false;
     
    $result = $a * $b;
    if ($a == (int)$result / $b)
        return false;
    else
        return true;
}
 
// Driver code
$a = 10000000000;
$b = -10000000000;
if (isOverflow($a, $b))
    echo "Yes";
else
    echo "No";
 
// This code is contributed by ajit.
?>

Javascript

<script>
 
// JavaScript program to check for integer
// overflow on multiplication
 
// Function to check whether there is
// overflow in a * b or not. It returns
// true if there is overflow.
function isOverflow(a, b)
{
    // Check if either of them is zero
    if (a == 0 || b == 0)
        return false;
     
    var result = a*b;
    if (result >= 9223372036854775807 ||
        result <= -9223372036854775808)
        result=0
    if (a == parseInt(result / b))
        return false;
    else
        return true;
}
 
// Driver code
var a = 10000000000, b = -10000000000;
if (isOverflow(a, b))
    document.write( "Yes");
else
    document.write( "No");
 
</script>

Producción:  

Yes

Complejidad del tiempo : O(1)
 

Publicación traducida automáticamente

Artículo escrito por Saif Haider y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA

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