Programa para encontrar mayor valor entre a^n y b^n

Dados tres enteros a, b y n, la tarea es encontrar el mayor valor entre a ⁿ y b ⁿ .
Ejemplos: 
 

Entrada: a = 3, b = 4, n = 5 
Salida: b^n es mayor que a^n  El
valor de a ⁿ es 243 y el valor de b ⁿ es 1024. 
Entonces, b ⁿ es mayor que a ⁿ .
Entrada: a = -3, b = 2, n = 4 
Salida: a^n es mayor que b^n  El
valor de a ⁿ es 243 y el valor de b ⁿ es 16. 
Entonces, a ⁿ es mayor que b ⁿ . 
 

Enfoque básico: para cada valor de a, b y n, calcule los valores de a ⁿ y b ⁿ . A continuación, compare el resultado obtenido y visualice el resultado según la salida.
El problema con este enfoque surge cuando hay valores grandes de a, b y n. Para valores grandes de a, n, el cálculo de una ⁿ puede exceder el límite de enteros, lo que provocará un desbordamiento de enteros.
Un mejor enfoque es comprobar el valor de n. 
 

• Si n es par, calcule el valor absoluto de a y b.
• Si n es impar, tome el valor dado tal como es.
• Ahora comprueba si a es igual a b. En caso afirmativo, imprima 0.
• Si a es mayor que b, imprima 1.
• De lo contrario, imprime 2.

// C++ code for finding greater
// between the a^n and b^n
#include <bits/stdc++.h>
using namespace std;
 
// Function to find the greater value
void findGreater(int a, int b, int n)
{
    // If n is even
    if (!(n & 1)) {
 
        a = abs(a);
        b = abs(b);
    }
    if (a == b)
        cout << "a^n is equal to b^n";
 
    else if (a > b)
        cout << "a^n is greater than b^n";
 
    else
        cout << "b^n is greater than a^n";
}
 
// Driver code
int main()
{
    int a = 12, b = 24, n = 5;
    findGreater(a, b, n);
    return 0;
}

// JAVA code for finding greater
// between the a^n and b^n
import java.io.*;
 
class GFG
{
    // Function to find
    // the greater value
    static void findGreater(int a,
                            int b, int n)
{
    // If n is even
    if (!((n & 1) > 0))
    {
 
        a = Math.abs(a);
        b = Math.abs(b);
    }
    if (a == b)
        System.out.println("a^n is " +
                           "equal to b^n");
 
    else if (a > b)
        System.out.println("a^n is greater " +
                                  "than b^n");
 
    else
        System.out.println("b^n is greater " +
                                  "than a^n");
}
 
// Driver code
public static void main (String[] args)
{
int a = 12, b = 24, n = 5;
findGreater(a, b, n);
}
}
 
// This code is contributed
// by shiv_bhakt.

# Python3 code for finding greater
# between the a^n and b^n
import math
 
# Function to find the greater value
def findGreater(a, b, n):
 
    # If n is even
    if ((n & 1) > 0):
 
        a = abs(a);
        b = abs(b);
    if (a == b):
        print("a^n is equal to b^n");
 
    elif (a > b):
        print("a^n is greater than b^n");
 
    else:
        print("b^n is greater than a^n");
 
# Driver code
a = 12;
b = 24;
n = 5;
findGreater(a, b, n);
 
# This code is contributed by mits

// C# code for finding greater
// between the a^n and b^n
using System;
 
class GFG
{
    // Function to find
    // the greater value
    static void findGreater(int a,
                            int b,
                            int n)
    {
    // If n is even
    if (!((n & 1) > 0))
    {
 
        a = Math.Abs(a);
        b = Math.Abs(b);
    }
     
    if (a == b)
        Console.WriteLine("a^n is " +
                          "equal to b^n");
 
    else if (a > b)
        Console.WriteLine("a^n is greater " +
                                 "than b^n");
 
    else
        Console.WriteLine("b^n is greater " +
                                 "than a^n");
}
 
// Driver code
public static void Main()
{
    int a = 12, b = 24, n = 5;
    findGreater(a, b, n);
}
}
 
// This code is contributed
// by shiv_bhakt.

<?php
// PHP code for finding greater
// between the a^n and b^n
 
// Function to find
// the greater value
function findGreater($a, $b, $n)
{
    // If n is even
    if (!($n & 1))
    {
 
        $a = abs($a);
        $b = abs($b);
    }
    if ($a == $b)
        echo "a^n is equal to b^n";
 
    else if ($a > $b)
        echo "a^n is greater than b^n";
 
    else
        echo "b^n is greater than a^n";
}
 
// Driver code
$a = 12; $b = 24; $n = 5;
findGreater($a, $b, $n);
 
// This code is contributed by ajit
?>

<script>
 
// Javascript code for finding greater
// between the a^n and b^n
 
    // Function to find
    // the greater value
    function findGreater(a , b , n)
    {
        // If n is even
        if (!((n & 1) > 0)) {
 
            a = Math.abs(a);
            b = Math.abs(b);
        }
        if (a == b)
            document.write("a^n is " + "equal to b^n");
 
        else if (a > b)
            document.write("a^n is greater " + "than b^n");
 
        else
            document.write("b^n is greater " + "than a^n");
    }
 
    // Driver code
     
        var a = 12, b = 24, n = 5;
        findGreater(a, b, n);
 
// This code is contributed by todaysgaurav
 
</script>

b^n is greater than a^n

Complejidad de tiempo: O(1)

Espacio Auxiliar: O(1)