Dado un número, la tarea es verificar si el número es divisible por 20. El número de entrada puede ser grande y puede que no sea posible almacenar int largo y puede ser un número muy grande, entonces usamos la string.
Ejemplos:
Input : 7575680 Output : Yes Input : 987985865687690 Output : No
Un número es divisible por 20 si es divisible por 5 y 4. Podemos comprobar si un número es divisible por 4 comprobando si los dos últimos dígitos son divisibles por 4 . Podemos comprobar la divisibilidad por 5 comprobando el último dígito . Además, si el último dígito de un número es cero y el penúltimo dígito es un múltiplo de 2, entonces el número es divisible por 20.
C++
// CPP program to check if a large number
// is divisible by 20.
#include <iostream>
using namespace std;
bool divisibleBy20(string num)
{
// Get number with last two digits
int lastTwoDigits = stoi(num.substr(num.length() - 2,
num.length() - 1));
// Check if the number formed by last two
// digits is divisible by 5 and 4.
return ((lastTwoDigits % 5 == 0) &&
(lastTwoDigits % 4 == 0));
}
int main()
{
string num = "63284689320";
if (divisibleBy20(num))
cout << "Yes" << endl;
else
cout << "No" << endl;
return 0;
}
Java
// Java program to check if a large n
// number is divisible by 20.
import java.io.*;
class GFG {
static Boolean divisibleBy20(String num)
{
// Get number with last two digits
int lastTwoDigits = Integer.parseInt(num.substring(num.length() - 2,
num.length() ));
// Check if the number formed by last two
// digits is divisible by 5 and 4.
return ((lastTwoDigits % 5 == 0) &&
(lastTwoDigits % 4 == 0));
}
// Driver Program
public static void main (String[] args)
{
String num = "63284689320";
if (divisibleBy20(num) == true)
System.out.println("Yes");
else
System.out.println("No");
}
}
// This code is contributed by Gitanjali.
Python3
# Python3 program to check if a large
# number is divisible by 20.
import math
def divisibleBy20(num):
# Get number with last two digits
lastTwoDigits = int(num[-2:])
# Check if the number formed by last two
# digits is divisible by 5 and 4.
return ((lastTwoDigits % 5 == 0 and
lastTwoDigits % 4 == 0))
# driver code
num = "63284689320"
if (divisibleBy20(num) == True):
print("Yes")
else:
print("No")
# This code is contributed by Gitanjali.
C#
// C# program to check if a large
// 'n' number is divisible by 20.
using System;
using System.Text;
class GFG
{
static bool divisibleBy20(String num)
{
// Get number with last two digits
int lastTwoDigits = Int32.Parse(num.Substring(2));
// Check if the number formed
// by last two digits is
// divisible by 5 and 4.
return ((lastTwoDigits % 5 == 0) &&
(lastTwoDigits % 4 == 0));
}
// Driver Code
static public void Main ()
{
String num = "63284689320";
if (divisibleBy20(num) == true)
Console.Write("Yes");
else
Console.Write("No");
}
}
// This code is contributed by Raj
PHP
<?php
// PHP program to check
// if a large number is
// divisible by 20.
function divisibleBy20($num)
{
// Get number with
// last two digits
$lastTwoDigits = intval(substr($num,
(strlen($num) - 2), 2));
// Check if the number
// formed by last two
// digits is divisible
// by 5 and 4.
return (($lastTwoDigits % 5 == 0) &&
($lastTwoDigits % 4 == 0));
}
// Driver Code
$num = "63284689320";
if (divisibleBy20($num))
echo "Yes";
else
echo "No";
// This code is contributed by mits.
?>
Javascript
<script>
// Javascript program to check
// if a large number is
// divisible by 20.
function divisibleBy20(num)
{
// Get number with
// last two digits
let lastTwoDigits = parseInt(num.slice(-2, num.length))
console.log(num.slice(-2, 1))
// Check if the number
// formed by last two
// digits is divisible
// by 5 and 4.
return ((lastTwoDigits % 5 == 0) &&
(lastTwoDigits % 4 == 0))
}
// Driver Code
let num = "63284689320";
if (divisibleBy20(num))
document.write("Yes");
else
document.write("No");
// This code is contributed by _saurabh_jaiswal.
</script>
Producción
Yes
Método: Comprobación de que el número dado es divisible por 20 o no utilizando el operador de división de módulo «%».
C++
#include <iostream>
using namespace std;
int main() {
// input number
long int num = 987985865687690;
// finding given number is divisible by 20 or not
if (num % 20 == 0) {
cout<<"Yes";
}
else {
cout<<"No";
}
return 0;
}
// This code is contributed by laxmigangarajula03
Java
// Java code for the above approach
// To check whether the given number is divisible by 20 or
// not
import java.math.BigInteger;
class GFG {
public static void main(String[] args)
{
// input number
BigInteger num = new BigInteger("987985865687690");
// finding given number is divisible by 20 or not
if (num.mod(new BigInteger("20"))
.equals(new BigInteger("0"))) {
System.out.println("Yes");
}
else {
System.out.println("No");
}
}
}
// This code is contributed by phasing17
Python3
# Python code
# To check whether the given number is divisible by 20 or not
#input
n=987985865687690
# the above input can also be given as n=input() -> taking input from user
# finding given number is divisible by 20 or not
if int(n)%20==0:
print("Yes")
else:
print("No")
# this code is contributed by gangarajula laxmi
C#
// C# code for the above approach
// To check whether the given number is divisible by 20 or
// not
using System;
public class GFG {
static public void Main()
{
// input number
long num = 987985865687690;
// finding given number is divisible by 20 or not
if (num % 20 == 0) {
Console.Write("Yes");
}
else {
Console.Write("No");
}
}
}
// This code is contributed by laxmigangarajula03
Javascript
<script>
// JavaScript code for the above approach
// To check whether the given number is divisible by 20 or not
//input
var n = 987985865687690
// the above input can also be given as n=input() -> taking input from user
// finding given number is divisible by 20 or not
if (n % 20 == 0)
document.write("Yes")
else
document.write("No")
// This code is contributed by Potta Lokesh
</script>
Producción
No