Dados dos vectores en forma de (xi+yj+zk) de dos lados adyacentes de un paralelogramo. La tarea es encontrar el área de un paralelogramo.
Ejemplo:
Entrada:
x1 = 3, y1 = 1, z1 = -2
x2 = 1, y2 = -3, z2 = 4
Salida: Área = 17,3205081
Entrada:
x1 = 1, y1 = 3, z1 = 2
x2 = 1, y2 = -3, z2 = 4
Salida: Área = 19,078784028338912
Enfoque: supongamos que tenemos dos vectores a(x1*i+y1*j+z1*k) y b(x2*i+y2*j+z2*k) y sabemos que el área del paralelogramo está dada por:
Área del paralelogramo = magnitud del producto vectorial de los vectores a y b, es decir, |axb|
Y sabemos a X b = (y1*z2 – y2*z1)*i – (x1*z2 – x2*z1)*j + (x1*y2 – x2*y1)*k
Entonces área =
C++
// C++ code to calculate area of // parallelogram if vectors of // 2 adjacent sides are given #include<bits/stdc++.h> using namespace std ; // Function to calculate area of parallelogram float area(float x1, float y1, float z1, float x2, float y2, float z2) { float area = sqrt(pow((y1 * z2 - y2 * z1),2) + pow((x1 * z2 - x2 * z1),2) + pow((x1 * y2 - x2 * y1),2)); return area; } // Driver Code int main() { float x1 = 3; float y1 = 1; float z1 = -2; float x2 = 1; float y2 = -3; float z2 = 4; float a = area(x1, y1, z1, x2, y2, z2); cout << "Area = " << a; return 0; // This code is contributed // by Amber_Saxena. }
Java
// Java code to calculate area of // parallelogram if vectors of // 2 adjacent sides are given public class GFG { // Function to calculate area of parallelogram static float area(float x1, float y1, float z1, float x2, float y2, float z2) { float area =(float) Math.sqrt(Math.pow((y1 * z2 - y2 * z1),2) + Math.pow((x1 * z2 - x2 * z1),2) + Math.pow((x1 * y2 - x2 * y1),2)); return area; } // Driver code public static void main (String args[]){ float x1 = 3; float y1 = 1; float z1 = -2; float x2 = 1; float y2 = -3; float z2 = 4; float a = area(x1, y1, z1, x2, y2, z2); System.out.println("Area = " + a) ; } // This code is contributed by ANKITRAI1 }
Python
# Python code to calculate area of # parallelogram if vectors of # 2 adjacent sides are given import math # to calculate area of parallelogram def area(x1, y1, z1, x2, y2, z2): area = math.sqrt((y1 * z2 - y2 * z1) ** 2 + (x1 * z2 - x2 * z1) ** 2 + (x1 * y2 - x2 * y1) ** 2) return area # main function def main(): x1 = 3 y1 = 1 z1 = -2 x2 = 1 y2 = -3 z2 = 4 a = area(x1, y1, z1, x2, y2, z2) print("Area = ", a) # driver code if __name__=="__main__": main()
C#
// C# code to calculate area of // parallelogram if vectors of // 2 adjacent sides are given using System; class GFG { // Function to calculate area // of parallelogram static float area(float x1, float y1, float z1, float x2, float y2, float z2) { float area = (float) Math.Sqrt(Math.Pow((y1 * z2 - y2 * z1), 2) + Math.Pow((x1 * z2 - x2 * z1), 2) + Math.Pow((x1 * y2 - x2 * y1), 2)); return area; } // Driver code public static void Main () { float x1 = 3; float y1 = 1; float z1 = -2; float x2 = 1; float y2 = -3; float z2 = 4; float a = area(x1, y1, z1, x2, y2, z2); Console.Write("Area = " + a) ; } } // This code is contributed // by ChitraNayal
PHP
<?php // PHP code to calculate area of // parallelogram if vectors of // 2 adjacent sides are given // Function to calculate area // of parallelogram function area($x1, $y1, $z1, $x2, $y2, $z2) { $area = sqrt(pow(($y1 * $z2 - $y2 * $z1), 2) + pow(($x1 * $z2 - $x2 * $z1), 2) + pow(($x1 * $y2 - $x2 * $y1), 2)); return $area; } // Driver Code $x1 = 3; $y1 = 1; $z1 = -2; $x2 = 1; $y2 = -3; $z2 = 4; $a = area($x1, $y1, $z1, $x2, $y2, $z2); echo ("Area = "); echo ($a); // This code is contributed // by Shivi_Aggarwal ?>
Javascript
<script> // Javascript code to calculate area of // parallelogram if vectors of // 2 adjacent sides are given // Function to calculate area // of parallelogram function area(x1, y1, z1, x2, y2, z2) { area = Math.sqrt(Math.pow((y1 * z2 - y2 * z1), 2) + Math.pow((x1 * z2 - x2 * z1), 2) + Math.pow((x1 * y2 - x2 * y1), 2)); return area; } // Driver Code let x1 = 3; let y1 = 1; let z1 = -2; let x2 = 1; let y2 = -3; let z2 = 4; a = area(x1, y1, z1, x2, y2, z2); document.write ("Area = "); document.write (a); // This code is contributed by Bobby </script>
Area = 17.320508075688775
Complejidad de tiempo: O(1)
Espacio Auxiliar: O(1)
Publicación traducida automáticamente
Artículo escrito por AashutoshChauhan y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA