Programa para encontrar el XOR de valores ASCII de caracteres en una string

Dada una string str , la tarea es encontrar el XOR de los valores ASCII de los caracteres de la string.
Ejemplos: 
 

Entrada: str = «Geeks» 
Salida: 95 
Valor ASCII de G = 71 
Valor ASCII de e = 101 
Valor ASCII de e = 101 
Valor ASCII de k = 107 
Valor ASCII de s = 115 
XOR de valores ASCII = 71 ^ 101 ^ 101 ^ 107 ^ 115 = 95
Entrada: str = “GfG” 
Salida: 102 
 

Enfoque: La idea es averiguar el valor ASCII de cada carácter uno por uno y encontrar el valor XOR de estos valores .
A continuación se muestra la implementación del enfoque anterior: 
 

// C++ program to find XOR of ASCII
// value of characters in string
 
#include <bits/stdc++.h>
using namespace std;
 
// Function to find the XOR of ASCII
// value of characters in string
int XorAscii(string str, int len)
{
 
    // store value of first character
    int ans = int(str[0]);
 
    for (int i = 1; i < len; i++) {
 
        // Traverse string to find the XOR
        ans = (ans ^ (int(str[i])));
    }
 
    // Return the XOR
    return ans;
}
 
// Driver code
int main()
{
 
    string str = "geeksforgeeks";
    int len = str.length();
    cout << XorAscii(str, len) << endl;
 
    str = "GfG";
    len = str.length();
    cout << XorAscii(str, len);
 
    return 0;
}

// Java program to find XOR of ASCII
// value of characters in String
class GFG{
  
// Function to find the XOR of ASCII
// value of characters in String
static int XorAscii(String str, int len)
{
  
    // store value of first character
    int ans = (str.charAt(0));
  
    for (int i = 1; i < len; i++) {
  
        // Traverse String to find the XOR
        ans = (ans ^ ((str.charAt(i))));
    }
  
    // Return the XOR
    return ans;
}
  
// Driver code
public static void main(String[] args)
{
  
    String str = "geeksforgeeks";
    int len = str.length();
    System.out.print(XorAscii(str, len) +"\n");
  
    str = "GfG";
    len = str.length();
    System.out.print(XorAscii(str, len));
}
}
 
// This code is contributed by PrinciRaj1992

# Python3 program to find XOR of ASCII
# value of characters in string
 
# Function to find the XOR of ASCII
# value of characters in string
def XorAscii(str1, len1):
 
    # store value of first character
    ans = ord(str1[0])
 
    for i in range(1,len1):
 
        # Traverse string to find the XOR
        ans = (ans ^ (ord(str1[i])))
 
    # Return the XOR
    return ans
 
# Driver code
str1 = "geeksforgeeks"
len1 = len(str1)
print(XorAscii(str1, len1))
 
str1 = "GfG"
len1 = len(str1)
print(XorAscii(str1, len1))
 
# This code is contributed by mohit kumar 29

// C# program to find XOR of ASCII
// value of characters in String
using System;
 
class GFG{
   
// Function to find the XOR of ASCII
// value of characters in String
static int XorAscii(String str, int len)
{
   
    // store value of first character
    int ans = (str[0]);
   
    for (int i = 1; i < len; i++) {
   
        // Traverse String to find the XOR
        ans = (ans ^ ((str[i])));
    }
   
    // Return the XOR
    return ans;
}
   
// Driver code
public static void Main(String[] args)
{
   
    String str = "geeksforgeeks";
    int len = str.Length;
    Console.Write(XorAscii(str, len) +"\n");
   
    str = "GfG";
    len = str.Length;
    Console.Write(XorAscii(str, len));
}
}
 
// This code is contributed by PrinciRaj1992

<script>
 
// Javascript program to find XOR of ASCII
// value of characters in string
 
// Function to find the XOR of ASCII
// value of characters in string
function XorAscii(str, len)
{
 
    // store value of first character
    let ans = str.codePointAt(0);
 
    for (let i = 1; i < len; i++) {
 
        // Traverse string to find the XOR
        ans = (ans ^ (str.codePointAt(i)));
    }
 
    // Return the XOR
    return ans;
}
 
// Driver code
 
    let str = "geeksforgeeks";
    let len = str.length;
    document.write(XorAscii(str, len) + "<br>");
 
    str = "GfG";
    len = str.length;
    document.write(XorAscii(str, len));
 
</script>

123
102

Complejidad de tiempo: O(N) , donde N es la longitud de la string.