Dado un número entero N, la tarea es convertirlo en una array de caracteres.
Ejemplo:
Entrada: N = 2020
Salida: {2, 0, 2, 0}
Explicación: Aquí char array arr[] = {2, 0, 2, 0}
Entrada: N = 12349
Salida: {1, 2, 3, 4, 9}
Explicación: Aquí char array arr[] = {1, 2, 3, 4, 9}
Enfoque: el enfoque básico para hacer esto es encontrar recursivamente todos los dígitos de N e insertarlos en la array de caracteres requerida.
- Cuente los dígitos totales en el número.
- Declare una array char de dígitos de tamaño en el número.
- Separar enteros en dígitos y acomodarlos a una array de caracteres.
- Agregar el valor ASCII del carácter ‘0’ es 48 en cada elemento de la array.
A continuación se muestra la implementación del enfoque anterior:
C
// C program to convert integer
// number into character array
#include <stdio.h>
#include <stdlib.h>
// Function to convert integer to
// character array
char* convertIntegerToChar(int N)
{
// Count digits in number N
int m = N;
int digit = 0;
while (m) {
// Increment number of digits
digit++;
// Truncate the last
// digit from the number
m /= 10;
}
// Declare char array for result
char* arr;
// Declare duplicate char array
char arr1[digit];
// Memory allocation of array
arr = (char*)malloc(digit);
// Separating integer into digits and
// accommodate it to character array
int index = 0;
while (N) {
// Separate last digit from
// the number and add ASCII
// value of character '0' is 48
arr1[++index] = N % 10 + '0';
// Truncate the last
// digit from the number
N /= 10;
}
// Reverse the array for result
int i;
for (i = 0; i < index; i++) {
arr[i] = arr1[index - i];
}
// Char array truncate by null
arr[i] = '\0';
// Return char array
return (char*)arr;
}
// Driver Code
int main()
{
// Given number
int N = 12349;
int len = 5;
// Function call
char* arr = convertIntegerToChar(N);
// Print char array
for (int i = 0; i < len; i++)
printf("%c, ", arr[i]);
return 0;
}
Java
// Java program to convert integer
// number into character array
class GFG{
// Function to convert integer to
// character array
static char[] convertIntegerToChar(int N)
{
// Count digits in number N
int m = N;
int digit = 0;
while (m > 0)
{
// Increment number of digits
digit++;
// Truncate the last
// digit from the number
m /= 10;
}
// Declare char array for result
char[] arr;
// Declare duplicate char array
char []arr1 = new char[digit + 1];
// Memory allocation of array
arr = new char[digit];
// Separating integer into digits and
// accommodate it to character array
int index = 0;
while (N > 0)
{
// Separate last digit from
// the number and add ASCII
// value of character '0' is 48
arr1[++index] = (char)(N % 10 + '0');
// Truncate the last
// digit from the number
N /= 10;
}
// Reverse the array for result
int i;
for(i = 0; i < index; i++)
{
arr[i] = arr1[index - i];
}
// Return char array
return (char[])arr;
}
// Driver Code
public static void main(String[] args)
{
// Given number
int N = 12349;
int len = 5;
// Function call
char[] arr = convertIntegerToChar(N);
// Print char array
for(int i = 0; i < len; i++)
System.out.printf("%c, ", arr[i]);
}
}
// This code is contributed by amal kumar choubey
Python3
# Python3 program to convert integer # number into character array # Function to convert integer to # character array def convertIntegerToChar(N): # Count digits in number N m = N; digit = 0; while (m > 0): # Increment number of digits digit += 1; # Truncate the last # digit from the number m /= 10; # Declare char array for result arr = ['0' for i in range(digit)] # Declare duplicate char array arr1 = ['0' for i in range(digit + 1)]; # Separating integer # into digits and # accommodate it # to character array index = 0; while (N > 0): index += 1; # Separate last digit from # the number and add ASCII # value of character '0' is 48 arr1[index] = chr(int(N % 10 + 48)); # Truncate the last # digit from the number N = N // 10; # Reverse the array for result for i in range(0, index): arr[i] = arr1[index - i]; # Return char array return arr; # Driver Code if __name__ == '__main__': # Given number N = 12349; len = 5; # Function call arr = convertIntegerToChar(N); # Print array for i in range(0, len, 1): print(arr[i], end = " "); # This code is contributed by gauravrajput1
C#
// C# program to convert integer
// number into character array
using System;
class GFG{
// Function to convert integer to
// character array
static char[] convertintToChar(int N)
{
// Count digits in number N
int m = N;
int digit = 0;
while (m > 0)
{
// Increment number of digits
digit++;
// Truncate the last
// digit from the number
m /= 10;
}
// Declare char array for result
char[] arr;
// Declare duplicate char array
char []arr1 = new char[digit + 1];
// Memory allocation of array
arr = new char[digit];
// Separating integer into digits and
// accommodate it to character array
int index = 0;
while (N > 0)
{
// Separate last digit from
// the number and add ASCII
// value of character '0' is 48
arr1[++index] = (char)(N % 10 + '0');
// Truncate the last
// digit from the number
N /= 10;
}
// Reverse the array for result
int i;
for(i = 0; i < index; i++)
{
arr[i] = arr1[index - i];
}
// Return char array
return (char[])arr;
}
// Driver Code
public static void Main(String[] args)
{
// Given number
int N = 12349;
int len = 5;
// Function call
char[] arr = convertintToChar(N);
// Print char array
for(int i = 0; i < len; i++)
Console.Write("{0}, ", arr[i]);
}
}
// This code is contributed by amal kumar choubey
Javascript
<script>
// Javascript program to convert integer
// number into character array
// Function to convert integer to
// character array
function convertIntegerToChar(N)
{
// Count digits in number N
let m = N;
let digit = 0;
while (m > 0)
{
// Increment number of digits
digit++;
// Truncate the last
// digit from the number
m = parseInt(m / 10, 10);
}
// Declare char array for result
let arr;
// Declare duplicate char array
let arr1 = new Array(digit + 1);
// Memory allocation of array
arr = new Array(digit);
// Separating integer into digits and
// accommodate it to character array
let index = 0;
while (N > 0)
{
// Separate last digit from
// the number and add ASCII
// value of character '0' is 48
arr1[++index] = String.fromCharCode(N % 10 + '0'.charCodeAt());
// Truncate the last
// digit from the number
N = parseInt(N / 10, 10);
}
// Reverse the array for result
let i;
for(i = 0; i < index; i++)
{
arr[i] = arr1[index - i];
}
// Return char array
return arr;
}
// Given number
let N = 12349;
let len = 5;
// Function call
let arr = convertIntegerToChar(N);
// Print char array
for(let i = 0; i < len; i++)
document.write(arr[i] + ", ");
// This code is contributed by divyeshtsbsdiya07
</script>
Producción:
1, 2, 3, 4, 9,
Publicación traducida automáticamente
Artículo escrito por manikumartharmaraj y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA