Dados dos enteros a y b , la tarea es sumarlos para obtener c . Después de eso, elimine los ceros de a , b y c y verifique los valores modificados si a + b = c , luego devuelva «SÍ» , de lo contrario, devuelva «NO» .
Ejemplos:
Entrada: a = 101, b = 102
Salida: SÍ
101 + 102 = 203.
Después de eliminar todos los ceros de a, b y c, a = 11, b = 12 y c = 23
Ahora verifique si a + b = c, es decir, 11 + 12 = 23 . Así que imprime Sí.
Entrada: a = 105, b = 108
Salida: NO
Después de eliminar todos los ceros a + b != c , por lo tanto, la salida es NO.
Acercarse:
- Cree una función para eliminar cero del número n .
- Compruebe si (eliminar cero (a) + eliminar cero (b) == eliminar cero (a + b)) y luego imprimir SÍ , de lo contrario, imprimir NO
A continuación se muestra la implementación del enfoque anterior.
C++
// C++ program to check the sum after
// Removing all zeroes is true or not
#include <bits/stdc++.h>
using namespace std;
// Function to remove zeroes
int removeZero(int n)
{
// Initialize result to zero holds the
// Result after removing zeroes from no
int res = 0;
// Initialize variable d to 1 that holds
// digits of no
int d = 1;
// Loop while n is greater than zero
while (n > 0) {
// Check if n mod 10 is not equal to
// zero
if (n % 10 != 0) {
// store the result by removing zeroes
// And increment d by 10
res += (n % 10) * d;
d *= 10;
}
// Go to the next digit
n /= 10;
}
// Return the result
return res;
}
// Function to check if sum is true after
// Removing all zeroes.
bool isEqual(int a, int b)
{
// Call removeZero() for both sides
// and check whether they are equal
// After removing zeroes.
if (removeZero(a) + removeZero(b) == removeZero(a + b))
return true;
return false;
}
// Driver code
int main()
{
int a = 105, b = 106;
isEqual(a, b) ? cout << "Yes"
: cout << "No";
return 0;
}
Java
// Java program to check the sum after
// Removing all zeroes is true or not
public class GfG {
// Function to remove zeroes
public static int removeZero(int n)
{
// Initialize result to zero holds the
// Result after removing zeroes from no
int res = 0;
// Initialize variable d to 1 that holds
// digits of no
int d = 1;
// Loop while n is greater than zero
while (n > 0) {
// Check if n mod 10 is not equal to
// zero
if (n % 10 != 0) {
// store the result by removing zeroes
// And increment d by 10
res += (n % 10) * d;
d *= 10;
}
// Go to the next digit
n /= 10;
}
// Return the result
return res;
}
// Function to check if sum is true after
// Removing all zeroes.
public static boolean isEqual(int a, int b)
{
// Call removeZero() for both sides
// and check whether they are equal
// After removing zeroes.
if (removeZero(a) + removeZero(b) == removeZero(a + b))
return true;
return false;
}
public static void main(String []args){
int a = 105, b = 106;
if (isEqual(a, b) == true)
System.out.println("Yes");
else
System.out.println("No");
}
}
// This code is contributed by Rituraj Jain
Python3
# Python 3 program to check the sum after
# Removing all zeroes is true or not
# Function to remove zeroes
def removeZero(n):
# Initialize result to zero holds the
# Result after removing zeroes from no
res = 0
# Initialize variable d to 1 that
# holds digits of no
d = 1
# Loop while n is greater than zero
while (n > 0):
# Check if n mod 10 is not equal
# to zero
if (n % 10 != 0):
# store the result by removing
# zeroes And increment d by 10
res += (n % 10) * d
d *= 10
# Go to the next digit
n //= 10
# Return the result
return res
# Function to check if sum is true
# after Removing all zeroes.
def isEqual(a, b):
# Call removeZero() for both sides
# and check whether they are equal
# After removing zeroes.
if (removeZero(a) +
removeZero(b) == removeZero(a + b)):
return True
return False
# Driver code
a = 105
b = 106
if(isEqual(a, b)):
print("Yes")
else:
print("No")
# This code is contributed
# by sahishelangia
C#
// C# program to check the sum after
// Removing all zeroes is true or not
using System;
class GFG
{
// Function to remove zeroes
public static int removeZero(int n)
{
// Initialize result to zero holds the
// Result after removing zeroes from no
int res = 0;
// Initialize variable d to 1 that holds
// digits of no
int d = 1;
// Loop while n is greater than zero
while (n > 0)
{
// Check if n mod 10 is not equal to
// zero
if (n % 10 != 0)
{
// store the result by removing zeroes
// And increment d by 10
res += (n % 10) * d;
d *= 10;
}
// Go to the next digit
n /= 10;
}
// Return the result
return res;
}
// Function to check if sum is true after
// Removing all zeroes.
public static bool isEqual(int a, int b)
{
// Call removeZero() for both sides
// and check whether they are equal
// After removing zeroes.
if (removeZero(a) +
removeZero(b) == removeZero(a + b))
return true;
return false;
}
// Driver Code
public static void Main()
{
int a = 105, b = 106;
if (isEqual(a, b) == true)
Console.WriteLine("Yes");
else
Console.WriteLine("No");
}
}
// This code is contributed
// by Akanksha Rai
PHP
<?php
// PHP program to check the sum after
// Removing all zeroes is true or not.
// Function to remove zeroes
function removeZero($n)
{
// Initialize result to zero holds the
// Result after removing zeroes from no
$res = 0;
// Initialize variable d to 1 that
// holds digits of no
$d = 1;
// Loop while n is greater than zero
while ($n > 0)
{
// Check if n mod 10 is not equal
// to zero
if ($n % 10 != 0)
{
// store the result by removing
// zeroes and increment d by 10
$res += ($n % 10) * $d;
$d *= 10;
}
// Go to the next digit
$n = floor($n / 10);
}
// Return the result
return $res;
}
// Function to check if sum is true
// after Removing all zeroes.
function isEqual($a, $b)
{
// Call removeZero() for both sides
// and check whether they are equal
// After removing zeroes.
if (removeZero($a) +
removeZero($b) == removeZero($a + $b))
return true;
return false;
}
// Driver code
$a = 105 ;
$b = 106 ;
if (isEqual($a, $b))
echo "Yes";
else
echo "No";
// This code is contributed by Ryuga
?>
Javascript
<script>
// Javascript program to check the sum after
// Removing all zeroes is true or not
// Function to remove zeroes
function removeZero( n)
{
// Initialize result to zero holds the
// Result after removing zeroes from no
let res = 0;
// Initialize variable d to 1 that holds
// digits of no
let d = 1;
// Loop while n is greater than zero
while (n > 0) {
// Check if n mod 10 is not equal to
// zero
if (n % 10 != 0) {
// store the result by removing zeroes
// And increment d by 10
res += (n % 10) * d;
d *= 10;
}
// Go to the next digit
n = Math.floor(n/10);
}
// Return the result
return res;
}
// Function to check if sum is true after
// Removing all zeroes.
function isEqual( a, b)
{
// Call removeZero() for both sides
// and check whether they are equal
// After removing zeroes.
if (removeZero(a) + removeZero(b) == removeZero(a + b))
return true;
return false;
}
// Driver Code
let a = 105, b = 106;
if (isEqual(a, b) == true)
document.write("Yes");
else
document.write("No");
</script>
Producción:
No
Complejidad de tiempo: O (log 10 n)
Espacio Auxiliar: O(1)