Encuentre el radio de los círculos que están alineados en una fila, y se da la distancia entre los centros del primer y último círculo.

Aquí se dan n círculos que se tocan entre sí externamente y están alineados en una fila. Se da la distancia entre los centros del primer y último círculo. Los círculos tienen un radio de igual longitud. La tarea es encontrar el radio de cada círculo. 
Ejemplos: 
 

Input: d = 42, n = 4
Output: The radius of each circle is 7

Input: d = 64, n = 5
Output: The radius of each circle is 8

Enfoque : 
supongamos que hay n círculos, cada uno de los cuales tiene un radio de longitud r . 
Sea, la distancia entre el primer y el último círculo = d 
De la figura, está claro, 
r + r + (n-2)*2r = d 
2r + 2nr – 4r = d 
2nr – 2r = d 
entonces, r = d /(2n-2)

 

// C++ program to find radii of the circles
// which are lined in a row
// and distance between the
// centers of first and last circle is given
 
#include <bits/stdc++.h>
using namespace std;
 
void radius(int n, int d)
{
    cout << "The radius of each circle is "
         << d / (2 * n - 2) << endl;
}
 
// Driver code
int main()
{
    int d = 42, n = 4;
    radius(n, d);
    return 0;
}

// Java program to find radii of the circles
// which are lined in a row
// and distance between the
// centers of first and last circle is given
import java.io.*;
 
class GFG
{
 
static void radius(int n, int d)
{
    System.out.print( "The radius of each circle is "
        +d / (2 * n - 2));
}
 
// Driver code
static public void main (String []args)
{
    int d = 42, n = 4;
    radius(n, d);
}
}
 
// This code is contributed by anuj_67..

# Python program to find radii of the circles
# which are lined in a row
# and distance between the
# centers of first and last circle is given
 
def radius(n, d):
    print("The radius of each circle is ",
        d / (2 * n - 2));
 
d = 42; n = 4;
radius(n, d);
 
 
# This code is contributed by PrinciRaj1992

// C# program to find radii of the circles
// which are lined in a row
// and distance between the
// centers of first and last circle is given
using System;
 
class GFG
{
 
static void radius(int n, int d)
{
    Console.Write( "The radius of each circle is "
        +d / (2 * n - 2));
}
 
// Driver code
static public void Main ()
{
    int d = 42, n = 4;
    radius(n, d);
}
}
 
// This code is contributed by anuj_67..

<script>
// javascript program to find radii of the circles
// which are lined in a row
// and distance between the
// centers of first and last circle is given
function radius(n , d)
{
    document.write( "The radius of each circle is "
        +d / (2 * n - 2));
}
 
// Driver code
var d = 42, n = 4;
radius(n, d);
 
// This code is contributed by 29AjayKumar
</script>

The radius of each circle is 7

Complejidad de tiempo: O(1)

Espacio Auxiliar: O(1)