- Patrón de triángulo incremental numérico
Escriba un programa para imprimir un patrón de triángulo incremental numérico comenzando con un número dado N.
Ejemplos:
Input : 3
Output : 3
4 5
6 7 8
4 5
3
A continuación se muestra la implementación del problema mencionado anteriormente.
C++
#include <iostream>
using namespace std;
int main()
{
int i, j, r, N, count;
N = 3; // initializing N
N--;
r = 5;
for (i = 0; i < r; i++) {
if (i <= r / 2) {
count = N + 1;
for (j = 0; j <= i; j++) {
N++;
cout << N << " ";
}
cout << endl;
}
else {
N = count - (r - i);
count = N;
for (j = i; j < r; j++) {
cout << N << " ";
N++;
}
cout << endl;
}
}
}
Java
// Java Program for incrementing
// or decrementing triangle pattern
import java.io.*;
class GFG
{
public static void main(String args[])
{
int i, j, r, N, count = 0;
N = 3; // initializing N
N--;
r = 5;
for (i = 0; i < r; i++)
{
if (i <= r / 2)
{
count = N + 1;
for (j = 0; j <= i; j++)
{
N++;
System.out.print(N + " ");
}
System.out.println();
}
else
{
N = count - (r - i);
count = N;
for (j = i; j < r; j++)
{
System.out.print(N + " ");
N++;
}
System.out.println();
}
}
}
}
// This code is contributed
// by Subhadeep Gupta
Python 3
# python 3 program to print incrementing # and decrementing triangle pattern if __name__ == "__main__": N = 3 # initializing N N -= 1 r = 5 for i in range( r): if i <= r // 2: count = N + 1 for j in range(i + 1): N += 1 print(str(N), end = " ") print() else : N = count - (r - i) count = N for j in range(i, r): print(str(N), end = " ") N += 1 print() # This code is contributed # by ChitraNayal
C#
// C# Program for incrementing
// or decrementing triangle pattern
using System;
class GFG
{
public static void Main()
{
int i, j, r, N, count = 0;
N = 3; // initializing N
N--;
r = 5;
for (i = 0; i < r; i++)
{
if (i <= r / 2)
{
count = N + 1;
for (j = 0; j <= i; j++)
{
N++;
Console.Write(N + " ");
}
Console.Write("\n");
}
else
{
N = count - (r - i);
count = N;
for (j = i; j < r; j++)
{
Console.Write(N + " ");
N++;
}
Console.Write("\n");
}
}
}
}
// This code is contributed
// by ChitraNayal
PHP
<?php
// PHP program for incrementing
// or decrementing triangle pattern
$N = 3; // initializing N
$N--;
$r = 5;
for ($i = 0; $i < $r; $i++)
{
if ($i <= $r / 2)
{
$count = $N + 1;
for ($j = 0; $j <= $i; $j++)
{
$N++;
echo $N . " ";
}
echo "\n";
}
else
{
$N = $count - ($r - $i);
$count = $N;
for ($j = $i; $j < $r; $j++)
{
echo $N . " ";
$N++;
}
echo "\n";
}
}
// This code is contributed
// by ChitraNayal
?>
Javascript
<script>
var i, j, r, N, count;
N = 3; // initializing N
N--;
r = 5;
for (i = 0; i < r; i++) {
if (i <= r / 2) {
count = N + 1;
for (j = 0; j <= i; j++) {
N++;
document.write(N + " ");
}
document.write("<br>");
} else {
N = count - (r - i);
count = N;
for (j = i; j < r; j++) {
document.write(N + " ");
N++;
}
document.write("<br>");
}
}
</script>
Producción:
3 4 5 6 7 8 4 5 3
- Patrón de triángulo numérico decreciente
Escriba un programa para imprimir un patrón de triángulo numérico decreciente que comience con un número dado N.
Ejemplos:
Input : 3
Output : 3
5 4
8 7 6
5 4
3
A continuación se muestra la implementación del problema mencionado anteriormente.
C++
#include <iostream>
using namespace std;
int main()
{
int i, j, r, N, N1;
N1 = 3;
N = 0;
r = 5;
for (i = 0; i < r; i++) {
if (i <= r / 2) {
N = N1;
for (j = 0; j <= i; j++) {
N++;
}
N1 = N;
for (j = 0; j <= i; j++) {
N--;
cout << N << " ";
}
cout << endl;
}
else {
for (j = i; j < r; j++) {
N--;
cout << N << " ";
}
cout << endl;
}
}
}
Java
// Java program for incrementing
// and decrementing triangle pattern
class GFG
{
public static void main(String[] args)
{
int i, j, r, N, N1;
N1 = 3;
N = 0;
r = 5;
for (i = 0; i < r; i++)
{
if (i <= r / 2)
{
N = N1;
for (j = 0; j <= i; j++)
{
N++;
}
N1 = N;
for (j = 0; j <= i; j++)
{
N--;
System.out.print(N + " ");
}
System.out.println();
}
else
{
for (j = i; j < r; j++)
{
N--;
System.out.print(N + " ");
}
System.out.println();
}
}
}};
// This code is contributed
// by ChitraNayal
Python 3
# python 3 program for incrementing # and decrementing triangle pattern if __name__ == "__main__": N1 = 3 N = 0; r = 5; for i in range( r): if i <= r // 2: N = N1 for j in range(i + 1): N += 1 N1 = N for j in range(i + 1): N -= 1 print(N, end = " ") print() else : for j in range(i, r): N -= 1 print(N, end = " ") print() # This code is contributed # by ChitraNayal
C#
// C# program for incrementing
// and decrementing triangle pattern
using System;
class GFG
{
public static void Main()
{
int i, j, r, N, N1;
N1 = 3;
N = 0;
r = 5;
for (i = 0; i < r; i++)
{
if (i <= r / 2)
{
N = N1;
for (j = 0; j <= i; j++)
{
N++;
}
N1 = N;
for (j = 0; j <= i; j++)
{
N--;
Console.Write(N + " ");
}
Console.Write("\n");
}
else
{
for (j = i; j < r; j++)
{
N--;
Console.Write(N + " ");
}
Console.Write("\n");
}
}
}};
// This code is contributed
// by ChitraNayal
PHP
<?php
// PHP program for incrementing
// and decrementing triangle pattern
$N1 = 3;
$N = 0;
$r = 5;
for ($i = 0; $i < $r; $i++)
{
if ($i <= $r / 2)
{
$N = $N1;
for ($j = 0; $j <= $i; $j++)
{
$N++;
}
$N1 = $N;
for ($j = 0; $j <= $i; $j++)
{
$N--;
echo $N ." ";
}
echo "\n";
}
else
{
for ($j = $i; $j < $r; $j++)
{
$N--;
echo $N ." ";
}
echo "\n";
}
}
// This code is contributed
// by ChitraNayal
?>
Javascript
<script>
// Javascript program for incrementing
// and decrementing triangle pattern
let i, j, r, N, N1;
N1 = 3;
N = 0;
r = 5;
for (i = 0; i < r; i++)
{
if (i <= r / 2)
{
N = N1;
for (j = 0; j <= i; j++)
{
N++;
}
N1 = N;
for (j = 0; j <= i; j++)
{
N--;
document.write(N + " ");
}
document.write("<br>");
}
else
{
for (j = i; j < r; j++)
{
N--;
document.write(N + " ");
}
document.write("<br>");
}
}
// This code is contributed by avanitrachhadiya2155
</script>
Producción:
3 5 4 8 7 6 5 4 3
Publicación traducida automáticamente
Artículo escrito por Smitha Dinesh Semwal y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA