Dadas dos fracciones a/b y c/d, compáralas e imprime la mayor de las dos.
Ejemplos:
Input: 5/6, 11/45 Output: 5/6 Input: 4/5 and 2/3 Output: 4/5
Simplemente podemos convertir las fracciones en valores de punto flotante dividiendo el numerador por el denominador. Una vez que tenemos los dos números de coma flotante correspondientes a cada fracción, podemos comparar estos números y determinar qué fracción es mayor.
Sin embargo, la respuesta calculada puede ser incorrecta debido a aproximaciones de punto flotante y truncamientos durante el proceso de división. Para obtener la respuesta más precisa, debemos evitar recurrir a la división de coma flotante.
Para comparar dos fracciones necesitamos hacer que sus denominadores sean iguales. Podemos hacer esto mediante la multiplicación cruzada de numeradores con denominadores. Veamos cómo funciona esto
We have two fractions a/b and c/d. Let Y = (a/b - c/d) = (ad - bc)/(bd) Now, if Y > 0 then a/b > c/d if Y = 0 then a/b = c/d if Y < o then a/b < c/d Since bd is always positive, the sign of Y depends only on the numerator (ad-bc). So we need to compute (ad-bc) only.
Complejidad:
dado que realizamos dos operaciones de multiplicación y una de resta, la respuesta se calcula en tiempo constante, es decir, O (1)
C++
// CPP program to find max between // two Rational numbers #include <bits/stdc++.h> using namespace std; struct Fraction { int num, den; }; // Get max of the two fractions Fraction maxFraction(Fraction first, Fraction sec) { // Declare nume1 and nume2 for get the value of // first numerator and second numerator int a = first.num; int b = first.den; int c = sec.num; int d = sec.den; // Compute ad-bc int Y = a * d - b * c; return (Y > 0) ? first : sec; } // Driver Code int main() { Fraction first = { 3, 2 }; Fraction sec = { 3, 4 }; Fraction res = maxFraction(first, sec); cout << res.num << "/" << res.den; return 0; }
Java
// Java program to find max between // two Rational numbers import java.io.*; import java.util.*; class Fraction { int num, den; //Constructor Fraction(int n,int d){ num=n; den=d; } // Get max of the two fractions static Fraction maxFraction(Fraction first, Fraction sec) { // Declare nume1 and nume2 for get the value of // first numerator and second numerator int a = first.num; int b = first.den; int c = sec.num; int d = sec.den; // Compute ad-bc int Y = a * d - b * c; return (Y > 0) ? first : sec; } // Driver function public static void main (String[] args) { Fraction first = new Fraction( 3, 2 ); Fraction sec = new Fraction( 3, 4 ); Fraction res = maxFraction(first, sec); System.out.println(res.num +"/"+ res.den); } } // This code is contributed by Gitanjali.
Python3
# Python3 program to find max # between two Rational numbers # Get max of the two fractions def maxFraction(first, sec): # Declare nume1 and nume2 for get the value # of first numerator and second numerator a = first[0]; b = first[1] c = sec[0]; d = sec[1] # Compute ad-bc Y = a * d - b * c return first if Y else sec # Driver Code first = ( 3, 2 ) sec = ( 3, 4 ) res = maxFraction(first, sec) print(str(res[0]) + "/" + str(res[1])) # This code is contributed by Ansu Kumari.
C#
// C# program to find max between // two Rational numbers using System; class Fraction { int num, den; //Constructor Fraction(int n,int d) { num=n; den=d; } // Get max of the two fractions static Fraction maxFraction(Fraction first, Fraction sec) { // Declare nume1 and nume2 for get the value of // first numerator and second numerator int a = first.num; int b = first.den; int c = sec.num; int d = sec.den; // Compute ad-bc int Y = a * d - b * c; return (Y > 0) ? first : sec; } // Driver function public static void Main () { Fraction first = new Fraction( 3, 2 ); Fraction sec = new Fraction( 3, 4 ); Fraction res = maxFraction(first, sec); Console.WriteLine(res.num +"/"+ res.den); } } // This code is contributed by vt_m.
PHP
<?php // PHP program to find max // between two Rational numbers // Get max of the two fractions function maxFraction($first, $sec) { // Declare nume1 and nume2 // for get the value of // first numerator and second // numerator $a = $first[0]; $b = $first[1]; $c = $sec[0]; $d = $sec[1]; // Compute ad-bc $Y = $a * $d - $b * $c; return ($Y) ? $first : $sec; } // Driver Code $first = array( 3, 2 ); $sec = array ( 3, 4 ); $res = maxFraction($first, $sec); echo $res[0] . "/" . $res[1]; // This code is contributed // by mits. ?>
Javascript
// javascript program to find max // between two Rational numbers // Get max of the two fractions function maxFraction(first, sec) { // Declare nume1 and nume2 for get the value // of first numerator and second numerator a = first[0]; b = first[1] c = sec[0]; d = sec[1] // Compute ad-bc Y = a * d - b * c return (Y > 0) ? first : sec; } // Driver Code first = [ 3, 2 ]; sec = [ 3, 4 ]; res = maxFraction(first, sec); document.write(res[0] + "/" + res[1]);
Producción :
3/2
Publicación traducida automáticamente
Artículo escrito por Sayan Mahapatra y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA