Dada la cantidad total de rupias en una bolsa y la proporción de monedas. La bolsa contiene solo monedas de 1 R, 50 paise, 25 paise en proporción X, Y, Z. La tarea es determinar el número de monedas de 1 Rs, monedas de 50 Paise y monedas de 25 Paise para que después de la suma de todas obtengamos nuevamente el total de rupias dadas.
Ejemplos:
Input: totalRupees = 1800, X = 1, Y = 2, Z = 4
Output: 1 rupees coins = 600
50 paisa coins = 1200
25 paisa coins = 2400
Input: totalRupees = 2500, X = 2, Y = 4, Z = 2
Output: 1 rupees coins = 555
50 paisa coins = 1110
25 paisa coins = 2220
Acercarse:
Supongamos que la proporción en la que se dividen las monedas de 1 R, 50 paise y 25 paise es 1:2:4.
Ahora,
las monedas de 1 R en una bolsa son 1x.
50 monedas de paise en una bolsa son 2x.
25 monedas de paise en una bolsa son 4x.
Ahora convierta estos paises en rupias.
Entonces,
x monedas de 1 Rs cada una, el valor total es x rupias.
2x monedas de 50 paise es decir (1/2) rupias cada una, el valor total es x rupias.
4x monedas de 25 paise es decir (1/4) rupias cada una, el total es x rupias.
Por lo tanto,
3x = 1800
x = 600
1 moneda de rupias = 600 * 1 = 600
50 monedas de paisa = 600 * 2 = 1200
25 monedas de paisa = 600 * 4 = 2400
A continuación se muestra la implementación del enfoque anterior:
C++
// C++ implementation of above approach
#include <bits/stdc++.h>
using namespace std;
// function to calculate coin.
int coin(int totalRupees, int X, int Y, int Z)
{
float one = 0, fifty = 0, twentyfive = 0,
result = 0, total = 0;
// Converting each of them in rupees.
// As we are given totalRupees = 1800
one = X * 1;
fifty = ((Y * 1) / 2.0);
twentyfive = ((Z * 1) / 4.0);
total = one + fifty + twentyfive;
result = ((totalRupees) / total);
return result;
}
// Driver code
int main()
{
int totalRupees = 1800;
int X = 1, Y = 2, Z = 4;
int Rupees = coin(totalRupees, X, Y, Z);
cout << "1 rupess coins = " << Rupees * 1 << endl;
cout << "50 paisa coins = " << Rupees * 2 << endl;
cout << "25 paisa coins = " << Rupees * 4 << endl;
return 0;
}
Java
// Java implementation of above approach
import java.io.*;
class GFG {
// function to calculate coin.
static int coin(int totalRupees, int X, int Y, int Z)
{
float one = 0, fifty = 0, twentyfive = 0,
result = 0, total = 0;
// Converting each of them in rupees.
// As we are given totalRupees = 1800
one = X * 1;
fifty = ((Y * 1) / 2);
twentyfive = ((Z * 1) / 4);
total = one + fifty + twentyfive;
result = ((totalRupees) / total);
return (int)result;
}
// Driver code
public static void main (String[] args) {
int totalRupees = 1800;
int X = 1, Y = 2, Z = 4;
int Rupees = coin(totalRupees, X, Y, Z);
System.out.println( "1 rupess coins = " + Rupees * 1);
System.out.println( "50 paisa coins = " + Rupees * 2);
System.out.println( "25 paisa coins = " + Rupees * 4);
}
}
//This code is contributed by inder_verma.
Python3
# Python3 implementation of above approach
# function to calculate coin.
def coin(totalRupees, X, Y, Z):
# Converting each of them in rupees.
# As we are given totalRupees = 1800
one = X * 1
fifty = ((Y * 1) / 2.0)
twentyfive = ((Z * 1) / 4.0)
total = one + fifty + twentyfive
result = ((totalRupees) / total)
return int(result)
# Driver code
if __name__=='__main__':
totalRupees = 1800
X, Y, Z = 1, 2, 4
Rupees = coin(totalRupees, X, Y, Z)
print("1 rupess coins = ", Rupees * 1)
print("50 paisa coins = ", Rupees * 2)
print("25 paisa coins = ", Rupees * 4)
# This code is contributed by
# Sanjit_Prasad
C#
// C# implementation of above approach
using System;
class GFG
{
// function to calculate coin.
static int coin(int totalRupees, int X,
int Y, int Z)
{
float one = 0, fifty = 0, twentyfive = 0,
result = 0, total = 0;
// Converting each of them in rupees.
// As we are given totalRupees = 1800
one = X * 1;
fifty = ((Y * 1) / 2);
twentyfive = ((Z * 1) / 4);
total = one + fifty + twentyfive;
result = ((totalRupees) / total);
return (int)result;
}
// Driver code
public static void Main ()
{
int totalRupees = 1800;
int X = 1, Y = 2, Z = 4;
int Rupees = coin(totalRupees, X, Y, Z);
Console.WriteLine( "1 rupess coins = " + Rupees * 1);
Console.WriteLine( "50 paisa coins = " + Rupees * 2);
Console.WriteLine( "25 paisa coins = " + Rupees * 4);
}
}
// This code is contributed by inder_verma
PHP
<?php
// PHP implementation of above approach
//function to calculate coin
function coin($totalRupees, $X, $Y, $Z)
{
$one = 0;
$fifty = 0;
$twentyfive = 0;
$result = 0;
$total = 0;
// Converting each of them in rupees.
// As we are given totalRupees = 1800
$one = $X * 1;
$fifty = (($Y * 1) / 2.0);
$twentyfive = (($Z * 1) / 4.0);
$total = $one + $fifty + $twentyfive;
$result = (($totalRupees) / $total);
return $result;
}
// Driver Code
$totalRupees = 1800;
$X = 1;
$Y = 2;
$Z = 4;
$Rupees = coin($totalRupees, $X, $Y, $Z);
echo "1 rupess coins = ", $Rupees * 1, "\n";
echo "50 paisa coins = ", $Rupees * 2, "\n";
echo "25 paisa coins = ", $Rupees * 4, "\n";
// This code is contributed
// by Shashank_Sharma.
?>
Javascript
<script>
// Javascript implementation of above approach
// function to calculate coin.
function coin(totalRupees, X, Y, Z)
{
var one = 0, fifty = 0, twentyfive = 0,
result = 0, total = 0;
// Converting each of them in rupees.
// As we are given totalRupees = 1800
one = X * 1;
fifty = ((Y * 1) / 2.0);
twentyfive = ((Z * 1) / 4.0);
total = one + fifty + twentyfive;
result = ((totalRupees) / total);
return result;
}
// Driver code
var totalRupees = 1800;
var X = 1, Y = 2, Z = 4;
var Rupees = coin(totalRupees, X, Y, Z);
document.write( "1 rupess coins = " + Rupees * 1 + "<br>");
document.write( "50 paisa coins = " + Rupees * 2 + "<br>");
document.write( "25 paisa coins = " + Rupees * 4 + "<br>");
</script>
1 rupess coins = 600 50 paisa coins = 1200 25 paisa coins = 2400
Complejidad del tiempo:O(1)
Espacio Auxiliar: O(1)
Publicación traducida automáticamente
Artículo escrito por Naman_Garg y traducido por Barcelona Geeks. The original can be accessed here. Licence: CCBY-SA