Programa para hallar la suma de la serie 23+ 45+ 75+….. hasta N términos

Dado un número N, la tarea es encontrar el término N de la siguiente serie:
 

23 + 45 + 75 + 113 + 159 +…… hasta N términos

Ejemplos: 
 

Input: N = 4
Output: 256
Explanation:
Nth term = (2 * N * (N + 1) * (4 * N + 17) + 54 * N) / 6
         = (2 * 4 * (4 + 1) * (4 * 4 + 17) + 54 * 4) / 6
         = 256

Input: N = 10
Output: 2180

Enfoque:
El término N de la serie dada se puede generalizar como: 

Suma de los primeros n términos de esta serie: 

Por lo tanto, Suma de los primeros n términos de esta serie: 
A continuación se muestra la implementación del enfoque anterior: 
 

// CPP program to find sum
// upto N-th term of the series:
// 23, 45, 75, 113...
 
#include <iostream>
using namespace std;
 
// calculate Nth term of series
int findSum(int N)
{
    return (2 * N * (N + 1) * (4 * N + 17) + 54 * N) / 6;
}
 
// Driver Function
int main()
{
 
    // Get the value of N
    int N = 4;
 
    // Get the sum of the series
    cout << findSum(N) << endl;
 
    return 0;
}

// Java program to find sum
// upto N-th term of the series:
// 23, 45, 75, 113...
import java.util.*;
 
class solution
{
     
static int findSum(int N)
{
    //return the final sum
    return (2 * N * (N + 1) * (4 * N + 17) + 54 * N) / 6;
}
 
//Driver program
public static void main(String arr[])
{
// Get the value of N
    int N = 4;
 
// Get the sum of the series
 System.out.println(findSum(N));
 
}
}

# Python3 program to find sum
# upto N-th term of the series:
# 23, 45, 75, 113...
 
# calculate Nth term of series
def findSum(N):
     
    return (2 * N * (N + 1) * (4 * N + 17) + 54 * N) / 6
     
#Driver Function
if __name__=='__main__':
#Get the value of N
    N = 4
 
#Get the sum of the series
    print(findSum(N))
 
#this code is contributed by Shashank_Sharma

// C# program to find sum
// upto N-th term of the series:
// 23, 45, 75, 113...
using System;
 
class GFG
{
     
static int findSum(int N)
{
    //return the final sum
    return (2 * N * (N + 1) *
           (4 * N + 17) + 54 * N) / 6;
}
 
// Driver Code
static void Main()
{
    // Get the value of N
    int N = 4;
     
    // Get the sum of the series
    Console.Write(findSum(N));
}
}
 
// This code is contributed by Raj

<?php
// PHP program to find sum
// upto N-th term of the series:
// 23, 45, 75, 113...
 
// calculate Nth term of series
function findSum($N)
{
    return (2 * $N * ($N + 1) *
           (4 * $N + 17) + 54 * $N) / 6;
}
 
// Driver Code
 
// Get the value of N
$N = 4;
 
// Get the sum of the series
echo findSum($N);
 
// This code is contributed
// by anuj_67
?>

<script>
// javascript program to find sum
// upto N-th term of the series:
// 23, 45, 75, 113...
 
// calculate Nth term of series
function findSum( N)
{
    return (2 * N * (N + 1) * (4 * N + 17) + 54 * N) / 6;
}
 
// Driver Function
 
    // Get the value of N
    let N = 4;
 
    // Get the sum of the series
    document.write(findSum(N));
     
// This code is contributed by Rajput-Ji
 
</script>

256

Complejidad de tiempo: O(1)

Espacio Auxiliar : O(1) ya que usa variables constantes