Dado un número N. La tarea es escribir un programa para encontrar el N-ésimo término de la siguiente serie:
1, 6, 17, 34, 56, 86, 121, 162, …..(Términos N)
Ejemplos:
Input: N = 4 Output: 34 For N = 4 4th Term = ( 3 * 4 * 4 - 4 * 4 + 2) = 34 Input: N = 10 Output: 261
Enfoque: El enésimo término generalizado de esta serie:
A continuación se muestra la implementación requerida:
C++
// C++ program to find the N-th term of the series: // 1, 6, 17, 34, 56, 86, 121, 162, ..... #include <iostream> #include <math.h> using namespace std; // calculate Nth term of series int nthTerm(int n) { return 3 * pow(n, 2) - 4 * n + 2; } // Driver code int main() { int N = 4; cout << nthTerm(N) << endl; return 0; }
Java
// Java program to find the N-th term of the series: // 1, 6, 17, 34, 56, 86, 121, 162, ..... public class GFG { // calculate Nth term of series static int nthTerm(int n) { return 3 * (int) Math.pow(n, 2) - 4 * n + 2; } // Driver code public static void main(String args[]) { int N = 4; System.out.println(nthTerm(N)); } // This Code is contributed by ANKITRAI1 }
Python3
# Python program to find the # N-th term of the series: # 1, 6, 17, 34, 56, 86, 121, 162, ..... # calculate Nth term of series def nthTerm(n): return 3 * pow(n, 2) - 4 * n + 2 # Driver code N = 4 print(nthTerm(N)) # This code is contributed by # Sanjit_Prasad
C#
// C# program to find the // N-th term of the series: // 1, 6, 17, 34, 56, 86, 121, 162, ..... using System; class GFG { // calculate Nth term of series static int nthTerm(int n) { return 3 * (int) Math.Pow(n, 2) - 4 * n + 2; } // Driver code public static void Main() { int N = 4; Console.Write(nthTerm(N)); } } // This code is contributed // by ChitraNayal
PHP
<?php // PHP program to find the // N-th term of the series: // 1, 6, 17, 34, 56, 86, 121, 162, ..... // calculate Nth term of series function nthTerm($n) { return 3 * pow($n, 2) - 4 * $n + 2; } // Driver code $N = 4; echo nthTerm($N)."\n"; // This code is contributed // by ChitraNayal ?>
Javascript
<script> // JavaScript program to find the N-th term of the series: // 1, 6, 17, 34, 56, 86, 121, 162, ..... // calculate Nth term of series function nthTerm(n) { return 3 * Math.pow(n, 2) - 4 * n + 2; } // Driver code let N = 4; document.write( nthTerm(N) ); // This code contributed by gauravrajput1 </script>
Producción:
34
Complejidad de tiempo: O(1)
Complejidad espacial : O (1) ya que usa variables constantes