Encuentra la suma de n términos de la serie 1,8,27,64….

Dada una serie, la tarea es encontrar la suma de las siguientes series hasta n términos:
 

1, 8, 27, 64, …

Ejemplos: 
 

Input: N = 2
Output: 9
9 = (2*(2+1)/2)^2

Input: N = 4
Output: 100
100 = (4*(4+1)/2)^2

Planteamiento: Podemos resolver este problema usando la siguiente fórmula: 
 

    Sn = 1 + 8 + 27 + 64 + .........up to n terms
    Sn = (n*(n+1)/2)^2

A continuación se muestra la implementación del enfoque anterior: 
 

// C++ program to find the sum of n terms
#include <bits/stdc++.h>
using namespace std;
 
// Function to calculate the sum
int calculateSum(int n)
{
 
    // Return total sum
    return pow(n * (n + 1) / 2, 2);
}
 
// Driver code
int main()
{
 
    int n = 4;
    cout << calculateSum(n);
 
    return 0;
}

// Java program to find the sum of n terms
import java.io.*;
 
class GFG {
 
 
// Function to calculate the sum
static int calculateSum(int n)
{
 
    // Return total sum
    return (int)Math.pow(n * (n + 1) / 2, 2);
}
 
// Driver code
 
 
    public static void main (String[] args) {
        int n = 4;
    System.out.println( calculateSum(n));
 
    }
}
// This code is contributed by inder_verma..

# Python3 program to find the
# sum of n terms
 
#Function to calculate the sum
def calculateSum(n):
     
    #return total sum
    return (n * (n + 1) / 2)**2
     
#Driver code
if __name__=='__main__':
    n = 4
    print(calculateSum(n))
 
#this code is contributed by Shashank_Sharma

// C# program to find the sum of n terms
using System;
 
class GFG
{
 
// Function ot calculate the sum
static int calculateSum(int n)
{
 
    // Return total sum
    return (int)Math.Pow(n * (n + 1) / 2, 2);
}
 
// Driver code
public static void Main ()
{
    int n = 4;
    Console.WriteLine(calculateSum(n));
}
}
 
// This code is contributed
// by Akanksha Rai(Abby_akku)

<?php
// PHP program to find
// the sum of n terms
     
// Function to calculate the sum
function calculateSum($n)
{
    // Return total sum
    return pow($n * ($n + 1) / 2 , 2);
}
     
// Driver code
$n = 4;
echo calculateSum($n);
     
// This code is contributed
// by ANKITRAI1
?>

<script>
 
// javascript program to find the sum of n terms
 
// Function to calculate the sum
function calculateSum(n)
{
 
    // Return total sum
    return parseInt(Math.pow(n * (n + 1) / 2, 2));
}
 
// Driver code
 var n = 4;
document.write( calculateSum(n));
 
 
// This code contributed by shikhasingrajput
 
</script>

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