Programa para el N-ésimo término de la serie Progresión aritmética

Dado el primer término (a), la diferencia común (d) y un número entero N de la serie Progresión aritmética, la tarea es encontrar el término N ^de la serie.
Ejemplos: 
 

Input : a = 2 d = 1 N = 5
Output :
The 5th term of the series is : 6

Input : a = 5 d = 2 N = 10
Output :
The 10th term of the series is : 23

Acercarse: 
 

Sabemos que la serie Progresión aritmética es como = 2, 5, 8, 11, 14…. … 
En esta serie 2 es el término declarante de la serie. 
Diferencia común = 5 – 2 = 3 (Diferencia común en la serie). 
entonces podemos escribir la serie como:
t ₁ = a ₁ 
t ₂ = a ₁ + (2-1) * d 
t ₃ = a ₁ + (3-1) * d 
. 
. 
. 
t _norte = un ₁ + (N-1) * re 
 

^{Para encontrar el término} N en la serie Progresión aritmética usamos la fórmula simple.
 

TN = a1 + (N-1) * d

// CPP Program to find nth term of
// Arithmetic progression
#include <bits/stdc++.h>
using namespace std;
 
int Nth_of_AP(int a, int d, int N)
{
    // using formula to find the
    // Nth term t(n) = a(1) + (n-1)*d
    return (a + (N - 1) * d);
     
}
 
// Driver code
int main()
{
    // starting number
    int a = 2;
     
    // Common difference
    int d = 1;
     
    // N th term to be find
    int N = 5;
     
    // Display the output
    cout << "The "<< N
         <<"th term of the series is : "
         << Nth_of_AP(a,d,N);
 
    return 0;
}

// Java program to find nth term
// of Arithmetic progression
import java.io.*;
import java.lang.*;
 
class GFG
{
    public static int Nth_of_AP(int a,
                                int d,
                                int N)
    {
        // using formula to find the Nth
        // term t(n) = a(1) + (n-1)*d
        return ( a + (N - 1) * d );
    }
 
    // Driver code
    public static void main(String[] args)
    {
        // starting number
        int a = 2;
         
        // Common difference
        int d = 1;
         
        // N th term to be find
        int N = 5;
 
        // Display the output
        System.out.print("The "+ N +
                         "th term of the series is : " +
                          Nth_of_AP(a, d, N));
    }
}

# Python 3 Program to
# find nth term of
# Arithmetic progression
 
def Nth_of_AP(a, d, N) :
 
    # using formula to find the
    # Nth term t(n) = a(1) + (n-1)*d
    return (a + (N - 1) * d)
      
  
# Driver code
a = 2  # starting number
d = 1  # Common difference
N = 5  # N th term to be find
  
# Display the output
print( "The ", N ,"th term of the series is : ",
       Nth_of_AP(a, d, N))
 
 
 
# This code is contributed
# by Nikita Tiwari.

// C# program to find nth term
// of Arithmetic progression
using System;
 
class GFG
{
    public static int Nth_of_AP(int a,
                                int d,
                                int N)
    {
         
        // using formula to find the Nth
        // term t(n) = a(1) + (n-1)*d
        return ( a + (N - 1) * d );
    }
 
    // Driver code
    public static void Main()
    {
        // starting number
        int a = 2;
         
        // Common difference
        int d = 1;
         
        // N th term to be find
        int N = 5;
 
        // Display the output
        Console.WriteLine("The "+ N +
                          "th term of the series is : " +
                           Nth_of_AP(a, d, N));
    }
}
 
// This code is contributed by vt_m.

<?php
// PHP Program to find nth term of
// Arithmetic progression
 
function Nth_of_AP($a, $d, $N)
{
    // using formula to find the
    // Nth term t(n) = a(1) + (n-1)*d
    return ($a + ($N - 1) * $d);
     
}
 
// Driver code
 
// starting number
$a = 2;
 
// Common difference
$d = 1;
 
// N th term to be find
$N = 5;
     
// Display the output
echo("The " . $N . "th term of the series is : " .
                           Nth_of_AP($a, $d, $N));
 
// This code is contributed by Ajit.
?>

<script>
 
// JavaScript Program to find nth term of 
// Arithmetic progression
 
    function Nth_of_AP(a, d, N)
    { 
        // using formula to find the 
        // Nth term t(n) = a(1) + (n-1)*d
        return (a + (N - 1) * d);
       
    }
   
    // Driver code
 
    // starting number
    let a = 2; 
       
    // Common difference
    let d = 1; 
       
    // N th term to be find
    let N = 5; 
       
    // Display the output
    document.write("The "+ N + "th term of the series is : "
    + Nth_of_AP(a,d,N));
   
 
// This code is contributed by Mayank Tyagi
 
</script>

Producción : 
 

The 5th term of the series is : 6

Complejidad de tiempo: O(1), el código se ejecutará en un tiempo constante.
Espacio auxiliar: O(1), no se requiere espacio adicional, por lo que es una constante.