Dado un número N. La tarea es escribir un programa para encontrar el N-ésimo término de la siguiente serie:
0, 14, 40, 78, 124…(Términos N)
Ejemplos:
Input: N = 4 Output: 78 For N = 4 Sum(upto 4 terms) = ( 6 * n * n - 4 * n - 2) = ( 6 * 4 * 4 - 4 * 4 - 2) = 78 Input: N = 10 Output: 557
Enfoque: El término N generalizado de esta serie:
A continuación se muestra la implementación requerida:
C++
// CPP program to find the N-th term of the series // 0, 14, 40, 78, 124 ... #include <iostream> #include <math.h> using namespace std; // calculate sum upto Nth term of series int nthTerm(int n) { return 6 * pow(n, 2) - 4 * n - 2; } // Driver code int main() { int N = 4; cout << nthTerm(N); return 0; }
Java
// Java program to find the N-th term of the series // 0, 14, 40, 78, 124 ... import java.util.*; class solution { // calculate sum up to Nth term of series static int nthTerm(int n) { //return the final sum return 6 * (int)Math.pow(n, 2) - 4 * n - 2; } // Driver code public static void main(String arr[]) { int N = 4; System.out.println(nthTerm(N)); } } //This code is contributed by Surendra_Gangwar
Python3
# Python3 program to find # the N-th term of the series # 0, 14, 40, 78, 124 ... # calculate sum upto Nth # term of series def nthTerm(n): return int(6 * pow(n, 2) - 4 * n - 2) # Driver code N = 4 print(nthTerm(N)) # This code is contributed # by Shrikant13
C#
// C# program to find the // N-th term of the series // 0, 14, 40, 78, 124 ... using System; class GFG { // calculate sum up to Nth // term of series static int nthTerm(int n) { //return the final sum return 6 * (int)Math.Pow(n, 2) - 4 * n - 2; } // Driver code public static void Main() { int N = 4; Console.WriteLine(nthTerm(N)); } } // This code is contributed // by inder_verma
PHP
<?php // PHP program to find the // N-th term of the series // 0, 14, 40, 78, 124 ... // calculate sum upto // Nth term of series function nthTerm($n) { return 6 * pow($n, 2) - 4 * $n - 2; } // Driver code $N = 4; echo nthTerm($N); // This code is contributed by // Akanksha Rai(Abby_akku)
Javascript
<script> // JavaScript program to find the N-th term of the series // 0, 14, 40, 78, 124 ... // calculate sum upto Nth term of series function nthTerm( n) { return 6 * Math.pow(n, 2) - 4 * n - 2; } // Driver code let N = 4; document.write( nthTerm(N) ); // This code contributed by aashish1995 </script>
Producción:
78
Complejidad de tiempo: O(1)
Complejidad espacial : O (1) ya que usa variables constantes
Nota: La suma de n términos de la serie anterior (Sn) es: